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The Independent Particle Approximation • We approximate the strong electrostatic forces between e-s by treating the force on each electron independently, which includes force from nucleus and other electrons • Inner electrons can shield the nuclear charge, leading to “screening” Screening electron cloud The effective potential energy felt by an electron +Ze r electron ke 2 U (r ) Z eff (r ) r Zeff is the effective charge that the electron feels and depends on r. Note that Z eff Z when r is inside all other electrons Z eff 1 when r is outside all other electrons Unlike in hydrogen, in multielectron atoms the dependence of the potential energy on r due to screening lifts the degeneracy between the n states The Periodic Table Columns: groups with similar shells, similar properties Rows: periods with elements with increasingly-full shells Closed-shell –plus one (alkali) elements: reactive due to loosely-bound outer electron in s-shell Closed-shell–minus-one elements (halogens): elements with high electron affinity A (energy gained when an additional electron is added to a neutral atom); will easily form negative ions (take additional electron) in remaining p-shell state due to large nuclear charge; these elements are very reactive (e.g., F- with e.a.=3.4 eV) The Ionic Bond: Property Melting point and boiling point Electrical conductivity Hardness Brittleness electrostatic force of attraction between positively and negatively charged ions Explanation The melting and boiling points of ionic compounds are high because a large amount of thermal energy is required to separate the ions which are bound by strong electrical forces. Solid ionic compounds do not conduct electricity when a potential is applied because there are no mobile charged particles. No free electrons causes the ions to be firmly bound and cannot carry charge by moving. Most ionic compounds are hard; the surfaces of their crystals are not easily scratched. This is because the ions are bound strongly to the lattice and aren't easily displaced. Most ionic compounds are brittle; a crystal will shatter if we try to distort it. This happens because distortion cause ions of like charges to come close together then sharply repel. Cl R + Na+ Total energy of ion: The energy cost to transfer the electron from an alkali to a halogen is 2 E Ionization Energy (alkali) Electron Affinity (halogen) Effective potential ke + B n ke2 r r BE E ( R0 ) E 2nd term is repulsion between 2 e- clouds R e.g.: F2, HF • • • • The Covalent Bond The covalent bond is formed by sharing of outer shell electrons between atoms rather than by electron transfer. This lowers the energy of the system since electrons are attracted to both nuclei (stronger effective Coulomb potential) As an example, consider the H2+ molecular ion (two protons, one e-): y 1 (r) Aer / a y 2 (r) Aer / a 1 B 2 B • As the distance between the atoms is decreased, significant interference between the wave functions occur • In the bonding (symmetric) y+ state electron has a larger probability of being attracted by both protons – this state is the one responsible for the molecule formation. Therefore, the bonding state has a lower energy than the antibonding (antisymmetric). + y +y + y -y 2.5 + 6 2.0 5 1.5 4 2 1.0 |y(r)| y(r) 0.5 0.0 3 2 -0.5 1 -1.0 -1.5 0 -2.0 -5 -5 -4 -3 -2 -1 0 r (aB) 1 2 3 4 5 2 |y +y | + 2 |y -y | -4 -3 -2 -1 0 r(aB) 1 2 3 4 5 Comparison of Ionic and Covalent Bonding The type of bonding in a solid is determined mainly by the degree of overlap between the electronic wavefunctions of the atoms involved. van der Waals From charge fluctuations in atoms due to zero-point motion (from Heisenberg uncertainty principle); creates attractive dipole moments Always present, but significant only when other bonding not possible Typical strength ~1% of other bonds, short range, varying as r -6 To model the van der Waals interaction, considered two harmonic oscillators. Each dipole consists of a pair of opposite charges with a restoring force acting between each pair of charges. We wrote down the Hamiltonian for the oscillators. Transforming to normal coordinates decoupled the energy into a symmetric and antisymmetric contributions. Calculated the frequencies and bond energy C2: Translational Lattice Vectors – 2D A lattice is a set of points such that a translation from any point in the lattice by a vector; P Rn = n1 a + n2 b locates an exactly equivalent point, i.e. a point with the same environment as P. This is translational symmetry. Point D (n1, n2) = (0,2) Point F (n1, n2) = (0,-1) Point P (n1, n2) = (3,2) The vectors a, b are known as lattice vectors and (n1, n2) is a pair of integers whose values depend on the lattice point. Crystal Structure = Crystal Lattice + Basis y B C α b O a) Situation of atoms at the corners of regular hexagons a D A E x b) Crystal lattice obtained by identifying all the atoms in (a) UNIT CELL Primitive § Single lattice point per cell § Smallest area in 2D, or §Smallest volume in 3D Simple cubic(sc) Conventional = Primitive cell Conventional & Non-primitive § More than one lattice point per cell § Integral multibles of the area of primitive cell Body centered cubic(bcc) Conventional ≠ Primitive cell Crystal Structure 10 Face-centered Cubic (FCC) • Close-packed planes are perpendicular to cube diagonal • Stacking (ABCAB…) reduces symmetry to three-fold • Four 3-fold rotation axes + mirror plane, therefore Oh (octahedral symmetry) • Examples: Cu, Ag, Au, Ni, Pd, Pt, Al Groups: Fill in this Table for Cubics SC BCC FCC Volume of conventional cell a3 a3 a3 Lattice points per cell 1 2 4 Volume, primitive cell a3 ½ a3 ¼ a3 # of nearest neighbors 6 8 12 Nearest-neighbor distance a ½ a 3 a/2 # of second neighbors 12 6 6 Second neighbor distance a2 a a Many common semiconductors have Diamond or Zincblende crystal structures Tetrahedral coordination: Each atom has 4 nearest-neighbors (nn). Basis set: 2 atoms. Lattice face centered cubic (fcc). Diamond or Zincblende 2 atoms per fcc lattice point. Diamond: The 2 atoms are the same. Zincblende: The 2 atoms are different. The Cubic Unit Cell looks like For ABCABC… stacking it is called zinc blende Group: CsCl • The figure shows the crystal structure of CsCl. Take the lattice constant as a, all the bonds shown have the same length. The grey atoms are Cs and the green ones are Cl. • What are the primitive Bravais lattice and the associated basis for this crystal (including the locations of these atoms in terms of lattice parameter a)? • What is the distance to the nearest neighbors of Cs? If CsCl is Simple Cubic, what is NaCl? • CsCl: similar to bcc but atom at center of cube is different • NaCl: interpenetrating fcc structures – One atom at (0,0,0) – Second atom displaced by (1/2,0,0) • Majority of ionic crystals prefer NaCl structure despite lower coordination (what is coordination?) – Radius of cations much smaller than anions – For very small cations, anions can not get too close in CsCl structure – This favors NaCl structure where anion contact does not limit structure as much CsCl NaCl Perovskites A-site (Ba) Perovskites Oxygen • Superconductors (YBa2Cu3O7-δ) BaTiO3 • Ferroelectrics (BaTiO3) • Colossal Magnetoresistance (LaSrMnO3) • Multiferroics (BiFeO3) B-site (Ti) • High εr Insulators (SrTiO3) • Low εr Insulators (LaAlO3) • Conductors (Sr2RuO4) • Thermoelectrics (doped SrTiO3) • Ferromagnets (SrRuO3) Formula unit – ABO3 A atoms (bigger) at the corners O atoms at the face centers B atoms (smaller) at the body-center How many atoms per unit cell? Reflection Plane • A plane in a cell such that, when a mirror reflection in this plane is performed (e.g., x’=x, y’=y, z’=z), the cell remains invariant. • Mirror plane indicated by symbol m • Example: water molecule has 2 mirror planes sv (xz) sv (yz) Rotation Axes • Rotation through an angle about a certain axis • Trivial case is 360o rotation • Order of rotation: 2-, 3-, 4-, and 6correspond to 180o, 120o, 90o, and 60o. – These are only symmetry rotations allowed in crystals with long-range order; incompatible with translational symmetry – Small aggregates (short-range order) or molecules can also have 5-, 7-, etc. fold rotational symmetry What rotation axes does a cubic perovskite have? A-site (Ba) BaTiO3 B-site (Ti) Oxygen The density of lattice points on each plane of a set is the same and all lattice points are contained on each set of planes. z [2,3,3] Plane intercepts axes at 2 Reciprocal numbers are: 2 y 3a , 2b , 2c 1 1 1 , , 3 2 2 Indices of the plane (Miller): (2 3 3) (No commas, commas are for points) Indices of the direction: [2,3,3] x 3 The vector perpendicular to the plane shares the same coordinates. Miller indices still apply for a non-cubic system Distance between the (111) planes on a cubic lattice Review: Reciprocal Lattice The reciprocal lattice is composed of all points lying at positions from the origin, so that there is one point in the reciprocal lattice for each set of planes (hkl) in the real-space lattice. Suppose G can be decomposed into basis vectors: G hg1 + kg 2 + lg 3 (h, k, l integers) G rn 2m d hkl 2 Ghkl g i a j 2ij Note: a has dimensions of length, g has dimensions of length-1 Ghkl is perpendicular to (hkl) plane The basis vectors gi define a reciprocal lattice: 1. for every real lattice there’s a reciprocal lattice 2. reciprocal lattice vector g1 is perpendicular to plane defined by a2 and a3 g1 2 a a a a 2 a3 a1 a 2 a 3 is volume of unit cell + cyclic permutations a’s are not unique, but volume is Constructing the Reciprocal Lattice 1. Identify the basic planes in the direct space lattice. 2. Draw normals to these planes from the origin. 3. Note that distances from the origin along these normals is proportional to the inverse of the distance from the origin to the direct space planes. Reciprocal Lattices to SC, FCC and BCC Direct lattice SC a1 ax a 2 ay a az 3 Reciprocal lattice b1 2 / a x b 2 2 / a y b 2 / a z 3 Volume of RL 2 / a 3 Direct Reciprocal Simple cubic Simple cubic bcc fcc fcc bcc a1 1 ax + y z 2 BCC 1 a 2 2 a x + y + z a 1 ax y + z 3 2 b1 2 y + z a 2 b 2 a x + z b 2 x + y 3 a a1 1 ax + y 2 FCC a 1 ay + z 2 2 a 1 a z + x 3 2 b1 2 x + y z a 2 b 2 a x y + z b 2 x + y z 3 a 42 / a 3 22 / a 3 DIFFRACTION • Diffraction is a wave phenomenon in which the apparent bending and spreading of waves when they meet an obstruction is measured. • Light, radio, sound and water waves. • Diffraction is optimally sensitive to the periodic nature of the solid’s atomic structure. Width Variable (500-1500 nm) Wavelength Constant (600 nm) Distance d = Constant Scattering Condition In a crystal, only significant contributions of this integral arise when G=K. (Reminder: G is perpendicular to plane.) I (K ) e ir( G K ) 2 dr K k k0 Note: Real space and reciprocal space overlapped We know that G=2/dhkl =2kosin (from the figure) ko source Thus, to get diffraction: 2/dhkl =2(2 /λ)sin or λ=2 d sin Weigner Seitz Cell: Smallest space enclosed when intersecting the midpoint to the neighboring lattice points. graphene b1 a1 a2 Real Space 2-atom basis The same perpendicular bisector logic applies in 3D b2 k Space Wigner-Seitz Unit Cell of Reciprocal Lattice = First Brillouin zone, whose construction exhibits all the wavevectors k which can be Bragg-reflected by the crystal First Brillouin Zone of the FCC Lattice The BZ reflects lattice symmetry Note: fcc lattice in reciprocal space is a bcc lattice SC BCC FCC 6 8 12 Nearest-neighbor distance a ½ a 3 a/2 # of second neighbors 12 6 6 Second neighbor distance a2 a a FCC Primitive and # of nearest Unit neighbors Conventional Cells Group: Find the structure factor for FCC. S hkl Cubic form: 1 1 1 1 1 1 Four atom basis: r 0,0,0 , r , ,0 , r ,0, & r 0, , 2 2 2 2 2 2 SFhkl f 1+ exp i h + k + exp i k + l + exp i h + l So: 022 002 S hklF=4f if h,k,l all even or odd S hklF=0 if h,k,l are mixed even or odd 202 000 Allowed low order reflections are: 111 020 111, 200, 220, 311, 222, 400, 331, 310 Forbidden reflections: 100, 110, 210, 211 200 220 Structure Factor Ni3Al (L12) structure Simple cubic lattice, with a four atom basis 1 1 1 1 1 1 rAl 0,0,0 , rNi , ,0 , rNi ,0, & rNi 0, , 2 2 2 2 2 2 F fal + fNi exp i h + k + exp i k + l + exp i h + l So : F=fAl +3fNi if h,k,l all even or odd F=fAl -fNi if h,k,l are mixed even or odd Again, since simple cubic, intensity at all points. But each point is ‘chemically sensitive’. Atomic Scattering Factor f (aka Structure or Form Factor) Atoms are of a comparable size to the wavelength of the x-rays and so the scattering is not point like. There is a small path difference between waves scattered at either side of the electron cloud. Increases with • For x-rays, scattering strength depends on electron density • Core electrons localized around nucleus, so density profile ~spherical atom iGr cos 2 r dr d cos d (r )e atom 40 Mean Atomic Scattering Factors iGr f (r )e dr Zn 30 20 Zr 10 0 Ca 0 0.5 1.0 -1 [sin()]/ (Å ) Only at 2=0 does f=Z 1.5 Diffraction Methods • Any particle will scatter and create a diffraction pattern • Beams are selected by experimentalists depending on sensitivity –X-rays not sensitive to low Z elements, but neutrons are –Electrons sensitive to surface structure if energy is low – Atoms (e.g., helium) sensitive to surface only Electron X-Ray Neutron λ = 1A° λ = 1A° λ = 2A° E ~ 104 eV E ~ 0.08 eV E ~ 150 eV interact with electron Penetrating interact with nuclei Highly Penetrating interact with electron Less Penetrating Lattice Vibrations When a wave propagates along one direction, 1D problem. Use harmonic oscillator approx., meaning amplitude vibration small. Atoms are tied via bonds, so they can't vibrate independently. The vibrations take the form of collective modes which propagate. Phonons are quanta of lattice vibrations. Longitudinal Waves Transverse Waves Monatomic Linear Chain The force on the nth atom; a a •The force to the right; K (u n+1 u n ) •The force to the left; K (u n u n1 ) Un-1 Un Un+1 The total force = Force to the right – Force to the left Thus, Newton’s equation for the nth atom is mun K un un1 K un un+1 .. m u n K (un +1 2un + un 1 ) Eqn’s of motion of all atoms are of this form, only.. the value of ‘n’ varies 0 un A exp i kxn t u n 2un Brillouin Zones of the Reciprocal Lattice Reciprocal Space Lattice: 2/a 4K M k 4 a 3 a 2 a 0 a a 2 a 3 a 4 a 1st Brillouin Zone (BZ=WS) Each BZ contains identical information about the lattice q 20 sin ka / 2 2nd Brillouin Zone 3rd Brillouin Zone 0 K m There is no point in saying that 2 adjacent atoms are out of phase by more than (e.g., 1.2 =-0.8 ) Modes outside first Brillouin zone can be mapped to first BZ m m m m m 1 λ=10a m 2 λ=5a Wave velocity • GROUP VELOCITY is velocity of energy transfer • If vphase > vgroup, wave is dispersive • vphase=k/k vgroup k dk / dk o a coska / 2 • The slope of the dispersion curve gives the group velocity. • Near the origin k = 0 the phase and group velocity must be the same (dispersionless) • The edges of the FBZ correspond to neighboring atoms moving in opposite directions. The energy cannot propagate along the crystal. vk kmax 0 Standing wave at the boundaries of the BZ (λ=2a) Diatomic Chain(2 atoms in primitive basis) 2 different types of atoms of masses m1 and m2 are connected by identical springs (n-2) (n-1) K (n) K m1 m2 (n+1) K K m1 (n+2) m m2 a) a b) Un-2 Un-1 Un Un+1 Un+2 Since a is the repeat distance, the nearest neighbors separations is a/2 Two equations of motion must be written; One for mass m1, and One for mass m2. m1un1 K 2un1 un 2 un 1, 2 m2un 2 K 2un 2 un1 un +1,1 + + 2 2 1 2 2 2 1 4 2 2 2 2 1 2 2 sin qa / 2 2 1/ 2 • As there are two values of ω for each value of k, the dispersion relation is said to have two branches A Optical Branch Upper branch is due to the positive sign of the root. B C Acoustical Branch –л/a 0 л/a 2л/a k Negative sign: k for small k. Dispersionfree propagation of sound waves • At C, M oscillates and m is at rest. • At B, m oscillates and M is at rest. • This result remains valid for a chain containing an arbitrary number of atoms per unit cell. A when the two atoms oscillate in antiphase Neon, FCC Monatomic NaCl: FCC, Diatomic 3D Dispersion curves • Every crystal has 3 acoustic branches, 1 longitudinal and 2 transverse • Every additional atom in the primitive basis contributes 3 further optical branches (again 2 transverse and 1 longitudinal) • P atoms/primitive unit cell means 3 acoustic branches and 3(p-1) optical branches=3p branches • One for each degree of freedom Stress Tensor Forces divided by an area are called stresses. The stresses/tractions tk (or k) along axis k are ... in components we can write this as tk1 t k tk 2 t k3 ti s ij n j where sij is the stress tensor and nj is a surface normal. The stress tensor describes the forces acting on planes within a body. Due to the symmetry condition s ij s ji there are only six independent elements. s ij xx yx zx xy yy zy xz yz zz The vector normal to the corresponding surface The direction of the force vector acting on that surface s11 s12 s13 s11 s 21 s 22 s 23 s12 s s s s i Sijs j 31 32 33 13 Similarly, the strain tensor can be written as: We can therefore write: s i Cij j s12 s13 s 22 s 23 s 23 s 33 11 12 13 11 12 13 21 22 23 12 22 23 31 32 33 13 23 33 Voigt’s notation: Additional simplification of the stress-strain 11 1 23 4 relationship can be realized through simplifying the matrix notation 22 2 13 5 for stresses and strains. 33 3 12 6 We can replace the indices as follows: • For the generalized case, Hooke’s law may be expressed as: s C where, i ij j C Stiffness (or Elastic cons tan t ) i Sijs j S Compliance • Both Sijkl and Cijkl are fourth-rank tensor quantities. • The consequence of the symmetry in the stress and strain tensors is that only 36 components of the compliance and stiffness tensors are independent and distinct terms. s 1 C11 s 2 C21 s C 3 31 s 4 C41 s C 5 51 s 6 C61 C12 C22 C32 C42 C52 C62 C13 C14 C23 C24 C33 C34 C43 C44 C53 C54 C63 C64 C15 C25 C35 C45 C55 C65 C16 1 But only one-half of the C26 2 non-diagonal terms are C36 3 independent constants since Cij = Cji C46 4 30 C56 5 + 6 21 2 C66 6 Independent terms abc 90o The cubic axes are equivalent, so the diagonal components for normal and shear distortions must be equal. And cubic is not elastically isotropic because a deformation along a cubic axis differs from the stress arising from a deformation along the diagonal. e.g., [100] vs. [111] Zener Anisotropy Ratio: A 2C44 C 44 C11 C12 x x=(a-b)/2 or C44 C11 C12 2 • These quantized normal modes of vibration are called PHONONS • PHONONS are massless quantum mechanical particles which have no classical analogue. – They behave like particles in momentum space or k space. • Phonons are one example of many like this in many different areas of physics. Such quantum mechanical particles are often called “Quasiparticles” Examples of other Quasiparticles: Photons: Quantized Normal Modes of electromagnetic waves. Magnons: Quantized Normal Modes of magnetic excitations in magnetic solids Excitons: Quantized Normal Modes of electron-hole pairs Polaritons: Quantized Normal Modes of electric polarization excitations in solids + Many Others!!! Phonon spectroscopy = Conditions for: inelastic scattering Constraints: Conservation laws of Momentum Energy In all interactions involving phonons, energy must be conserved and crystal momentum must be conserved to within a reciprocal lattice vector.