Download Mean and Standard Deviation of a binomial

Lesson 10.2
μ
(mean)= np
Where n = number of trials, p = probability of
success
σ2 (variance) = npq
where q = probability of failure
σ ( standard deviation) =
 Suppose
a dart player has probability p
of hitting the bull’s-eye with a single dart,
and all attempts are independent. Prove
that the expected number of bull’s eyes
the player will hit in two attempts is 2p.
Binomial distribution:
0
1q2
1
2pq
2
1p2
0q2 + 2pq + 2p2
2p(q+p)
2p
 In
the binomial distribution of tossing a
far coin 250 times and counting the
number of heads, what is the mean and
standard deviation?
 Mean: np
 250
* .5 = 125
 Sd: (npq).5
 (250 * .5 * .5).5
 7.91
 For
some binomial probability
distribution, μ = 45 and σ = 6, find n and p.
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