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Sampling distributions
Example
• Take random sample of 1 hour periods in an
ER.
• Ask “how many patients arrived in that one
hour period ?”
• Calculate statistic, say, the sample mean.
Sample 1:
2
3
1
Mean = 2.0
Sample 2:
3
4
2
Mean = 3.0
Situation
• Different samples produce different results.
• Value of a statistic, like mean or proportion,
depends on the particular sample obtained.
• But some values may be more likely than
others.
• The probability distribution of a statistic
(“sampling distribution”) indicates the
likelihood of getting certain values.
Let’s investigate how sample means
vary….
(click here for Live Demo)
Web link to try it yourself:
http://www.ruf.rice.edu/~lane/stat_sim/sampling_dist/
Sampling distribution of mean
IF:
• data are normally distributed with mean 
and standard deviation , and
• random samples of size n are taken, THEN:
The sampling distribution of the sample means is also
normally distributed.
The mean of all of the possible sample means is .
The standard deviation of the sample means (“standard
error of the mean”) is SE ( X )  
n
Example
• Adult nose length is normally distributed with mean
45 mm and standard deviation 6 mm.
• Take random samples of n = 4 adults.
• Then, sample means are normally distributed with
mean 45 mm and standard error 3 mm
[from SE ( X )   / n  6 / 4  3 mm ].
Using empirical rule...
• 68% of samples of n=4 adults will have an
average nose length between 42 and 48 mm.
• 95% of samples of n=4 adults will have an
average nose length between 39 and 51 mm.
• 99% of samples of n=4 adults will have an
average nose length between 36 and 54 mm.
What happens if we take larger
samples?
• Adult nose length is normally distributed
with mean 45 mm and standard deviation 6
mm.
• Take random samples of n = 36 adults.
• Then, sample means are normally
distributed with mean 45 mm and standard
error 1 mm [from 6/sqrt(36) = 6/6].
Again, using empirical rule...
• 68% of samples of n=36 adults will have an
average nose length between 44 and 46 mm.
• 95% of samples of n=36 adults will have an
average nose length between 43 and 47 mm.
• 99% of samples of n=36 adults will have an
average nose length between 42 and 48 mm.
• So … the larger the sample, the less the
sample averages vary.
What happens if data are not
normally distributed?
Let’s investigate that, too …
Sampling Distribution Demo: (Live Demo)
http://www.ruf.rice.edu/~lane/stat_sim/sampling_dist/
Central Limit Theorem
• Even if data are not normally distributed, as long as you take
“large enough” samples, the sample averages will at least be
approximately normally distributed.
• Mean of sample averages is still 
• Standard error of sample averages is still
SE ( X )   / n
• In general, “large enough” means more than 30
measurements, but it depends on how non-normal population
is to begin with.
Big Deal?
Let’s look at some useful applications...
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