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Geological Time Geochronology – The Science of Dating Rocks and Rock Layers The Geological Time Line Originally layers of rocks were defined by the assemblages of fossils found within them. The Cambrian, Ordivician, Devonian and Silurian Eras were defined by rocks found in England in the 1800’s. Only later were these eras dated. These eras were named for the ancient tribes that lived in these areas of Great Britain. The 4.6 billion years of Geologic Time broken into Eons, Eras, Periods (and subPeriods), Epochs and Ages. Notice the increasingly smaller increments of time. We find more subdivisions in the Phanerozoic as life began to flourish and change. Phanerozoic Eon • The Phanerozoic Eon is broken into 3 eras which are further subdivided into periods and epochs (and more informally into ages). How do we date Rocks? Relative Age Dating – The ability to determine whether one layer of rock is older or younger than other (a qualitative method) Absolute Age Dating – The ability to date rocks quantitatively. Rock layers are given fairly exact age determinations Geochronolgy – The Science of Dating Rocks Relative Age Dating Techniques: 1) Stratigraphy – layers of rock are often continuous for kilometers in all directions. These rock layers can often be defined by their mineral composition, fossil assemblages or other physical features. Generally deeper layers are older and therefore the relative ages of rock layers can be compared. Folding of rocks can put older layers above younger layers. Stratigraphy – Rock Layers • Newer layers of rock are deposited above older layers. • Each layer contains a specific rock type and often a specific assemblage of fossils. • Tectonic processes can overturn rock layers. Geochronolgy – The Science of Dating Rocks Relative Age Dating Techniques: 1) Stratigraphy continued – A classic layer called the Gubbio Clay separates the Cretaceous and the Tertiary Periods and can be traced across Europe. This layer had a higher than normal concentration of iridium – an element far more common in meteorites than the Earth’s crust. The Gubbio Clay • The thin black clay layer separates the white fossil-depleted Tertiary layer from the reddish fossil-rich Cretaceous layer below. • The black clay layer is enriched in the element Ir (iridium) Geochronolgy – The Science of Dating Rocks Absolute Age Dating Techniques: 1) Dendochronolgy – using tree rings to date recent geological or archeological events. This method can be extended back over a thousand years by overlapping the rings of trees. 2) Varved Clays in Glacial Lakes Seasonal Climate Changes can be seen in the sediments of the lake. Dendrochronolgy • Rings from many trees or wood planks both young and old can be overlapped to determine climatic conditions for as many as a thousand years. Obviously this method only useful for very modern (archaeological) studies. Varved Clays • The photograph above shows the layers at the bottom of a glacial lake. Thick layers form during the summer when the glacier melts faster. • Warmer years show the thickest varves. • Geologist s often drill cores from the bottom of glacial lakes. • Again this technique only measures climate within the Holocene period. Geochronology – The Science of Dating Rocks Absolute Age Dating Techniques: 3) Radiometric dating using radioisotopes: We can determine the decay rates for many radioactive isotopes. If the rock contains these isotopes, then we can determine how much these isotopes can decay. 4) Fossils (Paleontology) – Individual species have been dated throughout the fossil record. Most fossils have time ranges in which they existed in the fossil record which can give approximate dates. However large assemblages of fossils can help pinpoint dates more exactly Radiometric Dating • Most igneous rocks contain atoms which are unstable. These “radioisotopes” decay by ejecting particles and releasing radiation. • Uranium – 238 goes through a sequence of decays before eventually turning into lead – 206. The rate at which this decay occurs has be en determined scientifically 238U/206Pb decay chain Radiometric Dating • The rate of decay is measured in halflives. In the case of U-238, half of the material in a rock will decay into Pb-206 in 4.5 billion years. After several halflives the amount of original U- 238 decreases to a half, a quarter, an eighth and so on… Radiometric dating • Scientists must choose an appropriate radioisotope for each application. Which isotope would be useful for dating: a) Rocks that are over 2 billion years old? b) Dinosaur fossils that are about 200 million years old? c) The wood from an ancient ship found at the bottom of the Sea? Video • Carbon Dating (How Does it Work?): http://www.youtube.com/watch?v=ud kQwW6aLik&feature=related – this video also discusses paleomagnetism and 40K/40Ar and 238U/208Pb and Rb/Sr and thermoluminescence • Radiocarbon Dating: http://www.youtube.com/watch?v=2i o5opwhQMQ&feature=relmfu • Radiometric Dating (A how-to): http://www.youtube.com/watch?v=19 20gi3swe4&feature=related Video • Radiocarbon Dating Clip: (History Channel) http://www.youtube.com/watch?v=10 XD9lJpDAY&list=LPhNseJZQOmkE&in dex=8&feature=plcp • Dating The Radiocarbon Way: http://www.youtube.com/watch?v=xKvq6VLe4s&feature=related (very clear, very technical) Radiometric Dating • Igneous rocks containing zircon (ZrSiO4) have atoms of U that substitute for Zr in the crystal structure. • Zircons are perfect for radiometric dating because they do not erode easily and they contain radioisotopes. • Once the zircon crystallizes, from that point on the ratio of U-238/Pb-206 begins to decrease. 238U/206Pb Age Dating • Uranium-lead dating is usually performed on the mineral zircon (ZrSiO4), though it can be used on other durable Zr-containing minerals. • The zircon mineral incorporates uranium and thorium atoms into its crystalline structure, but strongly rejects lead. Therefore we can assume that the entire lead content of the zircon is radiogenic. 238U/206Pb dating employs a very long half life (4.5 billion years) and therefore can be used to date extremely old rocks – as old as the age of the Earth. • The amount of U-238 is at its greatest when the rock solidifies from a magma – after this point the rock gains no additional U-238 and this radioisotope decays from this point onward. • The other commonly used radioisotope is 40K/40Ar. Potassium is a common element in feldspars – the most common silicate. • 238U/206Pb Age Dating Carbon-14 Dating • Carbon-14 Dating is more commonly used by Archeologists. • Since all living things contain carbon, this method can date any organic or formerly living thing • C-14 exists is a rare isotope of carbon, existing as only about 1 part per trillion carbon atoms. Thus a sample of carbon needs to be reasonably large (up to 1 gram) Carbon-14 Dating • Carbon-14 is produced continually in the atmosphere and becomes part of many CO2 atoms. • Carbon dioxide is continually taken up by plants and moves through the carbon cycle. • Animals and plants continue to ingest new C-14 as long as they are living. Once an organism dies, it stops taking up new C-14 and the ratio of C-14/C12 starts to decrease (following the pattern of halflives seen below) Carbon-14 Dating • Scientists measure the ratio of C-14/C -12 to determine how many half lives have occurred and can date the sample Radiometric Dating Questions 1) Rn-222 has a half-life of 3.82 days, how long until only 1/16 of the original remains? 2) After 24 days, only 2 mg of an original 128 mg sample remains. What is the half life of this radioisotope? Radiometric Dating Questions 3) If the half-life of iodine-131 is 8.10 days, how long will it take a 50.00 g sample to decay to 6.25 g? 4) The half-life of hafnium-156 is 0.025 s. How long will it take a 560 g sample to decay to one-fourth its original mass? Lets get more technical – Carbon Dating Equation Above is the equation for the beta decay of C-14. 14C → 14N + -1 e (neutron is converted into proton and a high 0 energy electron (β-particle)). • t = age of the fossil (or the date in which the fossil died) • t1/2 = half-life of C-14 (which equals 5730 years) • N/NO = relative amount of the radioisotope in a sample in comparison to the amount of the radioisotope in a “fresh” sample. • ln (natural logarithm) Carbon Dating • A sample of flesh from the flesh of a Woolly Mammoth found in the Siberian permafrost contains 23.2 mg of C-14. An equal mass of the flesh of a modern animal contains 49.6 mg of C14. The half-life of C-14 is 5730 years. What is the age of the frozen Mammoth? Carbon Dating • N/NO = • t1/2 = Carbon Dating • A sample of wood from a fire found at an archaeological site containing he bones of a Neanderthal man contains 7.28 mg of C-14. An equal mass of a modern piece of wood contains 34.6 mg of C-14. The half-life of C-14 is 5730 years. What is the age of the wood and likely the Neanderthal man? Carbon Dating • N/NO = • t1/2 = 238U/206Pb Age Dating The mathematical expression that relates radioactive decay to geologic time, is: • • • • • where t = age of the sample Dt = number of atoms or amount of the radiogenic stable daughter isotope in the sample at time t D0 = number of atoms or amount of the daughter stable isotope in the original composition (at t = 0) Pt = number of atoms or amount of the parent radioisotope in the sample at time t λ = the decay constant for the parent radioisotope, equal to ln(2) / t1/2. where t1/2 is expressed in the same time units as t. • In its simplest form, this can be rearranged to yield the age t: t = 1 ln [(Dt – DO) + 1] λ Pt λ = ln 2 t1/2 238U/206Pb Age Dating 1) An igneous rock contains zircons. U-238 from the zircons has a mass of 3.25 mg. The mass of Pb-206 from the zircon has a mass of 1.35 mg. What is the age of the zircon and therefore the igneous rock? t = 1 ln [(Dt – DO) + 1] λ Pt λ = ln 2 t1/2 238U/206Pb Age Dating 2) A volcanic lava flowed over a sedimentary rock contain trilobite fossils. U-238 from the zircons in the lava has a mass of 1.17 mg. The mass of Pb-206 from the zircon has a mass of 0.235 mg. What is the age of the zircon and therefore the lava flow? How old are the trilobites? t = 1 ln [(Dt – DO) + 1] λ Pt λ = ln 2 t1/2