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Chapter 9 Equations, Inequalities and Problem Solving Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. 9.1 The Addition Property of Equality Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Linear Equations An equation is of the form “expression = expression.” x + 7 = 10 An equation contains an equal sign and an expression does not. Equations 7x 6x 4 3(3 y 5) 10 y Expressions 7x 6x 4 y 1 11 y 21 Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Martin-Gay, Developmental Mathematics, 2e 3 Linear Equations Linear Equation in One Variable A linear equation in one variable can be written in the form Ax + B = C where A, B, and C are real numbers and A ≠ 0. Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Martin-Gay, Developmental Mathematics, 2e 4 Using the Addition Property to Solve Equations Addition Property of Equality Let a, b, and c represent numbers. Then a=b Also, a=b and a + c = b + c and a – c = b – c are equivalent equations. are equivalent equations. Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Martin-Gay, Developmental Mathematics, 2e 5 Example Solve x – 4 = 7 for x. Check: x47 x4474 x 0 11 x 11 x47 11 4 7 77 Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Martin-Gay, Developmental Mathematics, 2e 6 Example Solve: y – 1.2 = –3.2 – 6.6 y 1.2 3.2 6.6 y 1.2 9.8 y 1.2 1.2 9.8 1.2 y 8.6 Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Martin-Gay, Developmental Mathematics, 2e 7 Example Solve: 6x + 8 – 5x = 8 – 3 6 x 8 5x 8 3 6 x 5x 8 8 3 x 8 5 x 88 58 x 3 Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Martin-Gay, Developmental Mathematics, 2e 8 Example Solve: 3(3x – 5) = 10x 3(3x 5) 10 x 3(3x ) 3(5) 10 x 9 x 15 10 x 9 x 15 9 x 10 x 9 x 15 x Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Martin-Gay, Developmental Mathematics, 2e 9 Example Solve: 4p – 11 – p = 2 + 2p – 20 3p – 11 = 2p – 18 3p + (– 2p) – 11 = 2p + (– 2p) – 18 Simplify both sides. Add –2p to both sides. p – 11 = –18 Simplify both sides. p – 11 + 11 = –18 + 11 Add 11 to both sides. p = –7 Simplify both sides. Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Martin-Gay, Developmental Mathematics, 2e 10 Example Solve: 5(3 + z) – (8z + 9) = – 4z 15 + 5z – 8z – 9 = – 4z 6 – 3z = – 4z 6 – 3z + 4z = – 4z + 4z 6+z=0 6 + (–6) + z = 0 + (–6) z = –6 Use distributive property. Simplify left side. Add 4z to both sides. Simplify both sides. Add –6 to both sides. Simplify both sides. Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Martin-Gay, Developmental Mathematics, 2e 11