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Section 3.2 Solving Systems of Equations Algebraically Use algebraic computation to get precise solutions The Substitution Method (One Equation into Another) The Elimination Method (Adding Equations) How to identify Consistent Systems (one solution – lines cross) Inconsistent Systems (no solution – parallel lines) Dependent Systems (infinitely many solutions – same line) Comparing the Methods Definition Simultaneous Linear Equations Consider the pair of equations together 4x + y = 10 -2x + 3y = -12 Each line has infinitely many pairs (x, y) that satisfy it. But taken together, only one pair (3, -2) satisfies both. Finding this pair is called solving the system. In 3.1, you learned to solve a system of two equations in two variables by graphing (approximation). In this section you will learn two ways to solve linear systems algebraically (precision). Solving Systems of Linear Equations Using the Substitution Method if a=b and b=c then a=c Substitution Method - Example You can pick either variable to start – you will get the same (x,y) solution. It may take some work to isolate a variable: Solve for (A)’s y or ( A) 2 x y 6 ( B) 3x 4 y 4 ( A1 ) y 6 2 x ( B ) 3 x 4(6 2 x) 4 ( B ) 5 x 24 4 ( B ) 5 x 20 ( B ) x 4 1 2 a solution ( A1 ) y 6 2(4) ( A1 ) y 2 Solution : (4,2) ( A) 2 x y 6 ( B) 3x 4 y 4 Solve for (A)’s x ( A) 2 x y 6 ( B) 3x 4 y 4 ( A1 ) 2 x 6 y ( A1 ) x 3 12 y ( B) 3(3 12 y ) 4 y 4 ( B) 9 32 y 4 y 4 ( B) 52 y 5 ( B) y 2 1 2 a solution ( A) 2 x (2) 6 ( A) x 4 Solution : (4,2) if a=b and c=d then a+c=b+d Using the Elimination (Addition) Method if a=b then ca=cb Elimination Method – Even Multiples When one variable term is an even multiple of its matching variable term, you only have to multiply one equation. Let’s eliminate y: Multiply (A) by -2 ( A) 5 x 4 y 22 ( B) 3 x 8 y 18 2( A) 10 x 8 y 44 ( B) 3 x 8 y 18 (C ) 13x 26 (C ) x 2 1 2 a solution ( A) 5(2) 4 y 22 ( A) 10 4 y 22 ( A) 4 y 12 ( A) y 3 Solution : (2,3) ( A) 5 x 4 y 22 ( B) 3 x 8 y 18 Elimination Method – No Multiples When no variable terms are even ( A) 2 x 3 y 17 multiples, you have to multiply both equations by different numbers. ( B) 5 x 7 y 29 Let’s eliminate y: Multiply (A) by 7 and (B) by -3 ( A) 2 x 3 y 17 ( B ) 5 x 7 y 29 7( A) 14 x 21 y 119 3( B ) 15 x 21 y 87 (C ) x 32 (C ) x 32 1 2 a solution ( A) 2(32) 3 y 17 ( A) 64 3 y 17 ( A) 3 y 81 ( A) y 27 Solution : (32,27) Clearing Fractions or Decimals Systems without a Single Point Solution 0 = 4 untrue Inconsistent Systems - how can you tell? An inconsistent system has no solutions. (parallel lines) Substitution Technique ( A) ( B) y 3 x 5 y 3 x 2 3 x 5 3 x 2 3x 3x 5 2 2 2 7 0 inconsiste nt Elimination Technique ( A) ( B) y 3 x 5 y 3 x 2 1( A) y 3 x 5 ( B ) y 3 x 2 0 7 inconsiste nt 0 = 0 or n = n Dependent Systems – how can you tell? A dependent system has infinitely many solutions. (it’s the same line!) Substitution Technique Elimination Technique ( A) 3y 2x 6 ( B) 12 y 8 x 24 ( A) 3y 2x 6 ( B ) 12 y 8 x 24 ( B) 8 x 12 y 24 x 32 y 3 ( A) 3 y 2( 32 y 3) 6 3y 3y 6 6 6 6 dependent 4( A) 12 y 8 x 24 ( B ) 12 y 8 x 24 00 dependent Application Problem TEMPORARY HELP A law firm had to hire several workers to help finish a large project. From the billing records shown in Illustration 3, determine the daily fee charged by the employment agency for a clerk-typist and for a computer programmer. The daily fees: $105 for a clerk-typist $185 for a programmer