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Solving a system of equations by multiplying When using the multiplication method, one of the equations will need to be multiplied by something to make one of the variable combinations eliminate themselves 6x + 5y = 19 -3(2x + 3y = 5 ) 6x + 5y = 19 -6x - 9y = -15 In this example, the X’s can eliminate themselves if we multiply the bottom row by -3 What we know now is that the answer will be (?, -1) To find the value of x you Use either equation from The question and substitute In to find your answer -4y = 4 -4 -4 y = -1 6x + 5(-1) = 19 The 6x -5 = 19 +5 +5 Answer 6x = 24 Is 6 6 x = 4 (4, -1) -50 ( 0.2x – 1.5y = -1) In this example, the 10 ( x – 4.5y = 1) X’s can eliminate -10x + 75y = 50 themselves if we multiply the top row 10x – 45y = 10 by -50 and the bottom row by 10 This way you will have no decimals and the X’s will eliminate themselves at the same time What we know now is that the answer will be (?, 2) The Answer Is (10, 2) 30y = 60 30 30 y=2 10x – 45(2) = 10 10x -90 = 10 +90 +90 10x = 100 10 10 x = 10 Pg. 454 – 455 4 – 28 even skip 22