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Measurement • • • • • • • • Accuracy vs Precision Percent Error Significant Figures Scientific Notation Temperature Conversions Dimensional Analysis Conversion Factors SI Conversions Number vs. Quantity • Quantity = number + unit UNITS MATTER!! A. Accuracy vs. Precision • Accuracy - how close a measurement is to the accepted value • Precision - how close a series of measurements are to each other ACCURATE = CORRECT PRECISE = CONSISTENT A. Accuracy vs. Precision B. Percent Error • Indicates accuracy of a measurement % error experimental accepted accepted your value given value 100 B. Percent Error • A student determines the density of a substance to be 1.40 g/mL. Find the % error if the accepted value of the density is 1.36 g/mL. % error 1.40 g/mL 1.36 g/mL 1.36 g/mL % error = 2.94 % 100 C. Significant Figures • Indicate precision of a measurement. • Recording Sig Figs – Sig figs in a measurement include the known digits plus a final estimated digit 2.31 cm C. Significant Figures • Counting Sig Figs – Digits from 1-9 are always significant 739 – Zeros between two other sig figs are always significant 5085 – One or more additional zeros to the right of both the decimal place and another sig digit are significant 2.60 – Count all numbers EXCEPT: • Leading zeros -- 0.0025 • Trailing zeros without a decimal point -- 2,500 C. Significant Figures Counting Sig Fig Examples 1. 23.50 4 sig figs 2. 402 3 sig figs 3. 5,280 3 sig figs 4. 0.080 2 sig figs C. Significant Figures • Calculating with Sig Figs – Multiply/Divide - The # with the fewest sig figs determines the # of sig figs in the answer (13.91g/cm3)(23.3cm3) = 324.103g 4 SF 3 SF 3 SF 324 g C. Significant Figures • Calculating with Sig Figs (con’t) – Add/Subtract - The # with the lowest decimal value determines the place of the last sig fig in the answer 3.75 mL + 4.1 mL 7.85 mL 7.9 mL C. Significant Figures • Calculating with Sig Figs (con’t) – Exact Numbers do not limit the # of sig figs in the answer • Counting numbers: 12 students • Exact conversions: 1 m = 100 cm • “1” in any conversion: 1 in = 2.54 cm C. Significant Figures Practice Problems 5. (15.30 g) ÷ (6.4 mL) 4 SF 2 SF = 2.390625 g/mL 2.4 g/mL 2 SF 6. 18.9 g - 0.84 g 18.06 g 18.1 g D. Scientific Notation • A way to express any number as a number between 1 and 10 (coefficient) multiplied by 10 raised to a power (exponent) • Number of carbon atoms in the Hope diamond • 460,000,000,000,000,000,000,000 atoms • 4.6 x 1023 atoms coefficient exponent D. Scientific Notation 65,000 kg 6.5 × 104 kg • Converting into Sci. Notation: – Move decimal until there’s 1 digit to its left. Places moved = exponent – Large # (>1) positive exponent Small # (<1) negative exponent – Only include sig figs – all of them! D. Scientific Notation Practice Problems 7. 8. 9. 2,400,000 g 2.4 0.00256 kg 2.56 7.0 10-5 km 10. 6.2 104 mm 6 10 g -3 10 kg 0.000070 km 62,000 mm D. Scientific Notation • Calculating with Sci. Notation (5.44 × 107 g) ÷ (8.1 × 104 mol) = Type on your calculator: 5.44 EXP EE 7 ÷ 8.1 EXP EE 4 EXE ENTER = 671.6049383 = 670 g/mol = 6.7 × 102 g/mol D. Scientific Notation Practice Problems 4 1010 cm2 11. (4 x 102 cm) x (1 x 108cm) 12. (2.1 x 10-4kg) x (3.3 x 102 kg) 6.9 10-2 kg2 13. (6.25 x 102) ÷ (5.5 x 108) 1.1 x 10-6 14. (8.15 x 104) ÷ (4.39 x 101) 1.86 x 103 15. (6.02 x 5.01 x 1022 1023) ÷ (1.201 x 101) E. Temperature • Temperature – measure of the average KE of the particles in a sample of matter Kelvin oC 273.15 9o Fahrenheit C 32 5 5o Celsius F 32 9 E. Temperature • Convert these temperatures: 298.15 ______________K 1) 25oC 2) 298 -15oF = ______________ K 3) 41.85 oC 315K = ______________ 4) 298 288K = ______________ oF = F. Dimensional Analysis • Dimensional Analysis is also called Unit Analysis and is a great way to solve problems in chemistry (or any time). F. Dimensional Analysis • Dimensional Analysis – A tool often used in science for converting units within a measurement system • Conversion Factor – A numerical factor by which a quantity expressed in one system of units may be converted to another system F. Dimensional Analysis Problem-Solving Steps 1. Analyze 2. Plan 3. Compute 4. Evaluate F. Dimensional Analysis • The “Factor-Label” Method – Units, or “labels” are canceled, or “factored” out g 3 cm 3 cm g F. Dimensional Analysis • Steps to solving problems: 1. Identify starting & ending units. 2. Line up conversion factors so units cancel. 3. Multiply all top numbers & divide by each bottom number. 4. Check units & answer. G. Conversion Factors Fractions in which the numerator and denominator are EQUAL quantities expressed in different units Example: 1 in. = 2.54 cm Factors: 1 in. and 2.54 cm 2.54 cm 1 in. How many minutes are in 2.5 hours? Conversion factor 2.5 hr x 1 cancel 60 min 1 hr = 150 min G. Conversion Factors Write conversion factors that relate each of the following pairs of units: 1. Liters and mL 1 L = 1000 mL 1L 1000 mL 2. Hours and minutes 3. Meters and kilometers 1 hr 60 min 1000 m 1 km H. SI Prefix Conversions 1. Memorize the following chart. (next slide) 2. Find the conversion factor(s). 3. Insert the conversion factor(s) to get to the correct units. 4. When converting to or from a base unit, there will only be one step. To convert to or from any other units, there will be two steps. H. SI Prefix Conversions move right move left Prefix teragigamegakilohectodekaBASE UNIT decicentimillimicronano- Symbol T G M k h da --d c m n Factor 1012 109 106 103 102 101 100 10-1 10-2 10-3 10-6 10-9 H. SI Prefix Conversions a. cm to m b. m to µm c. ns to s d. kg to g 1m 100 cm 1m 106 µm 1s 109 ns 1 kg 1000 g H. SI Prefix Conversions 4) 805 Tb = 14 8.05 x 10 ______________ b bytes Terabytes 1012 b 805 Tb 1 = 805 x 1012 bytes 1 Tb = 8.05 x 1014 bytes H. SI Prefix Conversions 5) 400. g = ______________ kg 6) 57 Mm = ______________ nm Dimensional Analysis Practice 1. You have $7.25 in your pocket in quarters. How many quarters do you have? 2. How many seconds are in 1.4 days? Plan: days hr min seconds 3. How many milliliters are in 1.00 quart of milk? 4. You have 1.5 pounds of gold. Find its volume in cm3 if the density of gold is 19.3 g/cm3. 5. Your European hairdresser wants to cut your hair 8.0 cm shorter. How many inches will he be cutting off? 6. Milton football needs 5.5 yards for a 1st down. How many cm is this? 7. A piece of wire is 1.3 m long. How many 1.5cm pieces can be cut from this wire? 8. How many liters of water would fill a container that measures 75.0 in3?