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The Official Police Procedure for Investigating Murders If 1 Body is found then you must seal off surrounding squares to avoid contaminating the crime scene. Special police tape is used! Each piece of tape is equal to the length of 1 square. 1 Body 4 Squares 8 Pieces of tape Another example of how to seal a crime scene…. 1 Body 6 Squares 12 Pieces of tape The reason for the 2 extra squares is that they contained other vital evidence to the crime. When you investigate a murder involving 1 body, you have to seal off the 4 squares surrounding it. The reason for this is so that investigators can walk around the perimeter. Other squares can be added to these 4 squares in any direction if they contain vital forensic evidence! Notice the cross in the middle. This is where the body is! How many… • Bodies? • Squares? • Pieces of tape? Solution 1 Body 6 Squares 12 Pieces of tape How many… • Bodies? • Squares? • Pieces of tape? Solution 2 Bodies 11 Squares 20 Pieces of tape How many… • Bodies? • Squares? • Pieces of tape? Solution 2 Bodies 6 Squares 10 Pieces of tape How many… • Bodies? • Squares? • Pieces of tape? Solution 1 Body 13 Squares 26 Pieces of tape To complete your initial crime scene investigator training, you have to show that you fully understand the procedure for dealing with a murder. Tasks Investigate different situations with 1 body….. • How many squares will you seal off? • How much police tape will your require? • Can you find a rule (using words/algebra) linking the numbers of squares to the length of police tape? For those of you wanting to become officers, you should also complete the following…. • Investigate for 2, 3, 4,….n number of bodies • Investigate a crime scene without a body Solution Let N = number of bodies A = Area of crime scene T = Tape used Number of bodies (N) 0 Perimeter (T) 2A + 2 1 2A 2 2A – 2 3 2A – 4 N 2A – 2N + 2 = 2(A – N + 1) Solution Let N = number of bodies A = Area of crime scene T = Tape used Number of bodies (N) 0 Area of crime scene (A) T/2 – 1 1 T/2 2 T/2 + 1 3 T/2 + 2 N T/2 + (N – 1)