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Pascal Diagonal Summation: combinatorial proofs Dr Gerard Tel Informatics Utrecht Univ. Pascal triangle Summation boxes Additive: C(n,k) = C(n-1,k) + C(n-1,k-1) Sum of Row n is Twice Rowsum n-1: 2n Combinatorial Coefficients Combinatorial Coefficient Subsets k-of-n Multiplicative: C(n,k) = n! / k! (n-k)! Diagonal Sums Fibonacci Number Morse codes Dash has duration of two dots Duration 1: ● E Duration 2: ●● I ▬ T Duration 3: ●●● S ●▬ A ▬● N Morse codes of duration 4 ●●●● H ●●▬ U There are 5, 3 start with ● ●▬● R 2 start with ▬ ▬ ●● ▬▬ D M Morse codes of duration 5 Starting with ● ●●●●● 5 ●●●▬ V ●●▬● F ●▬●● L ●▬ ▬ W Starting with ▬ ▬●●● ▬●▬ ▬ ▬● B K G Together 8 codes. Connection with Fibonacci numbers? Morse codes of duration 6 Starting with ● ●●●●●● ●●●●▬ 4 ●●●▬● roger ●●▬●● É ●●▬ ▬ Ü ●▬●●● ●▬●▬ ●▬ ▬● wait Ä P Starting with ▬ ▬●●●● ▬●●▬ ▬●▬● ▬ ▬●● ▬▬▬ 6 X C Z O Together 13 codes. ●▬ ▬ ▬ ▬ ▬● ▬ ▬ ●▬ ▬ J Q Y Conclusions • Morse numbers are Fibonacci numbers • Combinatorial arguments look easy but are hard • May increase intuition • Summation: Poly(k) C(n,k) with Absorption Rule (Mathematica)