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CHAPTER 5 INDICES AND LOGARITHMS What is Indices? Examples of numbers in index form. 33 (3 cubed or 3 to the power of 3) 25 (2 to the power of 5) 3 and 5 are known as indices. 27=33, 3 is a base and 3 is an index 32=25, 2 is a base and 5 is an index So , why we use indices? Indices can make large numbers much more manageable, as a large number can be reduced to just a base and an index. Eg: 1,048,576 = 220 LAWS OF INDICES Multiplication of indices with same base: am an = am + n bm + n = bm bn Example: x4 x3 = x 4 + 3 = x 7 1 4 7 4+(-7) 3 y y =y =y = 3 y 2x+3 = 2x 23 = 8(2x) y 1 y – 2 y 2 3 = 3 3 = 3 2 3 Division of indices with same base: am ÷ an = am n bm n = bm ÷ bn Example: 9 c 9 4 = c5 = c 4 c x 3 x-2 3 = 2 3 25 4p 2 p 1 3 1 p 5 3 3 3 12 p 3p Raising an index to a power (am)n = amn bmn = (bm)n EXAMPLE: (b4)3 = b43 = b12 (32)3 = 323 = 36 (2x)2 = 22x (2y+1)3 = 23y + 3 32c = (3c)2 n (ab) = n n a b EXAMPLE: (xy)3 = x3 y3 23 33 = 63 (ab)-2 = a-2 b-2 Law 5: a b n n a n b a a b b a b 5 2 2 4 2 5 5 25 EXAMPLE: 2 2 3 2 2 2 2 3 2 2 2 2 2 2 2 Other properties of index Zero index: a0 = 1, a 0 1 n a a-n Negative index: Fractional index: 1 n a a m n n a a 2 3 64 n m 3 64 a n 2 4 m 2 Law 5: a b n n a n b a a b b a b 5 2 2 4 2 5 5 25 EXAMPLE: 2 2 3 2 2 2 2 3 2 2 2 2 2 2 2 Example Solve (a) 91 – x = 27 1 p + 1 3 – p (b) 2 4 = 16 (c) Solve the simultaneous equation 2x.42y = 8 1 x -y 5 .25 = 125 (d) 4x+3 – 4x+2 = 6 Solution (a) (b) (c) (d) x = -0.5 p = 11 x = -1, y = 1 x = -1.5