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Transcript
Notes on Schmidt Trigger Physics 120, David Kleinfeld, Spring 2015 This circuit uses feedback to minimize the effect of noise on a threshold transition. It involves hysteresis (shown below), in terms of a higher level for the up than down transition, with the output from the comparator. First, the case without feedback: Add feedback resistor R4. 1 K V L gives !! !!! !! ! + !! + ! !! !!!"# !! =0 Case of Vout = 0 The NPN output transistor acts as a short, so K V L gives V! − V! V! V! + + =0 R! R! R! so V! = R!R! V R ! R! + R ! R! + R ! R ! ! Usually R4 is large (the fedback voltage is small) so that, expanding to order (1/R4), V! ≈ R! R ! R! 1− R! + R ! R ! R! + R ! V! and we see that the feedback lowers the lower threshold relative to the case without feedback. Case of Vout ≠ 0 The NPN output transistor acts as an open circuit, so K V L gives V! − V! V! V! − 𝑉!"# + + =0 R! R! R! and This leads to a morass of algebra 𝑉! = V!"# − V! V!"# − V! + =0 R! R! R! + R ! 𝑅! 𝑅! 𝑅! 𝑅! 𝑅! + 𝑅! 𝑅! + 𝑅! 𝑅! R! + R ! − 𝑅! 𝑅! 𝑅! 𝑉! 𝑉! + R! R! + R ! that simplifies when R4 is large and becomes: 𝑉! ≈ R! R! V! 1+ V R! + R ! R ! V! ! and we see that the feedback raises the upper threshold relative to the case without feedback. • When the value of the input heads from high to low, the "0" to "VP" transition causes an increase in threshold that adds hysteresis and prevents jitter. • When the value of the input heads from low to high, the "VP" to "0" transition causes a decrease in threshold that adds hysteresis and prevents jitter. 2 Example Simple case is R! = R ! ; R ! = 10R! ; V! = V! ∴ the threshold voltages are: V! = 𝑉! 1 1− ≈ 0.45 𝑉! ; 𝑉!"# 𝑡 = 0! = 0 2 10 𝑉! 1 1+ ≈ 0.55 𝑉! ; 𝑉!"# 𝑡 = 0! ≈ 1.05 𝑉! 2 10 3