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Phasor Relationships for Circuit Elements (7.4) Dr. Holbert September 4, 2001 ECE201 Lect-5 1 Phasor Relationships for Circuit Elements • Phasors allow us to express current-voltage relationships for inductors and capacitors much like we express the current-voltage relationship for a resistor. • A complex exponential is the mathematical tool needed to obtain this relationship. ECE201 Lect-5 2 I-V Relationship for a Resistor + i(t) v(t) R v(t ) R i (t ) – Suppose that i(t) is a sinusoid: i(t) = IM ej(wt+q) Find v(t). ECE201 Lect-5 3 Computing the Voltage v(t ) R i(t ) R I M e v(t ) VM e jwt jq jwt jq VI R ECE201 Lect-5 4 Class Example • Learning Extension E7.5 ECE201 Lect-5 5 I-V Relationship for a Capacitor + i(t) v(t) C – dv(t ) i (t ) C dt Suppose that v(t) is a sinusoid: v(t) = VM ej(wt+q) Find i(t). ECE201 Lect-5 6 Computing the Current jwt jq dv(t ) dVM e i(t ) C C dt dt i(t ) jwCVM e jwt jq ECE201 Lect-5 jwCv(t ) 7 Phasor Relationship • Represent v(t) and i(t) as phasors: V = VM q I = jwC V • The derivative in the relationship between v(t) and i(t) becomes a multiplication by jw in the relationship between V and I. ECE201 Lect-5 8 Example v(t) = 120V cos(377t + 30) C = 2mF • What is V? • What is I? • What is i(t)? ECE201 Lect-5 9 Class Example • Learning Extension E7.7 ECE201 Lect-5 10 I-V Relationship for an Inductor + i(t) v(t) L – di (t ) v(t ) L dt V = jwL I ECE201 Lect-5 11 Example i(t) = 1mA cos(2p 9.15•107t + 30) L = 1mH • What is I? • What is V? • What is v(t)? ECE201 Lect-5 12 Class Example • Learning Extension E7.6 ECE201 Lect-5 13 Circuit Element Phasor Relations (ELI and ICE man) Element V/I Relation Phasor Relation Phase Capacitor I = C dV/dt I = j ω C V I leads V = ωCV 90° by 90º Inductor V = L dI/dt V = j ω L I V leads I by 90º = ωLI 90° Resistor V = I R V=RI In-phase = R I 0° ECE201 Lect-5 14 Phasor Diagrams • A phasor diagram is just a graph of several phasors on the complex plane (using real and imaginary axes). • A phasor diagram helps to visualize the relationships between currents and voltages. ECE201 Lect-5 15 An Example 2mA 40 + + 1mF w = 377 1kW – VC V + – VR – ECE201 Lect-5 16 An Example (cont.) I = 2mA 40 VR = 2V 40 VC = 5.31V -50 V = 5.67V -29.37 ECE201 Lect-5 17 Phasor Diagram Imaginary Axis Real Axis V VC ECE201 Lect-5 VR 18 MATLAB Exercise • Let’s use MATLAB to plot an ac current and voltage, and then to graphically determine the lead-lag relationship • Start MATLAB on your computer • We begin by creating a time vector >> t = 0 : 0.0005 : 0.025; • Next, we create the voltage and current >> vt = 170 * cos(377*t+10*pi/180); >> it = 100 * cos(377*t-65*pi/180); ECE201 Lect-5 19 MATLAB Exercise • Now we will graph v(t) and i(t) >> plot(t,vt,'b',t, it,'r--'); >> xlabel('Time (sec)'); >> ylabel('Voltage (Volts) or Current (Amps)'); >> title('Household AC Voltage-Current'); >> legend('v(t)=170cos(377t+10)', 'i(t)=100cos(377t-65)'); ECE201 Lect-5 20 MATLAB Exercise • From the graphs created: – Determine whether the current leads the voltage, or vice versa – Determine the amount of lead by the current or voltage • Compare the voltage-current lead-lag relationship obtained by graphical means above to an analytic solution which you should be able to compute ECE201 Lect-5 21