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Transcript
Capacitance in DC Circuits
01 – Capacitance in DC
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The intent of this presentation is to present enough information to provide the reader with a
fundamental knowledge of Capacitance in DC Circuits and to better understand basic Michelin
system and equipment operations.
01 – Capacitance in DC
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Capacitance in DC
It will be recalled that electrons are loosely held in the rings of each atom of a good conductor such
as copper, and only a small force is required to dislodge these electrons. Good conductive materials
have an abundance of free electrons in their structure. On the other hand, it is a characteristic of
insulating materials to have the electrons firmly held in the rings of each atom of the material, and
considerable force is required to remove these electrons. Insulating materials have practically no free
electrons in their structure.
If an insulating material, sometimes called a dielectric, is placed between two plates of a good
conducting material, an elementary form of a capacitor has been developed.
01 – Capacitance in DC
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Capacitance in DC
The diagram below represents an elementary capacitor consisting of two metal plates separated from
each other by a thickness of dielectric. Under normal conditions with the capacitor de-energized, the
electrons in the dielectric revolve around the positive center of each atom in circular orbits.
01 – Capacitance in DC
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Capacitance in DC
In Fig. 2 the capacitor is connected to a DC voltage source. Electrons will flow from the negative side
of the source to Plate 2 and electrons will flow from Plate 1 back to the source of supply. This is the
normal direction of electron flow from negative to positive.
Plate 1
D.C.
Source
Plate 1
D.C.
Source
Plate 2
Fig. 2
Capacitor Charging
Plate 2
Fig. 3
Capacitor Fully Charging
The flow will continue until the potential across the two metal plates is equal to the DC source voltage
and then the flow will stop. There will be practically no flow of electrons through the dielectric (or
insulating) material between the plates. Plate 2 will now have a surplus of electrons and Plate 1 will
have a deficiency of electrons. The electrons in the atoms of the dielectric material will be attracted
toward the positive plate. However, they cannot flow from Plate 1 to Plate 2 because the electrons in
a good dielectric (insulating) material are firmly held in each atom. This causes the electron orbits of
each atom in the dielectric to become distorted into a form of elliptical pattern as illustrated in Fig. 3.
01 – Capacitance in DC
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Capacitance in DC
In Fig. 3 the capacitor is completely charged with the voltage across the capacitor plates equal to the
DC source voltage. Therefore, there is no electron flow. To simplify these illustrations, only three
atoms are shown. In an actual capacitor, the atoms in the dielectric with their orbits in this distorted
pattern would be legion in number.
Plate 1
Plate 1
D.C.
Source
D.C.
Source
Plate 2
Fig. 2
Capacitor Charging
Plate 2
Fig. 3
Capacitor Fully Charging
If the capacitor is disconnected from the DC source supply, the large number of surplus electrons on
the negative plate will be held to the plate by the attraction of the positive charge on the other plate.
The electrostatic field effect created by the charged plates will cause the atoms of the dielectric to
remain in a state of distortion. This distortion of the atoms is a manifestation of the electrical energy
stored in the capacitor.
01 – Capacitance in DC
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Capacitance in DC
In Fig. 4, a resistor is connected directly across the capacitor. The capacitor will now discharge
through the conducting resistor. Electrons on the negatively charged plate (Plate 2) will flow off the
plate through the resistor toward Plate 1 until they are equally distributed in the circuit, and then the
flow of electrons will cease. The electron flow from the capacitor plate indicates that the electrical
energy stored in the electrostatic field is being released from the capacitor.
As the electrons flow from the negatively charged plate, the electron orbits of each atom of the
dielectric will gradually change from the distorted elliptical pattern illustrated in Fig. 4 to the normal
circular ring pattern as shown in Fig. 5.
01 – Capacitance in DC
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Capacitance in DC
If too great a voltage is applied to the capacitor, the electrons in the atoms of the dielectric will be
pulled from orbit. This breakdown in the insulating ability of the dielectric releases the energy stored
in the capacitor and, in the case of a solid dielectric material usually permanently destroys its
usefulness.
01 – Capacitance in DC
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Capacitance in DC
Capacitance
A capacitor can store electrical energy and also return this energy back into an electric circuit. It is
important at this point to understand what the term capacitance actually means. Capacitance is
really the property of a circuit or circuit component which allows it to store electrical energy in
electrostatic form.
Capacitors store energy, but other components also create capacitance effect. For example, the two
wires of a circuit separated by air will act as a capacitor, or adjacent turns of a coil winding separated
only by the insulation of the wire will have some capacitance effect. The standard unit of
measurement for capacitance is the FARAD and may be defined as follows:
A capacitor has a capacitance of one farad when a change of one volt across its plates
results in the charge of one coulomb.
01 – Capacitance in DC
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Capacitance in DC
Capacitance
The farad is too large of a unit of measure for the typical capacitor. Therefore a smaller unit is used
called the microfarad (F).
Microfarad (F) = 10-6
Nanofarad (F) = 10-9
Picofarads (F) = 10-12
The capacitance of a capacitor can be increased by:
1. Increasing the plate area and, therefore, the area of the dielectric under stress.
2. Having the metal plates as close as possible with a resultant decrease in the thickness of its
dielectric.
3. Using a dielectric with as high a dielectric constant as practical.
01 – Capacitance in DC
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Capacitance in DC
Capacitance
The charge on the plates of a capacitor with a given applied voltage is directly proportional to the
capacitance of the capacitor. This charge is measured in coulombs and is directly proportional to the
charging voltage. Therefore, if the charge on the plates is directly proportional to both the
capacitance and the impressed voltage:
The formula for calculating Capacitance is: Q = V * C
This expression may be written in three forms:
Q  V  C ,  or V 
Q
Q
,  or C 
C
V
To illustrate the use of this formula,
Assume a capacitor takes a charge
of 0.005 coulombs when connected across a 100-volt DC source. Determine the capacitance of the
capacitor in microfarads:
01 – Capacitance in DC
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Capacitance in DC
Dielectric Characteristics
Three factors were listed earlier in this unit, which affect the capacitance of a capacitor. One of these
factors is the type of insulating material used for the dielectric. In practice, most capacitors are
constructed using a dielectric having a higher dielectric constant than air. Just what does the term
"dielectric constant" mean?
First, the dielectric constant of an insulating material measures its effectiveness when used as the
dielectric of a capacitor. Air is assumed to have a dielectric constant of 1. If a two-plate capacitor with
air as a dielectric has the air replaced by paper impregnated with paraffin, its capacitance will
increase. If the capacitance is doubled when using paper in place of air, then the dielectric constant
of paper will be 2. This dielectric constant indicates the degree of distortion of the orbits of the
electrons in the insulating material used for the dielectric for a given applied voltage. In the following
table are the dielectric constants of some typical insulating material.
01 – Capacitance in DC
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Capacitance in DC
Dielectric Characteristics
MATERIAL
DIELECTRIC CONSTANT (K)
1.0
4.0 to 10.0
4.3 to 4.7
7.0
4.1 to 4.9
2.4 to 3.0
6.4 to 7.0
2.2 to 4.6
2.0 to 2.6
1.9 to 2.2
3.0 to 7.0
2.0 to 4.2
Air
Bakelite
Castor Oil
Cellulose Acetate
Pyrex Glass
Lucite
Mica
Insulating Oils
Paper
Paraffin
Rubber Compounds
Hard Rubber
01 – Capacitance in DC
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Capacitance in DC
Dielectric Characteristics
If the voltage across the plate of a capacitor becomes too high, the dielectric may rupture. In other
words, an excessively high potential tears electrons from the orbits of the atoms of the dielectric
structure and the dielectric becomes a conducting material. This results in permanent damage to the
dielectric as it is burned or punctured by the high potential.
To assure adequate insulation protection, the insulating qualities of various dielectrics are given a
"Dielectric Strength Rating", either in "volts-per-centimeter" or the "volts-per-mil" of thickness required
to break down the dielectric. The dielectric strength rating is not to be confused with the dielectric
constant as these two terms are entirely different. For example, the dielectric of paper is about 2 and
that of Pyrex glass is approximate 4. However, the dielectric strength in terms of volts\millimeter for
the paper is about 1200 volts as compared with only 325 volts of the Pyrex glass.
01 – Capacitance in DC
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Capacitance in DC
Capacitors in Parallel
An increase in the capacitance can also be obtained by increasing the number of plates, which make
up the capacitor. This is the same as increasing the plate area.
Lead
Lead
Fig. 6
Fig. 6 shows a multi-plate capacitor with the plates in such a way as to have a maximum in plate
area. It will be noted that alternate plates are common or paralleled.
01 – Capacitance in DC
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Capacitance in DC
Capacitors in Parallel
When capacitors are connected in parallel, the effect is the same as increasing the number of plates.
This means that the total capacitance is equal to the sum of the capacitance of the individual
capacitors. For example, in Fig. 7, three capacitors of 30, 10, and 15 microfarads are connected in
parallel across the line voltage, designated as V. The charge on each capacitor in coulombs is:
The total Capacitance
Is equal to:
C1 + C2 + C3
C1=30F
C2=10F
The voltage across the
parallel circuit is:
VT = VC1 = VC2 = VC3
C3=15F
VT
Fig. 7 Capacitors in Parallel
QC1 = VC1 x C1
QC2 = VC2 x C2
QC3 = VC3 x C3
The total charge of the three capacitors in parallel is:
Q Total = VT x CT
Q Total = QC1 + QC2 + QC3
The total capacitance for the three capacitors in parallel is:
CT = C1 + C2 + C3
CT = 30F + 10F + 15F = 55F
01 – Capacitance in DC
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Capacitance in DC
Capacitors in Series
When capacitors are in series, there is a single circuit path with all the dielectrics of the individual
capacitors connected in succession. This is equivalent to increasing the thickness of the dielectric of
one capacitor. As a result the total capacitance of the circuit is less than the capacitance of any
individual capacitor.
When capacitors are charged in a series circuit, the same numbers of electrons flow to each
capacitor. Hence, each capacitor has the same charge in coulombs or each has the same value of
charge (Q).
C1=30F
C2=10F
C3=15F
VT
Fig. 8 Capacitors in Series
01 – Capacitance in DC
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Capacitance in DC
Capacitors in Series
The charge on each capacitor is the same:
C1=30F
QT = QC1 = QC2 = QC3
C2=10F
C3=15F
VT
The voltage across the total series circuit is:
Fig. 8 Capacitors in Series
VT = VC1 + VC2 + VC3
The voltage can also be expressed with charge and capacitance:
01 – Capacitance in DC
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Capacitance in DC
Capacitors in Series
To find the equation to calculate the total
capacitance in a series capacitive circuit,
let’s substitute the previous equation for
charge into the voltage relationship.
C1=30F
C2=10F
C3=15F
VT
Fig. 8 Capacitors in Series
Since (QT = QC1 = QC2 = QC3) then the following equation is true:
Using the microfarad ratings of the three capacitors given in Fig. 8, the total capacitance of the series
capacitor bank is:
01 – Capacitance in DC
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Capacitance in DC
Capacitors in Series
Exercises:
1. Calculate CT.
C1=1F
C2=1F
VT
2. Calculate CT
C1=1F
C2=1F
VT
01 – Capacitance in DC
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Capacitance in DC
Capacitors in Series
Exercises:
3. Calculate CT.
C1= ? F
VT
C2=7F
C3=8F
01 – Capacitance in DC
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Capacitance in DC
Capacitors in Series
Exercises:
4. Calculate CT.
5. Calculate Q on each capacitor
6. Calculate V on each capacitor
C1=200F
C2=50F
C3=10F
VT = 60 volts
01 – Capacitance in DC
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Capacitance in DC
Capacitors in Series
Exercises:
7. Calculate CT, QT, QC1, QC2, VC1, VC2
VC1
C1=20F
VC2
C2=30F
VT=100V
01 – Capacitance in DC
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Capacitance in DC
Capacitors in Series
Exercises:
8. Calculate CT, QT
10F
5F
50F
VT=50V
01 – Capacitance in DC
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20F
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