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living with the lab conductivity sensor implementation © 2011 LWTL faculty team living with the lab DISCLAIMER & USAGE The content of this presentation is for informational purposes only and is intended only for students attending Louisiana Tech University. The author of this information does not make any claims as to the validity or accuracy of the information or methods presented. Any procedures demonstrated here are potentially dangerous and could result in injury or damage. Louisiana Tech University and the State of Louisiana, their officers, employees, agents or volunteers, are not liable or responsible for any injuries, illness, damage or losses which may result from your using the materials or ideas, or from your performing the experiments or procedures depicted in this presentation. If you do not agree, then do not view this content. The copyright label, the Louisiana Tech logo, and the “living with the lab” identifier should not be removed from this presentation. You may modify this work for your own purposes as long as attribution is clearly provided. 2 living with the lab conductivity measurement circuit • we use the same voltage divider circuit used earlier for the photoresistor circuit ∆𝑉𝑐𝑜𝑛𝑑𝑢𝑐𝑡𝑖𝑣𝑖𝑡𝑦 𝑠𝑒𝑛𝑠𝑜𝑟 + ∆𝑉10𝑘Ω 𝑟𝑒𝑠𝑖𝑠𝑡𝑜𝑟 = 5 𝑣𝑜𝑙𝑡𝑠 • what happens to the electrical resistance of the water as it becomes more salty? it decreases • if the resistance of the salt water decreases, then what happens to the voltage drop across the conductivity sensor? it decreases • if the voltage drop across the conductivity sensor decreases, then how does this influence the voltage drop across the 10kΩ resistor? it increases digital output = 5V when HIGH (set high periodically to measure conductivity) analog input • (measures voltage across 10kΩ resistor) 10 kΩ so, increasing the salinity of the water causes the analog input read by the Arduino to (increase or decrease)? 0 to 1023 3 living with the lab what happens when salt is added to water???? • The ionically bonded NaCl molecules dissociate into Na+ and Cl- ions and become mobile • they are surrounded by polar water molecules (they are hydrated) electrodes (no voltage applied) Cl- H O H Cl- Na+ Na+ ClCl- Na+ Na+ Na+ Cl- Cl- Cl- Cl- Cl- Na+ Cl- Na+ Na+ Cl- Cl- ClNa+ Na+ ClNa+ ClNa+ Na+ Cl- Na+ water Cl- Na+ Na+ Cl- Na+ Na+ Na+ 4 living with the lab applying voltage to induce electron flow electrons are really not directly conducting through the water from one electrode to the other (like when electrons move through a copper wire) 5V e- e- 10 kΩ anode – oxidation cathode – reduction (loss of electrons) e- (gain of electrons) eCl- ClCl2 Cl- Na+ Cl- Cl Cl- ClCl- Cl- OHNa+ Na+ Cl reduction occurs at the negatively charged cathode: Na+ Na+ Na+ Na+ Cl- Na+ ion migration ee- H H2O 2 𝐻2 𝑂(𝑙) + 2𝑒 − → 𝐻2 𝑔 + 2𝑂𝐻− (𝑎𝑞) H H2O OH- ClNa+ Cl- Cl- Na+ Na+ Na+ Na+ is a spectator ion oxidation occurs at the positively charged anode: 2 𝐶𝑙 − 𝑎𝑞 → 𝐶𝑙2 𝑔 + 2𝑒 − It seems like an Na+ would accept an electron and be reduced . . . why not??? 5 living with the lab why is H2O reduced and not Na+ ??? reactions further down in the table are less likely to occur • reactions with positive voltages will occur spontaneously • you must apply external voltage across the electrodes to make a reaction with a negative potential occur 6 living with the lab the net reaction of conductivity system the net reaction occurring in the system is . . . • we must apply at least 2.19 V to the conductivity circuit to drive the reaction • applying 5 V is sufficient, and higher voltages will increase the rate of oxidation & reduction reactions 7 living with the lab system wiring digital output = 5V when HIGH (set high periodically to measure conductivity) analog input (measures voltage across 10kΩ resistor) 10 kΩ 8