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COLORADO STATE UNIVERSITY
ECE 332: ELECTRONIC PRINCIPLES II
HOMEWORK 8
Figures for problems 1, 2, and 3.
(b)
1. In an active-loaded differential amplifier of the form shown in figure (a), all transistors are
characterized by π‘˜ β€² (π‘Š/𝐿) = 3.2 π‘šπ΄/𝑉 2 , and |𝑉𝐴 | = 20𝑉. Find the bias current 𝐼 for which the
gain π‘£π‘œ /𝑣𝑖𝑑 = 100𝑉/𝑉.
2. Consider the active-loaded MOS differential amplifier of figure (a) in two cases:
a) Current source 𝐼 is implemented with a simple current mirror.
b) Current source 𝐼 is implemented with the modified Wilson current mirror shown in the
figure (b).
For the simple mirror 𝑅𝑆𝑆 = π‘Ÿπ‘œ |𝑄𝑆 and for the Wilson mirror 𝑅𝑆𝑆 β‰… π‘”π‘š7 π‘Ÿπ‘œ7 π‘Ÿπ‘œ5, and assuming
that all transistors have the same |𝑉𝐴 | and π‘˜ β€² (π‘Š/𝐿), show that for case (a) 𝐢𝑀𝑅𝑅 =
2(𝑉𝐴 /𝑉𝑂𝑉 )2 and for case (b) 𝐢𝑀𝑅𝑅 = 2√2(𝑉𝐴 /𝑉𝑂𝑉 )3 , where 𝑉𝑂𝑉 is the overdrive voltage that
corresponds to a drain current of 𝐼/2. For π‘˜ β€² (π‘Š/𝐿) = 10π‘šπ΄/𝑉 2, 𝐼 = 1π‘šπ΄, and |𝑉𝐴 | = 10𝑉,
find CMRR for both cases (in dB).
3. Consider an active-loaded differential amplifier figure (a) with the bias current source
implemented with the modified Wilson mirror of figure (b) with 𝐼 = 200πœ‡π΄ (shown below). The
transistors have |𝑉𝑑 | = 0.5𝑉 and π‘˜ β€² (π‘Š/𝐿) = 5 π‘šπ΄/𝑉 2 . What is the lowest value of the total
power supply (𝑉𝐷𝐷 + 𝑉𝑆𝑆 ) that allows each transistor to operate with|𝑉𝐷𝑆 | β‰₯ |𝑉𝐺𝑆 |? (Wilson
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mirror has the same output impedance as the cascode mirror. The minimum power supply
voltage allowed can be calculated assuming that Vds and Vgs for all the transistors are the
same.)
4. Consider the circuit in the figure shown below with the device geometries, in πœ‡π‘š, shown in
the table. Let 𝐼𝑅𝐸𝐹 = 225πœ‡π΄, |𝑉𝑑 | = 0.75𝑉 for all devices, πœ‡π‘› πΆπ‘œπ‘₯ = 180πœ‡π΄/𝑉 2 , πœ‡π‘ πΆπ‘œπ‘₯ =
60πœ‡π΄/𝑉 2 , |𝑉𝐴 | = 9𝑉 for all devices, 𝑉𝐷𝐷 = 𝑉𝑆𝑆 = 1.5𝑉.
Determine the width of 𝑄6 , π‘Š, that will ensure that the op amp will not have a systematic
offset voltage (i.e. (W/L)6/(W/L)4 = 2* ((W/L)7/(W/L)5)) ). Then, for all devices evaluate 𝐼𝐷 ,
|𝑉𝑂𝑉 |, |𝑉𝐺𝑆 |, π‘”π‘š , and π‘Ÿπ‘œ .
Provide your results in a table similar to the table below. Also find 𝐴1 (the DC gain for the first
stage amplifier), 𝐴2 (the DC gain for the second stage amplifier), the open-loop voltage gain
(i.e. the DC gain of the entire circuit), the input common-mode range, and the output voltage
range. Neglect the effect of 𝑉𝐴 on the bias current.
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