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Both pairs of opposite sides are parallel  Both pairs of opposite sides are congruent  The opposite angles are congruent  The diagonals bisect each other  Any pair of consecutive angles are supplementary  AB  DC AD  BC AB II DC AD II BC  DAB   BCD  ADC   ABC  DAB suppl.  ABC  BCD suppl.  AE  EC DE  EB ADC Has all properties of a parallelogram  All angles are right angles  Diagonals are congruent  Two disjoint pairs of consecutive sides are congruent  The diagonals are perpendicular  One diagonal is the perpendicular bisector of the other  One of the diagonals bisects a pair of opposite angles  One pair of opposite angles are congruent  Has all properties of a parallelogram and of a kite (half properties become full properties  All sides are congruent  The diagonals bisect the angles  The diagonals are perpendicular bisectors of each other  The diagonals divide the rhombus into four congruent right triangles  Has all properties of a rectangle and a rhombus  The diagonals form four isosceles right triangles  The legs are congruent  The bases are parallel  The lower base angles are congruent  The upper base angles are congruent  The diagonals are congruent  Any lower base angle is supplementary to any upper base angle  Given: ABCD is a rectangle DA = 5x CB = 25 DC = 2x Find: a.) The value of x b.) The perimeter of ABCD a.) 5x = 25 x=5 b.) DA= 25 CB = 25 DC = 10 AB = 10 Perimeter = 25 + 25 + 10 + 10 Perimeter = 70 Given: ABCD is a parallelogram AD  AB Prove: ABCD is a rectangle Statements Reasons 1. ABCD is a parallelogram 1. Given 2. AD  AB 3. <DAB is a right < 2. Given 4. ABCD is a rectangle 4. If a parallelogram contains at least one right <, it is a rectangle 3. Perpendicular lines form right <s Given: ABCD is a parallelogram <DAB = n <ABC = 2n Find: m <BCD and m < ADC 2n+n=180 3n=180 n=60 2n=120 m <BCD = 60 m<ADC = 120 Given: ABCD is a rhombus AB = 2x-5 BC = x a.) Find the value of x b.) Find the perimeter Given: ABCD is a parallelogram Prove: ▲AED ▲BEC Given: m<CAB = n m<CDB = 4n AD = 2n-53 Find: a.) AD b.) m<ACD 2x-5 = x X=5 AB = 2x-5 AB = 5 Perimeter = 5 + 5 + 5 + 5 Perimeter = 20 Statements Reasons 1. ABCD is a parallelogram 1. Given 2. BC  AD 2. In a parallelogram, opp. Sides are congruent 3. AC Bisects BD 3. In a parallelogram, diagonals bisect each other 4. BE  ED 4. If a ray bisects a segment, it divides the segment into 2 congruent segments 5. BD Bisects AC 6. AE  EC 5. Same as 3 7. ▲AED 7. SSS (2,4,6)  ▲BEC 6. Same as 4 n + 4n = 180 5n = 180 n = 36 4n = 144 2n-53 = 19 Therefore, AD = 19  m<ACD = 144 (In an isosceles trapezoid, upper base angles are congruent) Rhoad, Richard, George Milauskas, and Robert Whippie. Geometry for Enjoyment and Challenge. New Edition. Evanston, Illinois: McDougall, Littell & Company, 1997. 241-248. Print.