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INCOMPLETE DOMINANCE AND CODOMINANCE 1 INCOMPLETE DOMINANCE F1 hybrids have an appearance somewhat in between the phenotypes of the two parental varieties. Example: snapdragons (flower) red (RR) x white (rr) r r RR = red flower rr = white flower R R 2 INCOMPLETE DOMINANCE r r R Rr Rr R Rr Rr produces the F1 generation All Rr = pink (heterozygous pink) 3 INCOMPLETE DOMINANCE 4 CODOMINANCE Two alleles are expressed equally in multiple alleles in heterozygous individuals. Example: blood type 1. 2. 3. 4. type A type B type AB type O = = = = IAIA or IAi IBIB or IBi IAIB (equally expressed) ii (recessive alleles) 5 CODOMINANCE PROBLEM Example: homozygous male Type B (IBIB) X heterozygous female Type A (IAi) IA i IB IAIB IBi 1/2 = IAIB (A & B = equally expressed) IB IAIB IBi 1/2 = IBi (B dominant over i) 6 ANOTHER CODOMINANCE PROBLEM • Example: male Type O (ii) x female type AB (IAIB) IA IB i IAi IBi i IAi IBi 1/2 = IAi 1/2 = IBi 7 CODOMINANCE Question: If a boy has a blood type O and his sister has blood type AB, what are the genotypes and phenotypes of their parents? boy - type O (ii) X girl - type AB (IAIB) 8 CODOMINANCE Answer: 9 SEX-LINKED TRAITS Traits (genes) located on the sex chromosomes Sex chromosomes are X and Y XX genotype for females XY genotype for males Many sex-linked traits carried on X chromosome 10 SEX-LINKED TRAITS Example: Eye colour in fruit flies Sex Chromosomes fruit fly eye colour XX chromosome - female Xy chromosome - male 11 SEX-LINKED TRAIT PROBLEM Example: Eye colour in fruit flies (red-eyed male) x (white-eyed female) XRY x XrXr Remember: the Y chromosome in males does not carry these traits. Xr Xr RR = red eyed Rr = red eyed R X rr = white eyed XY = male Y XX = female 12 SEX-LINKED TRAIT SOLUTION: Xr XR XR Xr Y Xr Y Xr XR Xr Xr Y 50% red eyed female 50% white eyed male 13 FEMALE CARRIERS 14 GENETIC PRACTICE PROBLEMS 15 BREED THE P1 GENERATION tall (TT) x dwarf (tt) pea plants t t T T 16 SOLUTION: tall (TT) vs. dwarf (tt) pea plants t t T Tt Tt produces the F1 generation T Tt Tt All Tt = tall (heterozygous tall) 17 BREED THE F1 GENERATION tall (Tt) vs. tall (Tt) pea plants T t T t 18 SOLUTION: tall (Tt) x tall (Tt) pea plants T t T TT Tt t Tt tt produces the F2 generation 1/4 (25%) = TT 1/2 (50%) = Tt 1/4 (25%) = tt 1:2:1 genotype 3:1 phenotype 19