Download Slide 1

Survey
yes no Was this document useful for you?
   Thank you for your participation!

* Your assessment is very important for improving the work of artificial intelligence, which forms the content of this project

Document related concepts
no text concepts found
Transcript
Mendelian Genetics
Gregor Mendel – 1822-1884
Asexual Reproduction
• Bacteria can reproduce as often as every 12
minutes – and may go through 120 generations
in one day
• Thus capable of producing 6 x 1035 offspring
per day
• Bacteria often produce 1 mutation per 1000
replications of DNA
• So for fast-growing species, mutation is a good
way to respond to a changing environment
Why Sex?
John
Maynard
Smith
Sexual reproduction leads to
genetic variation via:
• Independent assortment
during meiosis
• Crossing over during
meiosis
• Random mixing of
gametes (sperm and egg)
Independent Assortment
Prophase I
of meiosis
Nonsister chromatids
held together
during synapsis
Pair of homologs
Chiasma
Centromere
TEM
Anaphase I
Anaphase II
Daughter
cells
Recombinant chromosomes
• The random nature of fertilization adds to the
genetic variation arising from meiosis.
• Any sperm can fuse with any egg.
– A zygote produced by a mating of a woman and
man has a unique genetic identity.
– An ovum is one of approximately 8,388,608
possible chromosome combinations (223).
– The successful sperm represents one of
8,388,608 different possibilities (223).
– The resulting zygote is composed of 1 in 70
trillion (223 x 223) possible combinations of
chromosomes.
– Crossing over adds even more variation to this.
Mendelian Genetics
Gregor Mendel – 1822-1884
Two possible types of inheritance
• One possible explanation of heredity is a “blending”
hypothesis
– The idea that genetic material contributed by two
parents mixes in a manner analogous to the way
blue and yellow paints blend to make green
• An alternative to the blending model is the
“particulate” hypothesis of inheritance: the gene idea
– Parents pass on discrete heritable units, later
known as genes
Mendel’s time
Today
Mendel’s garden at Brunn (Brno) Monastery
Some genetic vocabulary
– Character: a heritable
feature, such as
flower color
– Trait: a variant of a
character, such as
purple or white
flowers
Garden Pea
Flower Structure
TECHNIQUE
1
2
Parental
generation
(P)
3
Stamens
Carpel
4
RESULTS
First filial
generation
offspring
(F1)
5
In Mendel’s Experiments:
• Mendel chose to track
– Only those characters that varied in an “either-or”
manner
• Mendel also made sure that
– He started his experiments with varieties that were
“true-breeding”
• In a typical breeding experiment
– Mendel mated two contrasting, true-breeding
varieties, a process called hybridization
Breeding Terminology
• The true-breeding parents
– Are called the P (parental) generation
• The hybrid offspring of the P generation
– Are called the F1 (filial) generation
• When F1 individuals self-pollinate
– The F2 generation is produced
EXPERIMENT
P Generation
(true-breeding
parents)
Purple
flowers
White
flowers
EXPERIMENT
P Generation
(true-breeding
parents)
F1 Generation
(hybrids)
Purple
flowers
White
flowers
All plants had purple flowers
Self- or cross-pollination
EXPERIMENT
P Generation
(true-breeding
parents)
Purple
flowers
White
flowers
F1 Generation
(hybrids)
All plants had purple flowers
Self- or cross-pollination
F2 Generation
705 purpleflowered
plants
224 white
flowered
plants
Mendel developed a hypothesis to explain his
results that consisted of four ideas
• Alternative versions of genes (different alleles)
account for variations in inherited characters
• For each character, an organism inherits two alleles,
one from each parent
• If two alleles differ, then one, the dominant allele, is
fully expressed in the organism’s appearance. The
other, recessive allele has no effect on a hybrid
organism’s appearance
• The two alleles for each character segregate
(separate) during gamete formation
Law of Segregation
P Generation
Appearance:
Purple flowers White flowers
Genetic makeup:
pp
PP
p
Gametes:
P
Law of Segregation
P Generation
Appearance:
Purple flowers White flowers
Genetic makeup:
pp
PP
p
Gametes:
P
F1 Generation
Appearance:
Genetic makeup:
Gametes:
Purple flowers
Pp
1/
1/
2 p
2 P
Law of Segregation
P Generation
Appearance:
Purple flowers White flowers
Genetic makeup:
pp
PP
p
Gametes:
P
F1 Generation
Appearance:
Genetic makeup:
Gametes:
Purple flowers
Pp
1/
1/
2 p
2 P
Sperm from F1 (Pp) plant
F2 Generation
P
p
PP
Pp
Pp
pp
P
Eggs from
F1 (Pp) plant
p
3
:1
3
Phenotype
Genotype
Purple
PP
(homozygous)
Purple
Pp
(heterozygous)
1
2
1
Purple
Pp
(heterozygous)
White
pp
(homozygous)
Ratio 3:1
Ratio 1:2:1
1
Test cross
TECHNIQUE
Dominant phenotype,
unknown genotype:
PP or Pp?
Predictions
If purple-flowered
parent is PP
Sperm
p
p
Recessive phenotype,
known genotype:
pp
or
If purple-flowered
parent is Pp
Sperm
p
p
P
P
Pp
Eggs
Pp
Eggs
P
Pp
Pp
pp
pp
p
Pp
Pp
RESULTS
or
All offspring purple
1/
2
offspring purple and
1/ offspring white
2
EXPERIMENT
YYRR
P Generation
yyrr
Gametes YR
yr
F1 Generation
Predictions
YyRr
Hypothesis of
dependent assortment
Hypothesis of
independent assortment
Sperm
or
Predicted
offspring of
F2 generation
1/
Sperm
1/
2
YR
1/
2
2
YyRr
YYRR
2
1/
4
1/
Yr
4
yR
1/
4
yr
4
YR
YYRR
YYRr
YyRR
YyRr
YYRr
YYrr
YyRr
Yyrr
YyRR
YyRr
yyRR
yyRr
YyRr
Yyrr
yyRr
yyrr
YR
Eggs
1/
YR
yr
1/
1/
4
1/
4
Yr
Eggs
yr
YyRr
3/
yyrr
1/
4
1/
yR
4
4
Phenotypic ratio 3:1
1/
yr
4
9/
16
3/
16
3/
16
1/
16
Phenotypic ratio 9:3:3:1
RESULTS
315
108
101
32
Phenotypic ratio approximately 9:3:3:1

Rr
Segregation of
alleles into eggs
Rr
Segregation of
alleles into sperm
Sperm
1/
R
2
2
Eggs
4
r
2
r
R
R
1/
1/
r
2
R
R
1/
1/
1/
4
r
r
R
r
1/
4
1/
4
Probability of YYRR  1/4 (probability of YY)  1/4 (RR)  1/16
Probability of YyRR  1/2 (Yy)
 1/4 (RR)  1/8
Probability of YYRR  1/4 (probability of YY)  1/4 (RR)  1/16
Probability of YyRR  1/2 (Yy)
Probability of yyrr = ?
A. 1/8
B. 1/16
C. 1/32
 1/4 (RR)  1/8
Probability of YYRR  1/4 (probability of YY)  1/4 (RR)  1/16
Probability of YyRR  1/2 (Yy)
Probability of YYrr = ?
A. ¼
B. 1/8
C. 1/16
 1/4 (RR)  1/8
Probability of YYRR  1/4 (probability of YY)  1/4 (RR)  1/16
Probability of YyRR  1/2 (Yy)
Probability of YxRr = ?
(x can be Y or y)
A. ½
B. 3/4
C. 3/8
 1/4 (RR)  1/8
D. 1/16
ppyyRr
ppYyrr
Ppyyrr
PPyyrr
ppyyrr
1/ (yy)  1/ (Rr)
(probability
of
pp)

4
2
2
1/  1/  1/
4
2
2
1/  1/  1/
2
2
2
1/  1/  1/
4
2
2
1/  1/  1/
4
2
2
1/
Chance of at least two recessive traits
 1/16
 1/16
 2/16
 1/16
 1/16
 6/16 or 3/8
Related documents