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Transcript
Chapter 12
Structure
Determination: Mass
Spectrometry and
Infrared Spectroscopy
Suggested Problems – 111,14-16,18,23,26,3034,41-2
CHE2202, Chapter 12
Learn, 1
Determining the Structure of an
Organic Compound
• The analysis of the outcome of a reaction requires that
we know the full structure of the products as well as the
reactants
• In the 19th and early 20th centuries, structures were
determined by synthesis and chemical degradation that
related compounds to each other
• Physical methods now permit structures to be determined
directly. We will examine:
–
–
–
–
mass spectrometry (MS)
infrared (IR) spectroscopy
nuclear magnetic resonance spectroscopy (NMR)
ultraviolet-visible spectroscopy (UV-VIS)
CHE2202, Chapter 12
Learn, 2
Mass Spectrometry of Small Molecules:
Magnetic-Sector Instruments
• Mass spectrometry (MS) determines
molecular weight by measuring the mass of a
molecule
• Components of a mass spectrometer:
– Ionization source - Electrical charge assigned to
sample molecules
– Mass analyzer - Ions are separated based on
their mass-to-charge ratio
– Detector - Separated ions are observed and
counted
CHE2202, Chapter 12
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Electron-Ionization, MagneticSector Mass Spectrometer
• Small amount of sample undergoes
vaporization at the ionization source to form
cation radicals
• Amount of energy transferred causes
fragmentation of most cation radicals into
positive and neutral pieces
CHE2202, Chapter 12
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Electron-Ionization, MagneticSector Mass Spectrometer
• Fragments pass through a strong magnetic
field in a curved pipe that segregates them
according to their mass-to-charge ratio
• Positive fragments are sorted into a detector
and are recorded as peaks at the various m/z
ratios
– Mass of the ion is the m/z value
CHE2202, Chapter 12
Learn, 5
The electron-ionization, magneticsector mass spectrometer
CHE2202, Chapter 12
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Quadrupole Mass Analyzer
• Comprises four iron rods arranged parallel to
the direction of the ion beam
• Specific oscillating electrostatic field is
created in the space between the four rods
– Only the corresponding m/z value is able to pass
through and reach the detector
– Other values are deflected and crash into the
rods or the walls of the instrument
CHE2202, Chapter 12
Learn, 7
The Quadrupole Mass Analyzer
CHE2202, Chapter 12
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Representing the Mass Spectrum
• Plot mass of ions (m/z) (x-axis) versus the intensity
of the signal (roughly corresponding to the number
of ions) (y-axis)
• Tallest peak is base peak (Intensity of 100%)
• Peak that corresponds to the unfragmented radical
cation is parent peak or molecular ion (M+)
CHE2202, Chapter 12
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Interpreting Mass Spectra
• Provides the molecular weight from the mass of
the molecular ion
• Double-focusing mass spectrometers have a
high accuracy rate
• In compounds that do not exhibit molecular ions,
soft ionization methods are used
CHE2202, Chapter 12
Learn, 10
High Resolution Mass Spectrometry Can Distinguish
Between Compound with the Same Molecular Mass
Exact Masses of Isotopes
CHE2202, Chapter 12
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Natural Abundance of Isotopes
CHE2202, Chapter 12
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Other Mass Spectral Features
• Mass spectrum provides the molecular
fingerprint of a compound
– The way molecular ions break down, can produce
characteristic fragments that help in identification
• Interpretation of molecular fragmentation pattern
assists in the derivation of structural information
CHE2202, Chapter 12
Learn, 13
Mass Spectral Fragmentation of
Hexane
• Hexane (m/z = 86 for parent) has peaks at m/z
= 71, 57, 43, 29
CHE2202, Chapter 12
Learn, 14
Worked Example
• The male sex hormone testosterone contains
only C, H, and O and has a mass of
288.2089 amu, as determined by highresolution mass spectrometry
– Determine the possible molecular formula of
testosterone
CHE2202, Chapter 12
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Worked Example
• Solution:
– Assume that hydrogen contributes 0.2089 to the
mass of 288.2089
– Dividing 0.2089 by 0.00783 ( difference between
the atomic weight of one H atom and 1) gives
26.67
• Approximate number of H in testosterone
– Determine the maximum number of carbons by
dividing 288 by 12
– List reasonable molecular formulas containing
C,H, and O that contain 20-30 hydrogens and
whose mass is 288
CHE2202, Chapter 12
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Worked Example
– The possible formula for testosterone is
C19H28O2
CHE2202, Chapter 12
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Mass Spectrometry of Some
Common Functional Groups
• Alcohols
– Fragment through alpha cleavage and
dehydration
CHE2202, Chapter 12
Learn, 18
Mass Spectrometry of Some
Common Functional Groups
• Amines
– Nitrogen rule of mass spectrometry
• A compound with an odd number of nitrogen
atoms has an odd-numbered molecular weight
– Amines undergo -cleavage, generating alkyl
radicals and a resonance-stabilized, nitrogencontaining cation
CHE2202, Chapter 12
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Mass Spectrometry of Some
Common Functional Groups
• Halides
– Elements comprising
two common isotopes
possess a distinctive
appearance as a mass
spectra
CHE2202, Chapter 12
Learn, 20
Fragmentation of Carbonyl
Compounds
• A C–H that is three atoms away leads to an
internal transfer of a proton to the C=O called
the McLafferty rearrangement
• Carbonyl compounds can also undergo cleavage
CHE2202, Chapter 12
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Worked Example
• List the masses of the parent ion and of
several fragments that can be found in the
mass spectrum of the following molecule
2-methyl-2-pentanol
CHE2202, Chapter 12
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Worked Example
• Solution:
– The molecule is 2-methyl-2-pentanol
• It produces fragments resulting from dehydration and
alpha cleavage
• Peaks may appear at M+=102(molecular ion), 87, 84,
59
CHE2202, Chapter 12
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Mass Spectroscopy in Biological Chemistry:
Time-of-Flight (TOF) Instruments
• Most biochemical analyses by MS use soft
ionization methods that charge molecules with
minimal fragmentation
– Electrospray ionization (ESI)
• High voltage is passed through the solution sample
• Sample molecule gains one or more protons from the
volatile solvent, which evaporates quickly
– Matrix-assisted laser desorption ionization (MALDI)
• Sample is absorbed onto a suitable matrix compound
• Upon brief exposure to laser light, energy is
transferred from the matrix compound to the sample
molecule
CHE2202, Chapter 12
Learn, 24
MALDI–TOF Mass Spectrum of
Chicken Egg-White Lysozyme
CHE2202, Chapter 12
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Spectroscopy and the
Electromagnetic Spectrum
• Waves are classified by frequency or
wavelength ranges
CHE2202, Chapter 12
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Absorption Spectrum
• Organic compounds exposed to electromagnetic
radiation can absorb energy of only certain
wavelengths (unit of energy)
– Transmit energy of other wavelengths
• Changing wavelengths to determine which are
absorbed and which are transmitted produces
an absorption spectrum
• In infrared radiation, absorbed energy causes
bonds to stretch and bend more vigorously
• In ultraviolet radiation, absorbed energy causes
electrons to jump to a higher-energy orbital CHE2202, Chapter 12
Learn, 30
Infrared Energy Modes
• Molecules possess a certain amount of
energy that causes them to vibrate
• Molecule absorbs energy upon
electromagnetic radiation only if the radiation
frequency and the vibration frequency match
CHE2202, Chapter 12
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Interpreting Infrared Spectra
• IR spectrum interpretation is difficult as the
arrangement of organic molecules is complex
– Disadvantage - Generally used only in pure
samples of fairly small molecules
– Advantage - Provides a unique identification of
compounds
• Fingerprint region - 1500cm-1 to 400 cm-1 (approx)
• Complete interpretation of the IR spectrum is not
necessary to gain useful structural information
– IR absorption bands are similar among compounds
CHE2202, Chapter 12
Learn, 34
Characteristic IR Absorptions of
Some Functional Groups
CHE2202, Chapter 12
Learn, 35
IR Spectra of Hexane, 1-Hexene,
and 1-Hexyne
CHE2202, Chapter 12
Learn, 36
Regions of the Infrared Spectrum
• Region from 4000 to 2500 cm-1 can be divided
into areas characterized by:
–
–
–
–
Single-bond stretching motions
Triple-bond stretching motions
Absorption by double bonds
Fingerprint portion of the IR spectrum
CHE2202, Chapter 12
Learn, 37
Worked Example
• Using IR spectroscopy, distinguish
between the following isomers:
– CH3CH2OH and CH3OCH3
• Solution:
– CH3CH2OH is a strong hydroxyl bond at
3400–3640 cm-1
– CH3OCH3 does not possess a band in the
region 3400–3640 cm-1
CHE2202, Chapter 12
Learn, 39
Infrared Spectra of Some Common
Functional Groups
• Alkanes
– No functional groups
– C–H and C–C bonds are responsible for
absorption
– C–H bond absorption ranges from 2850 to 2960
cm-1
– C–C bonds show bands between 800 to 1300
cm-1
CHE2202, Chapter 12
Learn, 40
Infrared Spectra of Some Common
Functional Groups
• Alkenes
– Vinylic =C–H bonds are responsible for
absorption from 3020 to 3011cm-1
– Alkene C=C bonds are responsible for absorption
close to 1650cm-1
– Alkenes possess =C–H out-of-plane bending
absorptions in the 700 to 1000 cm-1 range
CHE2202, Chapter 12
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Infrared Spectra of Some Common
Functional Groups
• Alkynes
– C≡C stretching absorption exhibited at 2100 to
2260 cm-1
• Similar bonds in 3-hexyne show no absorption
– Terminal alkynes such as 1-hexyne possess
≡C–H stretching absorption at 3300 cm-1
CHE2202, Chapter 12
Learn, 42
Some Vibrations are Infrared Inactive
A bond absorbs IR radiation only if its dipole moment changes when it vibrates.
CHE2202, Chapter 12
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Aromatic Compounds
• Weak C–H stretch at 3030 cm1
• Weak absorptions at 1660 to 2000 cm1
range
• Medium-intensity absorptions at 1450 to
1600 cm1
CHE2202, Chapter 12
Learn, 44
Alcohols and Amines
• Alcohols
– O–H 3400 to 3650 cm1
• Usually broad and intense
• Amines
– N–H 3300 to 3500 cm1
• Sharper and less intense than an O–H
CHE2202, Chapter 12
Learn, 45
The IR Spectrum of an Alcohol
CHE2202, Chapter 12
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The IR Spectrum of an Amine
CHE2202, Chapter 12
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Carbonyl Compounds
• Strong, sharp C=O peak in the range of 1670
to 1780 cm1
• Exact absorption is characteristic of type of
carbonyl compound
• Principles of resonance, inductive electronic
effects, and hydrogen bonding provides a
better understanding of IR radiation
frequencies
CHE2202, Chapter 12
Learn, 48
Carbonyl Compounds
• Aldehydes
– 1730 cm1 in saturated aldehydes
– 1705 cm1 in aldehydes next to double bond
or aromatic ring
– Low absorbance frequency is due to the
resonance delocalization of electron density
from the C=C into the carbonyl
CHE2202, Chapter 12
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The IR Spectrum of an Aldehyde
The carbon—hydrogen stretch of an aldehyde hydrogen occurs
at 2820 cm–1 and at 2720 cm–1.
CHE2202, Chapter 12
Learn, 50
Ketones
• Saturated open-chain ketones and sixmembered cyclic ketones absorb at 1715cm-1
• Five-membered ketones absorb at 1750cm-1
– Stiffening of C=O bond due to ring strain
• Four members absorb at 1780cm-1
CHE2202, Chapter 12
Learn, 51
This C═O Bond Is Essentially a
Pure Double Bond
CHE2202, Chapter 12
Learn, 52
This C═O Bond Has Significant
Single Bond Character
The less double bond character, the lower the frequency.
CHE2202, Chapter 12
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Carbonyl Compounds
• Esters
– Saturated esters absorb at 1735 cm-1
– Esters possess two strong absorbances
within the range of 1300 to 1000 cm-1
– Esters adjacent to an aromatic ring or a
double bond absorb at 1715 cm-1
CHE2202, Chapter 12
Learn, 54
The IR Spectrum of an Ester
CHE2202, Chapter 12
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The IR Spectrum of a Carboxylic Acid
CHE2202, Chapter 12
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Hydrogen Bonded OH Groups
Stretch at a Lower Frequency
It is easier to stretch a hydrogen bonded OH group.
CHE2202, Chapter 12
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The IR Spectrum of an Amide
CHE2202, Chapter 12
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Worked Example
• Identify the possible location of IR
absorptions in the compound below
CHE2202, Chapter 12
Learn, 59
Worked Example
• Solution:
– The compound possesses nitrile and ketone groups
as well as a carbon–carbon double bond
– Nitrile absorption occurs at 2210–2260 cm-1
– Ketone exhibits an absorption bond at 1690 cm-1
– Double bond absorption occurs at 1640–1680 cm-1
CHE2202, Chapter 12
Learn, 60