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Analysis of Diode Circuits using the Ideal Diode Model
Determine the state (on or off) of D1 and D2.
Recall --
Forward Bias: VA > VK, short circuit
Reverse Bias: VK > VA, open circuit
Start by assuming diode states
Assume D1 is OFF and D2 is ON.
The current through D2 flows from anode to cathode 
The anode voltage D1 is 10V, and the cathode voltage is 3V.
This means D1 is actually forward biased and should be ON. 
Let’s try again
Assume D1 is ON and D2 is OFF.
The current through D1 flows from anode to cathode 
The anode voltage D2 is 3V, and the cathode voltage is 6V.
This means D2 is indeed reverse biased and is OFF. 
So D1 is forward biased (ON) and D2 is reverse biased (OFF).
Let’s try some more!
Let’s try some more!
Let’s try some more!
Full-Wave (Bridge) Rectifier
Full-Wave (Bridge) Rectifier
Positive Half-Cycle:
Full-Wave (Bridge) Rectifier
Negative Half-Cycle:
Full-Wave (Bridge) Rectifier
I load
2f C
Full-Wave (Bridge) Rectifier
What happens when a diode fails?
(Diodes always fail as OPEN circuits)