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◙ EP-Program 5 - Strisuksa School - Roi-et Math : Real Number and Inequalities ► Dr.Wattana Toutip - Department of Mathematics – Khon Kaen University © 2010 :Wattana Toutip ◙ [email protected] ◙ http://home.kku.ac.th/wattou 5 Inequalities An inequality asserts that one expression is less than another . x 1 3,3x 2 y 4, x 2 3x 7 0 are examples of inequalities. To solve an inequality is to find the range of values for which it is true. When multiplying or dividing an inequality by a negative number the inequality changes round . If x y then 2 x 2 y . 5.1 Properties of Real Number 5.1.1 Interval and subset of real numbers a, b x a x b a, x x a a, b x a x b [a, ) x x a [a, b) x a x b ,b x x b (a, b] x a x b (, b] x x b (, ) x x R The set of real numbers ◙ EP .Program – Strisuksa School Roi-et. Mathematics 5.1.2 Properties of inequalities Let a, b, c be real numbers 1) Transitive Law: If a b and b c then a c If a b and b c then a c 2) Addition Law: If a b then a c b c If a b then a c b c 3) Multiplicative with Positive Number: If a b and c 0 then ac bc If a b and c 0 then ac bc 4) Multiplicative with Negative Number: If a b and c 0 then ac bc If a b and c 0 then ac bc 5.1.3 Properties of absolute value of real numbers Let k be a positive real number 1) x k if and only if x k or x k 2) x k if and only if k x k 3) x k if and only if x k or x k 5. Real Number and Inequalities page 2 ◙ EP .Program – Strisuksa School Roi-et. Mathematics 5. Real Number and Inequalities page 3 5.2 Inequalities in one variable Linear inequalities are solved by the same algebraic operations as linear equations .Quadratic and rational inequalities are solved by factorizing. 5.2.1 Example Solve the following inequalities : (a) 2 x 3 7 (b) x 2 3x 10 0 1 x (c) 1 3 x Solution (a) Subtract 3 from both sides, then divide by 2 . 2x 3 3 7 3 2x 4 x2 The solution is: x 2 (b) ■ Factorize the quadratic. ( x 5)( x 2) 0 The quadratic is zero at 5 and 2 .These values divide the number line into three regions. Compile a table to show when the factors are positive and when negative. x 5 5 x 2 2 x x5 x2 ( x 5)( x 2) We can see in the real line as shown in the following figure: 5 The solution is: 5 x 2 2 ■ ◙ EP .Program – Strisuksa School Roi-et. (c) Mathematics 5. Real Number and Inequalities page 4 Take the 1 over to the left hand side . 1 x 1 0 3 x 1 x (3 x) 0 3 x 2( x 1) 0 3 x The method of (a) , when expressions are multiplied, applies when they are divide .Proceed as in (a). The solution is : 1 x 3 ■ 5.2.2 Exercises Solve the following inequalities : 1. 3x 1 4 2. 1 2 x 2 3. 1 x 6 2 x 4. 3(1 2 x) 2( x 3) 5. x 2 8 x 12 0 6. x 2 3x 18 0 7. 2 x 2 3x 2 0 8. x 2 x 3 0 ◙ EP .Program – Strisuksa School Roi-et. 9. x 2 x 0 10. x 2 2 x 35 11. ( x 1)( x 2)( x 3) 0 12. (2 x 1)( x 3)(3 2 x) 0 13. ( x 1)2 ( x 1) 0 14. x 2 (2 x 1) 0 15. ( x 1)( x 2) 0 x3 16. ( x 3)(1 2 x) 0 ( x 2)2 17. x 3 10 x 18. x 1 1 2 x 19. x 12 3 x 20. x 2 x 1 x x Mathematics 5. Real Number and Inequalities page 5 ◙ EP .Program – Strisuksa School Roi-et. Mathematics 5. Real Number and Inequalities 5.3 Absolute Valued with Inequalities The absolute valued function x is defined by x if x x if x0 x0 If x k , for k positive, Then k x k . If x k ,for k positive , then x k or x k . The graph of y x is shown in Fig 5.1 Fig 5.1 Inequalities with absolute value terms can be solved by graphs. 5.3.1 Example Solve the following inequalities (a) 2 x 1 2 (b) x 3 2 x , by drawing graphs Solution (a) Remove the absolute valued signs: 2 x 1 2 or 2 x 1 2 1 1 x or x 1 2 2 page 6 ◙ EP .Program – Strisuksa School Roi-et. The solution is: x 1 1 or x 1 2 2 Mathematics 5. Real Number and Inequalities page 7 ■ (b) The graph of y x 3 and y 2 x are shown. They cross at x 1 .The modulus graph is below the linear graph after this value. x 1 The solution is: x 1 5.3.2 Exercises Solve the following inequalities 1) x 5 2) x 4 3) 2 x 1 4) x 2 4 5) x 3 2 ■ ◙ EP .Program – Strisuksa School Roi-et. Mathematics 5. Real Number and Inequalities page 8 Solve questions 6 to 9 by drawing graphs 6) x x 7) x 1 x 2 8) x 1 2 x 9) 2 x x 2 Common errors 1. Solving inequalities (a) Do not multiply or divide an inequality by term unless you are sure that the is positive . (b) If the solution to a quadratic inequality consist of two regions, then leave it like that .Write x 1or x 3 , do not write 1 x 3 . 2. Inequalities in two dimensions If you are dealing with say the inequality 3x 2 y 6 , then the region is enclosed by the line 3x 2 y 6 .It is not enclosed by the lines x 2 and y 3 . Solution (to exercise) 5.2.2 1. x 1 1 2. x 2 5 3. x 3 9 4. x 4 ◙ EP .Program – Strisuksa School Roi-et. Mathematics 5. Real Number and Inequalities 5. 6 x 2 6. x 3 or x 6 7. all x 8. 2.3 x 1.3 9. 2 x 1 x 5 or x 7 10. x 5 or x 7 11. x 3 or 2 x 1 1 1 12. x or 1 x 3 2 2 13. x 1 1 14. x , x 0 2 15. x 3 or 2 x 1 1 16. 3 x 2, 2 x 2 17. x 5 or 0 x 2 1 18. x 2 2 19. x 6 or 0 x 6 20. x 0 5.3.2 1. 5 x 5 2. x 4 or x 4 1 1 3. x 2 2 4. 2 x 6 5. x 5 or x 1 6. x 0 7. x 0 1 8. x 1 3 9. x 2 or x 2 =========================================================== References: Solomon, R.C. (1997), A Level: Mathematics (4th Edition) , Great Britain, Hillman Printers(Frome) Ltd. More: http://home.kku.ac.th/wattou/service/m456/03.pdf page 9