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U.P.B. Sci. Bull., Series A, Vol. 71,Iss. 2, 2009
ISSN 1223-7027
EULERIAN NUMBERS AND GENERALIZED ARITHMETICGEOMETRIC SERIES
Mircea I CÎRNU1
Pe baza teoremei Cauchy-Mertens de înmulţire a seriilor, se obţin într-un
mod simplu unele rezultate binecunoscute, cum ar fi reprezentarea numerelor
Euleriene, o identitate combinatorială şi formula sumei seriilor aritmeticogeometrice generalizate. Se dau două aplicaţii.
Based on Cauchy-Mertens theorem of series multiplication, we obtain in a
simple manner some
well-known results, namely
the Eulerian numbers
representation, a combinatorial identity and the formula for the sum of generalized
arithmetic-geometric series. Two applications are given.
Keywords: Eulerian numbers, generalized arithmetic-geometric series.
2000 Mathematics Subject Classification: 05A19, 11B68, 65B10.
1. Eulerian numbers and the sum of generalized arithmetic-geometric series
We present the formula that express the sums of generalized
arithmetic-geometric series by the Eulerian numbers ([1]). It can to be
considered as the definition of these numbers. Are included recurrence
and symmetry relations for Eulerian numbers that give the possibility to
compute these numbers.
In entire paper z is a complex variable.
Theorem 1. Let n 0 be a natural number. The sum of a
generalized arithmetic-geometric series (the generating function of the
sequence k n , k 0,1,2, ) is given by the formula
Gn z k n z k
k 1
n 1
E n, k z
1 z
z
n 1
k
,
z 1
(1)
k 0
where En, k are the Eulerian numbers, given by the relations
En,0 En, n 1 1 ,
1
(2)
Prof., Department of Mathematics III, University POLITEHNICA of Bucharest, Romania
26
Mircea Cîrnu
En, k k 1 En 1, k n k En 1, k 1 , k 1,2, , n 2 . (3)
z
is uniform
1 z
k 1
convergent. By differentiation and multiplication with z , we obtain
z
z
z
k
2 k
,
,
k
z
k
z
1
z
k3zk
1 4 z z 2 and
2
3
4
1 z k 1
1 z
1 z
k 1
k 1
so on. Hence the relations (1), (2), (3) are satisfied for n 0,1,2,3 .
We shall prove the relation (1) by mathematical induction after n .
Assuming the relation (1) is true for fixed n 0 , by differentiation and
multiplication with z , we obtain
n 1
z 1 nz n1
z2
n 1 k
k
k
z
E
n
,
k
z
k E n, k z k 1
n2
n 1
1 z k 0
1 z k 1
k 1
n 1
z
E n, k k 1 n k z z k .
n2
1 z k 0
We obtain the relation (1) for n 1 if we denote
Proof. For z r 1, the geometric series
z
k
n 1
E n, k k 1 n k z z
k 0
n
k
E n 1, k z k .
(4)
k 0
By identification, from (4) we obtain for the coefficients of z 0 , the
relation En,0 En 1,0 . Because E1,0 1, it follows that En,0 1 . For the
coefficients of z n , we obtain the relation En, n 1 En 1, n . Because
E1,0 1, it follows that En, n 1 1 . For the coefficients of z k , we obtain the
relation
k 1 En, k n k 1 En, k 1 En 1, k , k 1,2,, n 1 .
Replacing n 1 instead of n , the recurrence relation (3) follows.
Consequence. The Eulerian numbers satisfy the following symmetry
relation
(5)
En, k En, n k 1 , k 0,1,, n 1 , n 1,2,
Proof. We prove the relation (5) by induction after n . For n 1 the
relation (5) is obvious. By (2) it results the relation (5) is true for k 0 and
k n 1.
We suppose (5) satisfied for a fixed natural n 1. Replacing k with n k
in (5), it is obtain the relation
Eulerian numbers and generalized arithmetic-geometric series
En, n k En, k 1 , k 1, , n 2 .
27
(6)
Using the relation (3) and induction hypothesis under the forms (5) and
(6), we have
En 1, n k n k 1 En, n k k 1 En, n k 1
n k 1 En, k 1 k 1 En, k En 1, k ,
hence the relation (5) is true for n 1 . By induction axiom, the relation (5) is
accomplished for every natural number n 1.
Remark. From relations (2) and (3), the values of Eulerian numbers
En, k can be computed by recurrence. The first values of these numbers are
given below:
0
1
2
3
4
5
6
k
--------------------------------------------------------------------n
1
1
2
1
1
3
1
4
1
4
1
11
11
1
5
1
26
66
26
1
6
1
57
302
302
57
1
7
1
120 1191 2416 1191 120
1
2. Closed-form expression for the Eulerian numbers
Theorem 2. Let n 0 be a natural number. The Eulerian numbers are
given by the formula
k
j n 1
k j 1n , k 0,1, , n 1 .
E n, k 1
j 0
j
For k n , we have the following identity
(7)
28
Mircea Cîrnu
n
n 1
n j 1n 0 ,
j
1
j 0
j
and, for k n 1, the identity
n 1
n 1
1 j k j 1n 0 .
j 0
j
(8)
(9)
Proof. One consider the relation (1) given in theorem 1, in the form
n 1
j 1
k 0
1 z n1 j n z j 1 En, k z k ,
z 1.
Using Newton's binomial theorem and changing the index j k 1 in the
left hand series, the above relation becomes
n 1
n1
k n 1 k
n n
k
1
z
k
1
z
E n, k z .
k
k 0
k 0
k 0
(10)
Denoting
k n 1
, k 0,1, , n 1
1
n
ak
, bk k 1 , 0,1, ,
k
0
,
k n 1
and using the Cauchy-Mertens theorem about the multiplications of series (see
for example [2]), the identity (10) can be rewritten as:
n 1
k
k
k
a
z
b
z
c
z
E n, k z k ,
k k k
k 0
k 0
k 0
k 0
(11)
where the coefficients ck are given by the formula
k
ck a j bk j , k 0,1,
j 0
Identifying the coefficients in relation (11), if k n 1 , we have
(12)
29
Eulerian numbers and generalized arithmetic-geometric series
k
j n 1
k j 1n En, k , n 0,1, ,
ck 1
j
j 0
n
j n 1
n j 1n 0 and (8)
hence (7) is obtained. If k n , then cn 1
j
j 0
n 1
j n 1
k j 1n 0 and follows
is also verified. If k n 1, then ck 1
j
j 0
(9).
Remarks. 1) One observe that the identity (8) follows from (9). Namely,
n 1
j n 1
n j 2n 0 hence, if
from (9) for k n 1, we have 1
j 0
j
n
j n
n 1
substitute n with n 1 , we obtain 1 n j 1 0 , therefore
j 0
j
n
n 1
n
n j 1n n 1 1 j n j 1n 1 0 .
j 0
j
j
j
1
n
j 0
2) Representing the combinatorial coefficients by factorials, the identities
(8) and (9) may be written as:
1 j n j 1n1
n j !
j!
j 0
n
1 j k j 1n 0 ,
j ! n j 1!
j 0
n 1
0,
k n 1.
3. Formula for the sum of generalized arithmetic-geometric series
Replacing in formula (1) the closed-form expression of Eulerian numbers
given by the formula (7), it obtains the following result (see [3] or [1]) :
Theorem 3. Let be n 0 a natural number. The sum of the generalized
arithmetic-geometric series (the generating function of the sequence k n ,
k 0,1,) has the following formula
Gn z k n z k
k 1
k
j n 1
n k
1
k
j
1
z , z 1. (13)
j
1 z n1 k 0 j 0
z
n 1
30
Mircea Cîrnu
4. Applications
4.1. Arithmetic-geometric series
Let a, r , q be complex numbers, q 1 . Using the formula (13) for n 1,
the sum of arithmetic-geometric series is
a k 1r q k 1 a r q k 1 r k q k a r r q 2
q k 1
1 q q 1 q
k 1
k 1
a 1 q rq
1 q 2
.
4.2. Z-transforms
For n 1,2, , from (1) and (5), changing the index j n 1 k , the Ztransform of the sequence of powers of natural numbers { k n : k 0,1,2, }, is
given by the formula
kn
1
n
Z k k Gn
z
k 0 z
1
n 1
n 1
E n, j
z
z
E n, j z n 1 j
n 1
j
n 1
z 1 j 0
1 j 0 z
1
z
n 1
n 1
z
z
k
(14)
E
n
,
n
1
k
z
E n, k z k , z 1.
n 1
n 1
z 1 k 0
z 1 k 0
z
z 1 z
z 1 4z z 2
2
3
In particular, Z k
, Z k
, Z k
.
z 12
z 13
z 14
REFERENCES
[1]. L. Comtet, Advanced Combinatorics, Reidel, 1974.
[2]. W. Rudin, Principles of Mathematical Analysis, 3rd Ed., Mc Graw-Hill, New York, 1976.
[3]. R. Stalley, A Generalization of the Geometric Series, American Mathematical Monthly, 56
(1949) 5, 325-327.