Survey
* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project
* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project
AP Statistics: Section 6.3B Normal Approx. to a Binomial Dist. In section 6.2, we learned how to find the find the mean, variance and standard deviation of a probability distribution for a discrete random variable X. Let’s use this knowledge to find formulas for the mean and variance of a random variable with a binomial distribution. Let’s consider a binomial random variable B with a probability of success p. We could describe B with the following probability distribution where 1 represents a success and 0 a failure. Value of Bi 1 0 Probability pi p 1-p 0(1 p ) 1( p ) p (0 p) 2 (1 p) (1 p) 2 p p 2 (1 p) (1 2 p p 2 ) p p 2 p3 p 2 p 2 p3 p p 2 p(1 p) B represents a single trial of some binomial chance process. Let X = B1+B2+…..+Bn represent the number of successes in n independent trials of this chance process. In other words, X is a binomial random variable with parameters n and p. By the rules of section 7.2 p p p np p (1 p ) p (1 p ) p (1 p ) np (1 p ) If X has the distribution B(n, p), then x x n p np (1 p ) Be careful : These short formulas are good only for binomial distributions. They cannot be used for other discrete random variables. Example 1: A Federal report finds that lie detector tests given to truthful persons have a probability of 0.2 of suggesting that the person is deceptive. A company asks 12 job applicants about stealing from previous employers and used a lie detector test to assess their truthfulness. Suppose that all 12 answered truthfully and let X = the number of people who the lie detector test says are being deceptive. a) Find and interpret x . x (12)(.2) 2.4 If the lie detector test was given to many different groups of 12 job applicants, the average number of times the test would indicate an applicant was being deceptive is 2.4. b) Find x . x 12 .2 .8 1.386 The formula for binomial probabilities gets quite cumbersome for large values of n. While we could use statistical software or a statistical calculator, here is another alternative. The Normal Approximation to Binomial Distributions: Suppose that a count X has a binomial distribution B(n, p). When n is large (np _____ 10 and n(1 - p) _____), 10 then the distribution of X is approximately Normal, N(____,________) np np(1 - p) Example 2: Are attitudes towards shopping changing? Sample surveys show that fewer people enjoy shopping than in the past. A survey asked a nationwide random sample of 2500 adults if they agreed or disagreed that “I like buying new clothes, but shopping is often frustrating and timeconsuming.” The population that the poll wants to draw conclusions about is all U.S. residents aged 18 and over. Suppose that in fact 60% of all adult U.S. residents would say “agree” if asked the same question. What is the probability that 1520 or more of the sample would agree? 1 binomialcdf (2500,.6,1519) 1 .7869 .2131 Check conditions for Normal Approx. (2500)(.6) 10 2500(.4) 10 1500 10 1000 10 x (2500(.6) 1500 x 2500(.6)(.4) 24.4949 normalcdf (1520,100000,1500,24.4949) .2071 The accuracy of the Normal approximation improves as the sample size n increases. It is most accurate for any fixed n when p is close to ____ .5 and least accurate when p is near ____ 0 or ____ 1 and the distribution is ________. skewed