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Chapter 5 Forces in Multibody Dynamics 5.1 Introduction The science of dynamics deals with the effects of forces on material bodies. Therefore, a clear concept of force is necessary for a study of dynamics. The modeling of forces in the study of multibody dynamics is undoubtedly important. The objective of this chapter is to review the concepts of forces and their classification, then an extension of these concepts into a general form applicable to multibody systems is developed. 5.2 Forces A force can be presented by a vector, then it can be defined as a quantity having magnitude, direction, and sense. Equation (5.2.1) represents a force vector. F Fx i Fy j Fz k (5.2.1) Forces are classified as free, sliding, and bound forces. A force is not associated with a specific location called a free force, for example a force acting on a rigid body when translational motion of the body is concerned. A bound force is one with a specified point of application, for example a force acting on deformable or rigid body. The application point of a force vector determines the effect it has on a material system. For example, the forces, FA and FB , in Figure 5.2.1 have a different effect upon the multibody system. A sliding force is one which can be moved along a given line collinear with the force itself, as in Figure 5.2.2. 1 Figure 5.2.1 Forces applied at different points of a multibody system 2 Figure 5.2.2 A Sliding Force 3 5.3 Moment of a Force About a Point and About a Line A moment can be defined as the rotational effect of a force about a point or about a line. The moment, M o of a force F about the O may be defined as a vector with magnitude – magnitude F of the force times the perpendicular distance from O to F , direction – perpendicular to the plane at ), and sense – sense of advance according to the right-hand screw rule. Let a be a position vector from O to any point A on line L. Then the moment of F about O, M o , is defined as Mo a F (5.3.1) Example 5.3.1. Moment of a force about a point Given: F 4 i 3 j 2k N, which passes through the origin. Find the moment of this force about a point O (2,1,7)m. Solution: We have M o a F (2 i j 7k) (4 i 3 j 2k) (6k 4 j) (4k 2 i ) (28 j 21i ) 19 i 24 j 2k NM 4 Figure 5.3.1 Force acting along line L, and point O 5 The moment of a force about a line is defined similarly. Let us consider a force F with line of action L. Let Z be a line about which the moment of F is to be taken. Let r be the position vector from a point on line Z, the line of application of the force. Let u be the unit vector along Z. Figure 5.3.2 shows such a situation. Then the moment of F about Z, M Z , is defined as M Z [( r F) u ] u (5.3.2) Figure 5.3.2 Force F , line of action L, and line Z. 6 5.4 Moment of a System of Forces consider a rigid body B as shown in Figure 5.4.1, where it is subjected to an arbitrary forces system consisting of N forces. The resultant R of all the forces Fi ( i 1,..., N ) applied to the rigid body B is then N R Fi (5.4.1) i 1 Then resultant moment of the forces about point O can be determined by vector addition resulting from successive applications of Equation 5.3.1. This resultant can be written as N M O a i Fi (5.4.2) i 1 where a ( i 1,..., N ) locates a point on the line of action of Fi , as shown in Figure 5.4.1. 7 Figure 5.4.1 A set of forces acting on a rigid body 8 5.5 Generalized Applied (Active) Forces Applied (active) forces are composed of externally applied forces, gravitational forces, spring and damper forces, and contact forces. 5.5.1 Externally Applied Forces Consider a multibody system shown in Figure 5.5.1. Suppose the system has n degrees of freedom described by generalized coordinates, x r ( r = 1, …, n). The generalized coordinates describe the relative orientation and translation between bodies. Let one body of the system be subject to an externally applied force at point P. Then the generalized active forces are defined as v p Fr F x r (5.5.1) where v p is the velocity of point P in the inertial reference frame R and v p x r is the partial velocity of P with respect to x r in R. The velocity v p can be written in the form v p v prm x r n om ( sum on r and m) (5.5.2) where the n om are unit vectors fixed in the inertial frame R. Then the partial velocity of point P can be written in the form v p x r v prm n om (5.5.3) Unlike F , the generalized force Fr is a scalar. From Eq. (5.5.1), we know that the number of generalized forces and the system have same degrees of freedom. If the force F is perpendicular to the partial velocity, v p x r , then the generalized force Fr is zero. Also, Fr could be zero if either v p x r is zero, F is zero. 9 Figure 5.5.1 Force acting at point P on one body of multibody system 10 For a multibody system is subjected to a set of forces Fi (i 1,..., n ) applied at point Pi of the system as shown in Figure 5.5.2. Then the generalized forces for this set of forces with respect to the generalized coordinate x r , are obtained by adding the generalized forces from the individual forces. That is, N Fr Fi v Pi x r (5.5.4) i 1 Consider a typical body of a multibody system is subjected to an externally applied force field and the force field can be replaced by a system of forces consisting of single force Fk passing through G k together with a couple with torque Tk applied to B k (see Figure 5.5.3). Then the generalized active forces are defined as v k Fr F T k x r x r (5.5.5) where v k and k are the mass center velocity and angular velocity of body k, B k , in the inertial reference frame R. The generalized active forces can also given by the expression Fr v kmr Fkm krp Tkm (5.5.6) where Fkm and Tkm are the n om components of Fk and Tk . There is a sum over the repeated indices. 11 Figure 5.5.2 A system of forces acting in a multibody system. 12 Figure 5.5.3 Typical body B k of a multibody system and equivalent applied force system. 13 5.5.2 Gravitational Forces For bodies near the surface of the earth, the gravitational (or weight) forces are nearly constant. The gravitational forces acted on two points not too apart are almost parallel. We may replace the forces on bodies by a single force passing through the center of gravity of the body. In the vicinity of the earth’s system, for a body having dimensions small composed with the radius of the earth, the center of gravity can be identified with the mass center of the body. Gravitational force will give a freely body a downward acceleration. We can denote this acceleration by a vector g and which is a constant if air resistance is neglected. The gravity forces exerted by the earth on a multibody system are given by FkG m k g (k 1,..., N) (n sum on k) (5.5.7) where N is the number of bodies, m k is the mass of body k, g is the acceleration vector of the gravity. The contribution of the gravitational forces to the generalized active forces are G v k Fr Fk x r (5.5.8) where v k is the velocity of the mass center in inertial reference frame R of body k. 5.5.3 Spring and Dampers Forces In addition to the externally applied forces and torques on the system, the active forces exerted multibody systems by translational and torsional spring and damper between each body of the system are of great interest. Consider two typical adjoining bodies B j and B k shown in Figure 5.5.4. Let b measure the displacement between the two bodies along S. S is the line connecting the two typical body. Let the n be the unit vector parallel to line S. From the law of action and reaction, the spring and damper could be represented by forces equal in magnitude and opposite in direction acting B j and B k . Let the force acting on B j be Fj and the force acting on B k 14 be Fk . The Fj and Fk can be expressed as Fj Fk f (b, b ) n (5.5.9) where f (b, b ) is a function of the properties of the spring and damper. For a linear spring, f (b, b ) has the form f (b, b ) k 0 k1b (5.5.10) where k 0 and k 1 are constants. For a linear damper f (b, b ) has the form f (b, b ) c 0 c1b (5.5.11) where c 0 and c1 are constants. The contributions of Fj and Fk to the generalized active force Fr could be obtain as v Pj v Pk Fr Fj Fk x r x r (5.5.12) Since Fj Fk v Pj v Pk Fr Fj [ ] x r x r (5.5.13) 15 Next, consider two typical bodies, B j and B k , are hinged with torsional spring and damper shown in Figure 5.5.5. Let the two typical bodies, B j and B k , be connected with a hinge where axis is parallel to a unit vector m as shown in Figure 5.5.5. If we denote the relative hinge rotation by , the torques exerted on bodies B j and B k by the torsional spring and damper might be expressed in the form Tj Tk g(, ) m (5.5.14) where g(, ) is a function of the properties of the torsional spring and damper. For a linear torsional spring, g(, ) has the form g(, ) r0 r1 (5.5.15) where r0 and r1 are constants. For a torsional damper g(, ) has the form g(, ) v 0 v1 b (5.5.16) where v 0 and v1 are constants. The contributions of Tj and Tk to the generalized active force Fr could be obtain as Pj Pk Fr Tj Tk x r x r (5.5.17) Since Tj Tk 16 Figure 5.5.4 Two typical adjoining bodies B j and B k with translational springs and dampers Figure 5.5.5 Two contact bodies B j and B k 17 Pj Pk Fr Tj [ ] x r x r (5.5.18) 5.5.4 Contact Forces Contact forces are very difficult to model. It contribute nothing to the generalized forces, Fr . For example, in a hinge joint, the contribution of the interaction forces is equal to zero. To illustrate this, consider two contact bodies B j and B k , let the point of contact be express by point c of B j and c of B k , as in Figure 5.5.5. In contact condition, the velocities of point c and c in an inertial frame should be equal. The contact forces exerted on B j and B k , should have same magnitude and opposite direction. That is, Fj Fk (5.5.19) Then we will have v c v c v c v c Fr Fj Fk Fj (Fj ) 0 x r x r x r x r (5.5.20) 5.6 Generalized Inertia (Passive) Forces As with applied forces, we can define generalized inertia forces in the same way. The generalized inertia (passive) force is defined as the projection of an inertia force along a partial velocity vector. Consider a particle P having mass m and is subjected to a force F as in Figure 5.6.1. From Newton’s Law, the particle acceleration is proportional to the force. That is F ma (5.6.1) According to the d’Alembert principle, Eq. (5.6.1) could be written as 18 F ma 0 (5.6.2) or F F* 0 (5.6.3) where F* ma is the inertia force. For a multibody system, let the inertia force system on a typical body B k be represented by the single force Fk* passing through the mass center together with a couple with torque Tk* (see Figure 5.6.2). Then Fk* and Tk* can be written as: Fk* m k a k (no sum on k) (5.6.4) and Tk* I k k k (I k k ) (no sum on k) (5.6.5) where m k is the mass of B k and I k is the inertia dyadic of B k relative to its mass center. The contributions of inertia forces to the generalized inertia force F * r could be obtain as * v * F r Fk Tk x r x r * (5.5.12) where v is the mass center velocity of the rigid body, its angular velocity, Fk* the inertia force, Tk* the inertia torque, and x r the time derivative of the generalized coordinates. 19 Figure 5.6.1 Inertia force on particle P. 20 Figure 5.6.2 Typical body B k of a multibody system and equivalent inertia force system. Reference [1] Kane,T.R. and Levinson,D.A., Dynamics: Theory and Application, McGraw-Hill Book Company, New York, 1985. [2] Huston, R.L., and C.E. Passerello, and M.W. Harlow, “Dynamics of Multirigid-Body Systems,” Journal of Applied Mechanics, Vol. 45, 1978, pp. 889-894. [3] Huston,R.L., Multibody Dynamics, Butterworth-Heinemann, 1990. [4] Josephs, H., R.L., Huston, Dynamics of Mechanical Systems, CRC Press, 2002. 21