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5/13/2017 582762100 1/6 Eigen Values of the Laplace Transform Well, I fibbed a little when I stated that the Eigen function of linear, time-invariant systems (circuits) is: L e jω t G ω e jω t Instead, the more general Eigen function is: L e st G s e st Where s is a complex (i.e., real and imaginary) frequency of the form: s σ j ω such that: e st e σ j ω t σt e e jωt Note then, if σ 0 , the Eigen function e jω t previously described Eigen function e ! st becomes the Q: Yikes! I understand e st even less than I understood e What does this function mean? jω t ! st A: Remember, the function e is a complex function—it is actually an expression of two real-value functions. Jim Stiles The Univ. of Kansas Dept. of EECS 5/13/2017 582762100 2/6 These two real-valued functions could be its real and imaginary components: e st σt e e e σt e σt j ω t cos ωt j sin ωt cos ωt j e 1.0 σt sin ωt σ 0.2 ω 3.2 0.5 2 4 6 8 10 0.5 1.0 Or, the two real-valued functions could alternatively be the complex values magnitude and phase: σ 0.2 ω 3.2 3 2 1 2 4 6 8 10 1 2 3 st j ω t If σ 0 , then e e , and we’re back to the timeharmonic Eigen function: Jim Stiles The Univ. of Kansas Dept. of EECS 5/13/2017 582762100 3/6 1.0 σ 0.0 ω 3.2 0.5 2 4 6 1 v2 t 2 0.5 8 10 j t V e d 2 1.0 Q: What about basis functions? Can we use these Eigen function to expand a signal? A: Sure! Instead of the Fourier Transform, the result of st expanding a signal with basis function e is the Laplace Transform. For example, again consider the following linear circuit: i1t i2t C v1t Jim Stiles L R g t t v t dt v2t L v1t 1 The Univ. of Kansas Dept. of EECS 5/13/2017 582762100 4/6 Using the Laplace transform, we can determine the output voltage v 2t by: 1. Expand the input signal v1t using the basis function e st : V1 s v t e 0 1 s t (or use a look-up table!) dt 2. Determine the Eigen value of the linear operator relating v1t to v 2t : g t t v t dt v2t L v1t 1 V2 s G s V1 s where: G s g t e s t dt 3. Determine v 2t from the inverse Laplace transform of V2 s (definitely use a look-up table!). Q: But how do we determine G s ? A: It’s just pretty darn simple! Jim Stiles The Univ. of Kansas Dept. of EECS 5/13/2017 582762100 5/6 Again, we determine the Eigen value of each linear operator of our three linear circuit elements—only this time we use the st Eigen function e ! iR t L vR t R L e R Y st st VR s R iC t L vC t C L e st st C d e dt d vC t sC e dt st iC t vC t C IC s sC VC s Jim Stiles R vR t C Y C Y e R IR s iR t vR t R Y The Univ. of Kansas Dept. of EECS 5/13/2017 582762100 6/6 iL t t 1 L v L t iL t v L t dt L L Y L e L Y st t 1 e s t dt 1 e s t L sL IL s L v L t VL s sL As a result we can determine the Eigen value G s of a linear circuit by applying our circuit theory: I 1 s 1 I 2 s sC V1 s R sL V2 s V1 s Jim Stiles V2 s G21 s sL R 1 sL R sC The Univ. of Kansas Dept. of EECS