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Section 12.6 OR and AND Problems Copyright 2013, 2010, 2007, Pearson, Education, Inc. What You Will Learn Compound Probability OR Problems AND Problems Independent Events 12.6-2 Copyright 2013, 2010, 2007, Pearson, Education, Inc. Compound Probability In this section, we learn how to solve compound probability problems that contain the words and or or without constructing a sample space. 12.6-3 Copyright 2013, 2010, 2007, Pearson, Education, Inc. OR Probability The or probability problem requires obtaining a “successful” outcome for at least one of the given events. 12.6-4 Copyright 2013, 2010, 2007, Pearson, Education, Inc. Probability of A or B To determine the probability of A or B, use the following formula. P(A or B) P(A) P(B) P(A and B) 12.6-5 Copyright 2013, 2010, 2007, Pearson, Education, Inc. Example 1: Using the Addition Formula Each of the numbers 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10 is written on a separate piece of paper. The 10 pieces of paper are then placed in a hat, and one piece is randomly selected. Determine the probability that the piece of paper selected contains an even number or a number greater than 6. 12.6-6 Copyright 2013, 2010, 2007, Pearson, Education, Inc. Example 1: Using the Addition Formula Solution Draw a Venn Diagram 5 P(even) 10 4 P( 6) 10 2 P(both) 10 12.6-7 Copyright 2013, 2010, 2007, Pearson, Education, Inc. Example 1: Using the Addition Formula Solution even or P P even P 6 P both > 6 5 4 2 7 10 10 10 10 The seven numbers that are even or greater than 6 are 2, 4, 6, 7, 8, 9, and 10. 12.6-8 Copyright 2013, 2010, 2007, Pearson, Education, Inc. Mutually Exclusive Two events A and B are mutually exclusive if it is impossible for both events to occur simultaneously. If two events are mutually exclusive, then the P(A and B) = 0. The addition formula simplifies to P(A or B) P(A) P(B). 12.6-9 Copyright 2013, 2010, 2007, Pearson, Education, Inc. Example 3: Probability of A or B One card is selected from a standard deck of playing cards. Determine whether the following pairs of events are mutually exclusive and determine P (A or B). a) A = an ace, B = a 9 Solution Impossible to select both so 4 4 2 P ace or 9 P ace P 9 52 52 13 12.610 Copyright 2013, 2010, 2007, Pearson, Education, Inc. Example 3: Probability of A or B b) A = an ace, B = a heart Solution Possible to select the ace of hearts, so NOT mutually exclusive ace or P P ace P heart P both heart 4 13 1 16 4 52 52 52 52 13 12.611 Copyright 2013, 2010, 2007, Pearson, Education, Inc. Example 3: Probability of A or B c) A = a red card, B = a black card Solution Impossible to select both so mutually exclusive P red or black P red P black 26 26 52 52 52 52 12.612 Copyright 2013, 2010, 2007, Pearson, Education, Inc. 1 Example 3: Probability of A or B d) A = a picture card, B = a red card Solution Possible to select a red picture card, so NOT mutually exclusive picture card picture red P P P P both card card or red card 12 26 6 32 8 52 52 52 52 13 12.613 Copyright 2013, 2010, 2007, Pearson, Education, Inc. And Problems The and probability problem requires obtaining a favorable outcome in each of the given events. 12.614 Copyright 2013, 2010, 2007, Pearson, Education, Inc. Probability of A and B To determine the probability of A and B, use the following formula. P(A and B) P(A) P(B) 12.615 Copyright 2013, 2010, 2007, Pearson, Education, Inc. Probability of A and B Since we multiply to find P (A and B), this formula is sometimes referred to as the multiplication formula. When using the multiplication formula, we always assume that event A has occurred when calculating P(B) because we are determining the probability of obtaining a favorable outcome in both of the given events. 12.616 Copyright 2013, 2010, 2007, Pearson, Education, Inc. Example 5: An Experiment without Replacement Two cards are to be selected without replacement from a deck of cards. Determine the probability that two spades will be selected. 12.617 Copyright 2013, 2010, 2007, Pearson, Education, Inc. Example 5: An Experiment without Replacement Solution The probability of selecting a spade on the first draw is 13/52. Assuming we selected a spade on the first draw, then the probability of selecting a spade on the second draw is 12/51. 12.618 Copyright 2013, 2010, 2007, Pearson, Education, Inc. Example 5: An Experiment without Replacement Solution P(2 spades) P(spade 1) P(spade 2) 13 12 52 51 1 4 4 17 12.619 1 17 Copyright 2013, 2010, 2007, Pearson, Education, Inc. Independent Events Event A and event B are independent events if the occurrence of either event in no way affects the probability of occurrence of the other event. Rolling dice and tossing coins are examples of independent events. 12.620 Copyright 2013, 2010, 2007, Pearson, Education, Inc. Example 6: Independent or Dependent Events? One hundred people attended a charity benefit to raise money for cancer research. Three people in attendance will be selected at random without replacement, and each will be awarded one door prize. Are the events of selecting the three people who will be awarded the door prize independent or dependent events? 12.621 Copyright 2013, 2010, 2007, Pearson, Education, Inc. Example 6: Independent or Dependent Events? Solution The events are dependent since each time one person is selected, it changes the probability of the next person being selected. P(person A is selected) = 1/100 If person B is actually selected, then on the second drawing, P(person A is selected) = 1/99 12.622 Copyright 2013, 2010, 2007, Pearson, Education, Inc. Independent or Dependent Events? In general, in any experiment in which two or more items are selected without replacement, the events will be dependent. 12.623 Copyright 2013, 2010, 2007, Pearson, Education, Inc.