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Chapter 04 DC BRIDGES 1 Summary 4.1 Fundamental concept of bridge circuit 4.2 Principle of DC bridge 4.2.1Wheatstone Bridge and application 4.2.2Kelvin Bridge 2 Fundamental Concept of Bridges Circuit Bridge - to measure unknown values of resistance - the bridge circuit works as a pair of two-component voltage dividers connected across the same source voltage, with a null-detector meter movement connected between them to indicate a condition of "balance" at zero volts - In a condition of balance; R1 R3 or R1R4 R3 R2 R2 R4 3 Principle of DC Bridges Type of DC Bridges 1. Wheatstone Bridges - used for the measurement of dc resistance 2. Kelvin Bridges - used for the measurement of low resistance 4 Wheatstone bridge Consists of two parallel resistance branches - A voltage source is connected across the resistance network - A null detector, usually a galvanometer is connected between the parallel branches to detect a balanced condition R1 & R2 = precision resistors (standard) ± known R3 = adjustable resistor (precisely calibrated) - measured R4 / RX = unknown ± to be calculated - 5 Wheatstone Bridge Initially, the bridge is in unbalanced condition; - galvanometer will give a reading (current flows through the galvanometer) - V2 ≠ • Vx R3 is carefully adjusted so that no current will flow through the galvanometer - IG =0 & V2 =Vx the bridge is now in balanced condition Rx R2 From the figure, V2 VS Vx VS R2 R1 Rx R3 In balanced condition, V2 = VS, hence, R1Rx = R2R3 So, R2 R3 Rx R1 6 Wheatstone bridge The bridge is balance when no current through the Galvanometer (Ig =0) VAB VAC or VBD VCD RX R1 E E RX R3 R2 R1 RX ( R1 R2 ) R1 ( RX R3 ) R1 RX RX R2 R1 RX R1 R3 RX R2 R1 R3 RX ( R1 R3 ) / R2 7 Example 1 Given value R1 = 1.5KΩ, R2 = 1KΩ, R3 = 3KΩ & Rx = 2KΩ. Prove the bridges in balance condition. Solution: The bridges in balance condition when: R3 R2 Rx R1 (3k )(1k ) (2k )(1.5k ) 3M 3M ( The bridges is in balance condition) 8 EXAMPLE 2 Refer to figure below, calculate the Rx when the bridges balance. Solution : Rx R1 200Ω R3 R2 200 800 750 Rx 213.33 Rx 800Ω 750Ω 9 Example 3 Calculate the value of unknown resistance at the Wheatstone bridge in Figure 3, assuming the bridge to be in balanced condition. Solution: R1 = 2kΩ, R2= 10kΩ, R3 = 5kΩ, and R4 = Rx R1 R4 R2 R3 R2 Rx R3 R1 10k 5k Rx 2k Rx 25k 10 Example 4 A Wheatstone bridge has R2 = 3.5 kΩ, R3 = 5.51kΩ and R1 = 7 kΩ. (a) Calculate for Rx (b) Determine the measurement range if R3 is adjusted from 1 kΩ - 8kΩ Ans: (a) 2.755 kΩ (b) 500Ω - 4 kΩ 11 Example 5 1. 2. Given the Wheatstone bridge with R1 = 15 kΩ, R2 = 10 kΩ, and R3 = 4.5 kΩ. Find RX. Calculate the current through the Galvanometer in the circuit. Given R1 = 1 kΩ, R2 = 1.6 kΩ, R3 = 3.5 kΩ, R4 = 7.5 kΩ, RG = 200Ω and V = 6V. Ans: 1. 3KΩ, 2. 12 Kelvin Bridge a modification of Wheatstone’s bridge also called a Kelvin double bridge and some countries Thomson bridge used to measure values of resistance below 1Ω In low resistance measurement, the resistance of the leads connecting the unknown resistance to the terminal of the bridge circuit may affect the measurement. 13 Kelvin bridge schematic diagram 14 Bridge Balance Equation for Kelvin Bridge Ry - resistance of the connecting leads from R3 to Rx. Galvanometer can be connected either to point c or to point a. connected to point a, the resistance Ry, of the connecting lead is added to the indication for Rx. connection is made to point c, Ry is added to the bridge arm R3 - resulting measurement of Rx is lower than the actual value. (Actual value of R3 is higher than its nominal value by the resistance Ry) If the galvanometer is connected to point b, in between points c and a, in such a way that the ratio of the resistance from c to b and that from a to b equals the ratio of resistances R1 and R2, then 15 Bridge Balance Equation for Kelvin Bridge 16 Bridge Balance Equation for Kelvin Bridge 17 Example 5 If in Figure 5 the ratio of Ra to Rb is 1000Ω, R1 is 5Ω and R1 = 0.5R2. What is the value of Rx. Solution: R1 Rx R3 R2 18