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Here is what you write:
Could you answer the read text. I just get into this field, I don’t have the experince
In general, when you have both analog and digital circuitry, you use separate ground paths for
both. This is because digital circuits tend to have fast, transient current spikes, inducing
changes on the ground path, while analog circuits tend to be slower with fewer current
spikes. Keeping the ground paths connected at only one point helps prevent digital noise
from getting into your analog system and analog noise from getting into your digital system. In
your case, the analog ground is the ground of the scope. How come? The test fixture has
power supply +9V DC to the ground of the test fixture. The computer NI5112 board has a
computer ground. When I press the “bark” button on the fixture, the current will flow to 5112
ground through BNC cable. Below is the graph of Diff mode config. The test fixture has the
ground and the measurement system has AIGND. So, you said the analog ground is the
gound of the scope. What do you mean here? If you look at the graph below, in fact there are
two ground. I don’t understand here. Would you explain?
The digital ground is the ground pin on the 7805 on your circuit board. Your circuit has
the digital and analog sections totally isolated from each other. Do you mean I need to take off
the digital ground of my push buttons that I attached the file for DGND. It remain the 7805
digital ground. Using the 6250 for monitoring and control will join the analog and digital
grounds through the 6250. This may or may not cause problems, depending on the
magnitudes of the current and voltage through the UUT. If you do need isolation, use
differential mode for the analog input to the 6250 and you should be good. Connect a 10k
resistor from the AI- input of the 6250 to the digital ground of the 6250 to finish the isolation
(this is the bias resistor). Here why diff mode can isolated the digital ground, could you explain?
DGND ground is the same as RSE ground of the 5112, 6250, cb68lp. If you use RSE for
measuring R1, the ground are the same. It can not separated, right? But, if you use Diff mode,
you add bias resistor to digital ground (DGND) I believe, why analog ground will separated the
digital ground. I don’t here. Could you explain? I know you might explain before. But, could you
describe a little more.
In looking at your original configuration, I noticed that the digital signals on the 6250 are
configured as outputs. This implies that you are controlling the system with the 6250 and you
should disconnect your pushbuttons. If you are trying to monitor the system, the digital signals
should be set as inputs.
There are two major problems I can see with your digital circuit. The first is that, to control the
system from the 6250, lines 4 and 5 must always be opposite each other. This is guaranteed
by your hardware pushbuttons, but you will have to connect it correctly and/or program it
correctly if you want to automate it through the 6250. The second is that the digital ground
connection should not be at the 5112 input. You would be better off putting it at the ground on
the 7805 power supply or some other such direct connection to the digital power
system. Unless you have added one, there is no connection between the digital power
ground and the 5112 ground. This will cause ground loop problems, which will get worse if
you use a large resistor for R1.
If you have the 5112 connected, you must measure current-to-ground through the resistor R1
as you presently have it. You cannot do it in the old position. In the current position, you can
use either differential or RSE mode, for reasons we have discussed before. I I understand
here, because right now everything is flowing on BNC cable, you can use either method., right?
In the old position, with the 5112 disconnnected, you could also use either differential or RSE,
for the same reasons. With the 5112 connected and the resistor in the old position, the
current through the resistor will not be correct, no matter what mode you use the 6250, since
some (all) of the current will be going to the 5112 ground, making your measurement
inaccurate I understand here.