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Refraction Behavior of waves at boundaries When the energy in a wave hits a fixed boundary, the disturbance in the medium through which the energy is traveling (the wave) is inverted. When the wave hits a free boundary, the pulse is reflected but not inverted. Behavior of waves at boundaries When the energy in a wave travels through media with different density (), part of the wave is reflected, part is transmitted. low to high high to low Think about it… Make a rule summarizing the reflection and transmission characteristics of waves traveling through media with different densities. Include: • Height of wave • Width of wave • Speed of wave Possible explanation? low to high high to low Transmission of energy From less dense to more dense: • • Speed decreases Wavelength decreases From more dense to less dense • • Speed increases Wavelength increases low to high v, high to low v, Waves (and light) at boundaries When light passes from air (less dense) to glass (more dense), the speed and wavelength of light decrease. Change in speed change in direction Refraction Refraction: bending the path of light The broken pencil Years of experience has trained us into thinking that light travels in straight lines from objects to our eyes. When the image forms somewhere unexpected, we have to fight that training to make sense of what we see. The broken pencil, explained Light is reflected from pencil Light is refracted when it passes from water to glass and glass to air. Light travels straight to our eyes. In this example, the image appears to the left of the object’s location and appears broken. Other examples • Magnifying water • Using water to start a fire • Spearfishing • Uncovering root beer deceit • Best profile pics ever! Marching soldiers 1. Stand shoulder to shoulder forming a straight line, connected with meter sticks. 2. A line of tape separates the room into two ‘media’ 3. When students approach the line, they use baby steps. When they pass the line, they abruptly change pace 4. Observe what happens to the direction of travel. Conditions of refraction 1. Change in speed i.e., density change in media 2. Approach the boundary at an angle Otherwise, speed would change at the same time Passing through… When light passes through material, it is actually absorbed and re-emitted and absorbed and re-emitted and absorbed and …. The speed at which light is transmitted is called optical density Index of refraction One indicator of optical density is called index of refraction, abbreviated n 𝑛𝑚𝑎𝑡𝑒𝑟𝑖𝑎𝑙 3.00 𝑥 108 𝑚 𝑠 = 𝑣𝑚𝑎𝑡𝑒𝑟𝑖𝑎𝑙 Material Index of Refraction Vacuum 1.0000 Air 1.0003 Ice 1.31 Water 1.333 Ethyl Alcohol 1.36 Plexiglas 1.51 Crown Glass 1.52 Flint Glass 1.66 Zircon 1.923 Diamond 2.417 Quantified What is the speed of light in a diamond? 8 n Trydiamond it first = 2.42; c = 3.00 x 10 m/s vTry=it ?first 𝑐 𝑛= Try it first 𝑣 => 𝑣 = 𝑐 𝑛 3.00 𝑥 108 𝑚/𝑠 Try it first 𝑣= 2.42 𝑣 x 108 m/s Try =1.23 it first Predicting the direction of bending Traveling from fast (less dense) to slow (more dense), bent TOWARDS the normal fast 𝜃𝑖𝑛𝑐𝑖𝑑𝑒𝑛𝑡 > 𝜃𝑟𝑒𝑓𝑟𝑎𝑐𝑡𝑖𝑜𝑛 Predicting the direction of bending Traveling from slow (more dense) to fast (less dense), bent AWAY the normal 𝜃𝑖𝑛𝑐𝑖𝑑𝑒𝑛𝑡 < 𝜃𝑟𝑒𝑓𝑟𝑎𝑐𝑡𝑖𝑜𝑛 Tractor analogy True if … • sides are parallel • medium on either side of transparent medium is the same. Think about it… Copy this diagram onto a sheet of paper. What is the path of the tractor and light? In real life… Think about it… Draw the missing ray in each situation Think about it… The fish is shown in its actual position. Where will the image of the fish appear to the person above the water? If the person wants to hit the fish, where should s/he throw the spear? Justify your answer. Quantifying refraction, 1 of 3 The optical density makes a difference 𝜃𝑟𝑒𝑓𝑟𝑎𝑐𝑡𝑖𝑜𝑛 𝛼 𝑛 Collect some (virtual) data Go to PHeT Bending Light simulator. Set medium 1 to air. Set medium 2 to water. Turn on the ray. Measure and record the angle of incidence and angle of refraction. Repeat 10 or more times for angles between 0 and 90 Mathematical model 𝑦 = 𝑚𝑥 + 𝑏 sin 𝜃𝑖𝑛𝑐𝑖𝑑𝑒𝑛𝑐𝑒 = 1.33 sin 𝜃𝑟𝑒𝑓𝑟𝑎𝑐𝑡𝑖𝑜𝑛 + 0 1.33 is the index of refraction of water Snell’s Law 𝑛1 sin 𝜃1 = 𝑛2 𝑠𝑖𝑛𝜃2 Where 𝑛1 is index of refraction of medium 1 𝜃1 is the angle of incidence 𝑛2 is index of refraction of medium 2 𝜃2 is the angle of refraction More? You want more? In real life… Examples Examples Quantified A jeweler wants to determine the index of refraction of a gem stone. She shines a laser through it so that the incident beam strikes the face at 45 from the normal. If the light travels through the gem at an angle of 17 from the normal, what is the index of refraction? Try first45; 𝜃1it= 𝜃2 = 17; nair = 1.00 Try2 it=first n ? Try sinit first 𝜃 𝑛 1 1 = sin 𝜃2 𝑛2 => 𝑛2 = (sin 45°) 1.00 Try first 𝑛2it= sin 17° 𝑛 = 2.42 2 Try it first sin 𝜃1 𝑛1 sin 𝜃2 Quantified If your friend shone a laser from underwater to the air at an angle of 40 from the normal, at what angle would you expect it to travel? n Trywater it first= 1.33; water = 40; nair = 1.00 Trywater it first= ? sinit first 𝜃1 𝑛1 Try = sin 𝜃2 𝑛2 => 𝜃2 = (sin 40°)(1.33) −1 𝜃 = 𝑠𝑖𝑛 Try2it first 1.00 𝜃 Try2it= first59° sin 𝜃1 𝑛1 −1 𝑠𝑖𝑛 ( ) 𝑛2 = 𝑠𝑖𝑛−1 (0.85) Demo: triangular prism 1. Place a triangular prism upright on the table. 2. Place a pin (or friend’s eye or whatever) so that the light passes parallel to the normal into one face of the prism. 3. Look through for the object through the other face of the prism. Where is it? Why can’t you see it? Critical Angle When light travels from an optically dense material (e.g., water) to less optically dense material (e.g., air), it bends away from the normal. At some incident angle, it will refract parallel to boundary of the substance, i.e., no light passes the boundary. This angle is called the critical angle. Total Internal Reflection Beyond the critical angle, light is reflected back into the original substance. This is called total internal reflection Total Internal Reflection Total internal reflection From fun swimming… to fascinating demonstrations… to cool party tricks… to cool dorm room decorations… to optics… to revolutions in communications Think about it… Is it possible for light to undergo total internal reflection as it travels from air into water? Explain your answer. Collect some more (virtual) data Go to PHeT Bending Light simulator. Set medium 1 to water. Set medium 2 to air. At what angle does light totally internally reflect at a water / air boundary? Repeat for glass / water boundary. Repeat for a glass / air boundary. What patterns do you notice? Critical angle For values n1 < n2, (i.e., traveling from more dense to less materials) @ 2 = 90, sin 𝜃𝑐𝑟𝑖𝑡𝑖𝑐𝑎𝑙 = sin 90° 𝑛2 𝑛1 sin 𝜃𝑐𝑟𝑖𝑡𝑖𝑐𝑎𝑙 = 𝑛2 𝑛1 NOTE: 𝑛 𝑛1 If n2 > n1, 𝜃𝑐𝑟𝑖𝑡𝑖𝑐𝑎𝑙 = sin−1 ( 2 ) is undefined Think about it Go to Physics Classroom Refraction simulator. http://www.physicsclassroom.com/PhysicsClassroom/media/interactive/Refraction/i ndex.html Turn on protractor. Randomize the top or bottom medium. Using the Snell’s, calculate its index of refraction. Predict its critical angle. Summary of mathematical relationships 𝑛𝑚𝑎𝑡𝑒𝑟𝑖𝑎𝑙 = 𝑐 𝑣𝑚𝑎𝑡𝑒𝑟𝑖𝑎𝑙 𝑛1 sin 𝜃1 = 𝑛2 𝑠𝑖𝑛𝜃2 sin 𝜃𝑐𝑟𝑖𝑡𝑖𝑐𝑎𝑙 = 𝑛2 𝑛1 Deriving Snell’s Law Law of refraction A wave or line of soldiers or whatever hits the surface at an angle 1. At time 0, A2 reaches boundary. At some time t, A2 has traveled some distance into new medium (l2)and A1 has reached boundary after traveling some distance (l1). The wave or soldiers or whatever has been deflected by angle 2. i r Notice that the angle of incidence is the same as the angle formed by the wave front with the boundary. sin 𝜃𝑖 = 𝑙1 𝑎 where l is the distance the wave travels in a certain amount of time, so l = v1t 𝑣1 𝑡 sin 𝜃𝑖 = 𝑎 i l1 i a Notice that the angle formed by the angle of refraction is the same as the angle between the boundary and the wave front. a sin 𝜃𝑟 = 𝑙2 𝑎 r l2 where l is the distance the wave travels in a certain amount of time, so l = v2t 𝑣2 𝑡 sin 𝜃𝑟 = 𝑎 r Law of refraction Divide to obtain law of refraction: 𝑣1 𝑡 sin 𝜃1 = 𝑣𝑎 𝑡 sin 𝜃2 2 𝑎 𝑐 sin 𝜃1 𝑣1 𝑛1 = =𝑐 sin 𝜃2 𝑣2 𝑛2 Clever! 𝑛 sin 𝜃 = 𝑛 𝑠𝑖𝑛𝜃 1 1 2 2