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BIOMEASUREMENT 2202 Sensing - hearing S2 Biological acoustics and the sense of hearing I. Objectives • To understand the basic physics of sound generation and transmission through various media. • To outline the reception and transduction of a pressure wave by the inner ear and cochlea. • To review the non-linear response and feedback aspects of audition. The nature of sound From a physical point of view, sound is a travelling wave of compression and rarefaction through a medium (solid, liquid, vapour or plasma). Consider a leaf's rustling being heard by a cat. Four stages of this process can be identified: - generation of sound at the source - transfer of sound through the intervening media - reception and encoding of sound at the hearing apparatus - cerebral decoding, interpretation and response In these lectures we shall look at all 4 aspects but with emphasis on the physical description of the first 3. The 4th stage is of concern to neuroscientists as well as musicians. Physics brings investigative tools and the theories of waves, sound and acoustics to aid in the understanding of audition. • speed of sound in different media: in a gas c = c = f RT Mw in a liquid c = B where is the ratio of specific heats, T temperature in kelvin and Mw the mean molecular weight . p B , B is the isentropic bulk modulus of elasticity defined as s is the density, and a factor to account for differences between adiabatic and isothermal processes. in a solid c = Y where Y is Young's modulus of elasticity. fo c ± vo = fs c vs • doppler shift due to relative motion: where f is frequency, v is velocity, o refers to the observer and s to the sound source. • The human ear perceives sound level logarithmically. The usual measure is the sound pressure level (SPL) defines as: p SPL = 20 log p ref where the reference pressure amplitude is (dB) pref = 2 x 10-5 Pa. 1 Lumped mechanical elements and resonance - 1D case In order to comprehend the mechanism of hearing we must first review the behaviour of mechanical resonance. The ringing of a bell, the clicking of fingernails, the shudder in an accelerating vehicle, the sound of a piano, violin, flute and even the human voice - all owe their existence and characteristics to this phenomenon. There are three basic mechanical idealisations. • elasticity (spring) F = - k (x - xo) • resistance (friction) dx F = - r .v = - r dt • inertia (mass) d2x F = m a = - m dt2 From Newton's second law of motion: d2x m dt2 dx + r dt + k (x - xo) = 0 where we define the damping coefficient or: + o2 (x - xo) = 0 k o2 = m . x = C ept solving the quadratic for p gives dx + dt r =m , and square of the undamped resonant frequency Look for a solution of the form d2x dt2 -± p = p2 + p + o2 = 0 2 - 4o2 2 This will only be a real number if ≥ 2o in which case x(t) describes an exponential decay to its equilibrium value xo. Otherwise the system undergoes damped simple harmonic motion. In this case we must allow p to be a complex number whose magnitude undergoes exponential decay, while the argument provides oscillation on the x axis: o We define the mechanical quality factor Q = and rewrite for the < 2o case p = - 2 ± i o Using Euler's formula: 1 1 - 4Q2 where i is the imaginary number i2 = -1 ei = cos + i sin we can write the transient solution for x (choice of x origin such that xo = 0) x(t) = C exp ( - 2 t ) cos (t + ) where the system now oscillates at the damped resonant frequency res = o 1 1 - 4Q2 . The constants C and are determined by the initial conditions of the system, x(0) and v(0). 2 What is happening during this behaviour? Essentially we can describe the process as follows: dx • The equilibrium state is x = xo and v = dt = 0. • When displaced from equilibrium to position x1 we do work against the elastic forces to 1 store energy in the compression of the spring PE = 2 k (x1 - xo)2 • As x moves towards xo the PE is lost to friction (damping) but also is converted to KE which can later be reconverted to PE as in a simple pendulum. • How long the oscillations last depends on the relative size of the losses compared to the energy stored as either PE or KE. • The total energy (PE + KE) of the system decays exponentially to its equilibrium value. • The system Q can be interpreted as the energy stored divided by the energy lost to friction per cycle. It also gives a rough approximation of the number of oscillations the system will undergo before losing most of its amplitude. • The system is said to be underdamped if < 2o Q > 0.5 critically damped = 2o Q = 0.5 overdamped > 2o Q < 0.5 • For the overdamped case there are no oscillations and the effective decay time constant is = 2 (1 + 1 - 4Q2 ) -1 1.0 unforced resonance displacement x 0.8 f o = 3 Hz ov erdamped critically damped underdamped 0.6 Q = 0.2 Q = 0.5 Q = 2.0 0.4 0.2 0.0 -0.2 -0.4 0.0 0.2 0.4 0.6 0.8 1.0 time t The underdamped (Q > 0.5) case can be thought of as a sinusoidal wave with an exponential decay 2 envelope with time constant = 1.0 x 0.5 displacement unforced resonance f o = 15 Hz, Q = 10 0.0 env elope = 212 ms -0.5 0.0 0.2 0.4 0.6 time t 3 0.8 1.0 Forced resonance Assume • xo = 0 • sinusoidal driving force h(t) = a sin t • solution of the form x(t) = A() sin t + B() cos t 2 dx dx m dt2 + r dt + k (x - xo) = h The solution is valid provided the following conditions are met: a (o2 - 2) a A = B = 2 2 2 2 2 2 (o - ) + (o - 2)2 + 2 2 x(t) = C() cos(t - ) An alternate form of this solution is: with and a2 C2 = A2 + B2 = (o2 - 2)2 + 2 2 o2 - 2 o A tan = B = = Q. - o This shows us that a resonant system can oscillate at the same frequency as the driving force but with a frequency dependent amplitude and phase. The amplitude reaches a peak at the natural (unforced) resonant frequency o at which the phase switches sign. Example 1: Forced amplitude response (C) for Q = 3 and fo = 200 Hz. 90 amplitude phase amplitude 60 30 1.0 0 -30 0.5 -60 0 200 400 f (Hz) 4 600 800 phase (degrees) 1.5 Example 2: Forced amplitude response (C) for Q = 20 and fo = 400 Hz. 90 3.0 amplitude phase 60 30 2.0 1.5 0 1.0 -30 0.5 -60 0 200 400 600 phase (degrees) amplitude 2.5 800 f (Hz) High Q resonances are often referred to in terms of their bandwidth which is the frequency range for which the (amplitude)2 is more than half the maximum. a2 C2 = Maximum response occurs on resonance = o π Half-power points at = ± 4 ± = o2 - 2 o tan = Q . - = ±1 o Alternately: High Q approximation: Let = o + ∆ with ∆ << o o The bandwidth is then BW = 2 ∆ ≈ Q = (rad/s) then 2Q fo or Q ∆ ≈ 1 o (Hz) Acoustic impedance We can generalise the concepts of springiness, friction or inertia by developing the idea of impedance. Recall from electrical circuit theory: We now write in similar form V=ZI p=Zv where p is the pressure difference and v is the volume velocity. The units of Z as defined here are N.s m-1 or kg s-1 . Some texts prefer alternate definitions, but all follow the same approach of relating the potential difference to the corresponding flow in a linear equation. Both p and v are considered as the real components of complex phasors of the form eit. Euler's formula (above) allows us to treat sinusoidal waves and any combination thereof. The ratio of p to v will generally have a phase component as well as a magnitude. Think of pushing someone in a child's swing. Your forcing function (p) while periodic is 90˚ out of phase with the swing's motion (v). 5 The forced mechanical resonance equation rewritten in terms of v becomes: dv m dt + r v + k vdt = h k im + r + i v = h For a phasor at frequency we have1: mass damper spring Z: magnitude m r Z: phase π +2 0 k π -2 KE dissipation PE inductor L resistor R capacitor 1 C element electrical analog Z: magnitude Units: F = - kx k in N m-1 ; in rad s-1 F = - r v r in N.s m-1 m in kg s-1 NB: N = kg m s-2 Other terms in common use: admittance: this is the reciprocal of impedance often written as Y: v=Yp compliance2: the acoustic compliance Ca of an enclosed gas is defined as: V [m5 N-1] Po V: volume of container, : the ratio of specific heats, Po: gas pressure Ca = with resistance: the acoustic resistance for sound travel through a duct depends on diameter, temperature and gas composition and mean pressure 6 inertance: air has mass that must be accelerated in order to move or change v. acoustic inertance Ma depends on the medium as well as the geometry example: air of density o in a piston of cross-sectional area S. The pipe contains mass m of air in length . o S a o o F ma dv dv p=S = S = = S S dt = S S dt S o m Ma = S 2 = S [kg m-4] Mechanical resonance - Helmholtz resonator Putting all three elements together we get a simple resonance at a frequency determined by r,Ca and Ma. This is the common bottle-resonance found by blowing across the neck. The mass of air 'bounces' on the compliance of the air trapped in the flask. Acoustic resistance in the neck and radiation of sound energy dampen the resonance. c fo = 2π S LV c = speed of sound in the gas S = neck-area L = effective length of neck V = body volume Exercises: • Estimate the resonant frequency of a 1 litre glass soft drink bottle when it is • empty • half full • full • If the bottle were plastic how would squeezing the neck affect the resonant frequency? • What if the plastic body were squeezed? • Try some simple experiments with bottles at home to confirm your predictions. • Show that for negligible damping, the resonance equation reduces to Hooke's law. • Find a solution for x(t) and v(t) for the undamped unforced resonance. Use these to derive an expression for the total energy (PE+KE) and show that this is constant with time. 7 References: Beranek LL, Acoustics, McGraw-Hill, FIZ 621.3818. Elmore WC & Heald MA, Physics of waves, Wiley, FIZ 531.33. Kinsler LE & Frey AR, Fundamentals of acoustics, Wiley, FIZ 534. Rossing TD, The science of sound, Addison-Wesley, FIZ 534. Lord Rayleigh, Phil. Mag., 34 (1917), p.94. Also his Theory of sound Vols I and II. Plesset Milton S. "Bubble dynamics" in Cavitation in real liquids, R.Davies (ed.), Elsevier, 1964, p1-17. Bogdanov K, Biology in physics - is life matter?, chapter 6, Academic Press, 1999. Hopp SL, Owren MJ & Evans CS (eds.), Animal acoustic communication, Springer, 1998, BIOL 591.594. Tavolga WN, Popper AN & Fay RR (eds.), Hearing and sound communication in fishes, SpringerVerlag, 1981. Wood A, Acoustics, Blackie & Son Ltd 1940. Notes: 1. The complex exponential function satisfies Let z = eit. Then The chain rule applies: 2. deZ Z dz = e dz dt = i z and 1 = z zdt i y = ea sin t dy a sin t = a y cos t dt = a cos t e Adiabatic expansion of an ideal gas satisfies PV = PoVo = constant. Where Po is the ambient gas pressure and Vo the rest volume. Rearranging and taking the time derivative gives: P 1 dP Vo - (1+) dV Po = V Po dt = - Vo V dt Po dV dP 1 dV So: where C is termed the compliance. dt ≈ - V dt = - C dt Example of natural resonance: Spectrum of the Westminster bell. Higher harmonics are clearly visible but die out faster than the fundamental. 8 Supplementary notes on musical acoustics. Musical sources of sound • How does it arise? - resonant vibrations of solids bell, chime, cymbal - excited modes of a system guitar string, flute, blown bottle, rain, boiling kettle, human voice - fluid in fluid jet, wind, wheezing, 'shh!' • Sources - strings & pipes sine wave - bars & cantilevers sine & hyperbolic sine (sinh) - membranes & plates Bessel functions - human voice vocal chords (fleshy folds) vibrating at ~ 150 Hz excite vocal tract resonances In all cases the sound heard depends on - physical dimensions - material properties - how it is excited - immediate surroundings (length, volume, ...) (stiffness, elasticity, ...) (where, how hard, with what, ...) (end connections, enclosure, medium, ...) Natural modes of vibration: Mathematical solutions since 1700's. (Laplace, Helmholtz, Lord Rayleigh) Each point in a vibrating body tries to stay in equilibrium with its nearest neighbours. Source 75 pce orchestra @ fff bass drum pipe organ snare drum cymbals trombone piano bass saxophone bass tuba double bass Power (W) 70 25 13 12 10 6 0.4 0.3 0.2 0.16 Source 75 pce orchestra @ mf piccolo flute clarinet french horn triangle bass voice alto voice (@ pp) average speech violin (@ pppp) 9 Power (W) 0.09 0.08 0.06 0.05 0.05 0.05 0.03 0.001 0.000024 0.0000038 Example 1: Supplementary notes on musical acoustics. c Vibrating string fn = n 2L Solution: y(x) = A sin(2πfnx) with y(0) = y(L) = 0 displacement n=1 0 x displacement n=2 0 x displacement n=7 0 Example 2: Pipe x Vibrating air column 1 fn = n f1 c f1 = 2 L 2 as for string, but antinodes at ends 3 c: speed of sound in the air flute, organ, bagpipes, didgeridoo etc NOTE: For accurate work: Correction for length due to the width at the opening: Leff = L + 0.6 a Further notes and animations are available at: 10 http://www.biophysics.uwa.edu.au/music/music.html 11 Supplementary notes on musical acoustics. Stopped pipe fn = (2n - 1)f1 c f1 = 4 L 2n + 1 fn ≈ 3 • General solution (clamped-free): Example 3: Cantilever 2 f1 with 9πc f1 ≈ 8 L2 y(x) = A cos(bx) + B sin(bx) + C cosh(bx) + D sinh(bx) with A+C=0 Free at both ends Solution values for bL 1.875 and cos(bL) cosh(bL) + 1 = 0 cos(bL) cosh(bL) - 1 = 0 Resonant frequency for mode is: 4.694 4.694 displacement clamped-free free-free First 3 modes: , B+D=0 length 0 length 0 length displacement displacement 0 12 7.855 7.855 = ckb2 10.996 10.996 Supplementary notes on musical acoustics. Example 4: The human voice Vocalisation in humans has its origin in the glottal interruption of expired air. The harmonic content and fundamental frequency depend on muscle tension and to some extent on the air flow rate. Mechanical resonances in the vocal tract modify the amplitudes of the resulting harmonics. In this way our ears can distinguish between 2 notes sung at the same pitch, but heard as "ah" or "ee" etc. Figure: Principle of generation of voiced sounds in the human voice. The vocal fold vibrations convert the steady airstream to a pulsed airstream, the glottal voice source., corresponding to a complex curve of the vocal tract, which is characterised by resonances or formants corresponding to peaks. Hence the partials closest to the formants dominate the radiated spectrum. 13 Supplementary notes on musical acoustics. Human vowels distinguished by the frequencies of the two vocal resonances R1 and R2. 14 Measurements of human hearing: • Frequency response: (Fletcher-Munsen curves) Phon: unit of loudness level. phon = SPL (compared to pure tone at 1000 Hz) • Age-related loss. The average shifts with age of the threshold of hearing for pure tones of persons with "normal" hearing (Spoor 1967) 15 • Effect of background noise: Rating chart for determining speech communication capability from speech interference levels. PSIL: average in dB of the sound pressure levels of a noise in the 3-octave bands of centre frequency 500, 1000 and 2000 Hz. (1 foot = 305 mm). 16 The hearing apparatus (audiology) • ear vs microphone - eardrum converts varying air pressure into movement of the membrane - cochlea frequency selective hairs in the inner ear respond to vibration and trigger nerve cluster - CNS brain receives multiple nerve pulses from different parts of the cochlea • logarithmic perception - loudness & dB (volume level) reference level: 20 µPa 200 µPa 2 mPa 20 mPa = = = = 0 dB 10 dB 20 dB 30 dB quietest sound faint whisper 65 dB 80 dB 100 dB 120 dB conversation loud music 'deafening' pain & damage - pitch & octaves (the musical scale) equal distances along human cochlea correspond to equal frequency ratios pitch: musical term for the fundamental frequency of a continuous sound; A 440 Hz octave: frequency ratio of 2 secret maths explanation? a (**** logb = log(a) - log(b) *****) 256 Hz 440 Hz 880 Hz 220 Hz 32 Hz = = = = = C4 A4 A5 A3 C1 !! middle C A above octave above octave below 3 octaves below • characterisation - sensitivity & dynamic range The human ear is a 'dynamic' sensor with only about 30 dB range but with a variable level determined by bio-feedback. - frequency response This depends on sound level and age, but typically covers from However, the sense of pitch or melody only extends from about 20 Hz to 18 kHz. 60 Hz to 4 kHz. Notes by Graeme Yates revised & extended by Ralph James. 17