Download Chapter 1 Review

Name:
Class:
Date:
ID: A
Chapter 1 Review
1. Name three points that are collinear.
a.
b.
points T, Q, and R
points T, Q, and S
c.
d.
points S, Q, and R
points T, S, and R
2. Name a ray from Q through P.
3. Draw four points, A, B, C, and D, on a line so that CB and CA are opposite rays and CD and CA are the
same ray.
4. IfRS = 44 and QS = 68, find QR.
Q
a.
R
S
14
b.
44
c.
112
d.
24
5. Let C be between Z) and E. Use the Segment Addition Postulate to solve for v.
DC = 3v- 30
C£ = 6v-15
DE =27
a.
v=3
b.
v = 11
c.
v = -5
d.
v=
c.
8
d.
38
6. If ^5= 15 and AC = 23, find the length of BC.
15
B
a.
1
C
b.
15
7. Find the distance between the points (1,4) and (-2, -1).
a.
-Jlo
c.
b.
10
d.
34
ID: A
Name:
8. Find the midpoint of the segment with endpoints (9, 8) and (3, 5).
a.
(3,|)
b.
(12,13)
,, 13.
-
(6, y)
d.
(l,-2)
9. Find the approximate length of the segment from point C to the midpoint of AB.
?6
C
B
-6
BC=lx-13,AB = 4x + 26, B is the midpoint of AC.
A*
10. Find AB and BC in the situation shown above.
11. Given the points P(-7, 3), g(13, 51), and M(3, 27), prove that Mis the midpoint of PQ.
12. \fmZIOJ=22° and mZHOI = 25°, then what is the measure ofZHOJ?
H
O
a.
45 C
b.
44°
d.
47°
Name:
ID: A
13. mZJHI = (2x + 7)° and mZGHI = (8x - 2)° and mZJHG = 65 C
Find mZJHI and mZGHI.
J
G
H
a.
b.
c.
d.
mZJHI = 19° and mZGHI
mZJHI = 46° and mZGHI
wZJ//7 = 13° and mZGHI
mZJHI = 52° and mZGHI
= 46°
= 19°
= 52°
= 13°
14. If angle ROS is obtuse and angle TOR is straight, then angle TOS is what kind of angle?
0
a.
obtuse
b.
right
c.
straight
d.
acute
15. In the figure (not drawn to scale), MO bisects ZLMN, mZLMO = (13* - 31)°, and mZNMO = (x + 53)°.
Solve for* and find mZLMN.
N
a.
2,38°
b.
2, 7°
c.
7,207 C
d.
7, 120°
ID: A
Name:
16. If mZJOK = 28° and mZJOL = 58°, then what is the measure of ZKOL7
O
17. AB bisects /LLAX and ZLAB measures 68°. Find the measure of ZXAB.
Complete the conditional statement to make a true statement.
18. If ZG and Z// are supplementary and m/LH - 67°, then
.
19. Solve for x:
20. The figure below is an example of a(n)
a.
nonagon
b.
octagon
c.
hexagon
d.
heptagon
Name:
ID: A
21. The figure shown below
a.
b.
is a pentagon
is a hexagon
c.
d.
is a heptagon
is a quadrilateral
c.
d.
8.555cm 2
19.9cm2
22. Find the area. All lengths are in centimeters.
9.2
a.
b.
17.11cm 2
11.31cm"
23. Find the perimeter and area of a rectangle with length 150 ft and width 15 ft.
24. Find the area and circumference of the circle. Use n = 3.14.
ID: A
Name:
25. Find the area:
34ft
ID: A
Chapter 1 Review
Answer Section
1. ANS: A
PTS: 1
DIP: Level A
REF: MLGE0084
TOP: Lesson 1.1 Identify Points, Lines, and Planes
KEY: points | collinear
MSC: Comprehension
NOT: 978-0-547-31534-8
2. ANS:
QP
PTS: 1
DIP: Level A
REF: MGEO0003
TOP: Lesson 1.1 Identify Points, Lines, and Planes
MSC: Knowledge NOT: 978-0-547-31534-8
3. ANS:
Answers may vary.
KEY: ray
D
4.
5.
6.
7.
8.
PTS: 1
DIP: Level B
REF: MHGT0097
TOP: Lesson 1.1 Identify Points, Lines, and Planes
MSC: Application NOT: 978-0-547-31534-8
ANS: D
PTS: 1
DIP: Level B
TOP: Lesson 1.2 Use Segments and Congruence
KEY: segment length | segment addition postulate
NOT: 978-0-547-31534-8
ANS: D
PTS: 1
DIP: Level B
TOP: Lesson 1.2 Use Segments and Congruence
KEY: solve | variable segment addition postulate
NOT: 978-0-547-31534-8
ANS: C
PTS: 1
DIP: Level A
TOP: Lesson 1.2 Use Segments and Congruence
KEY: segment length | segment addition postulate
NOT: 978-0-547-31534-8
ANS: D
PTS: 1
DIP: Level A
NAT: NCTM.PSSM.OO.MTH.9-12.GEO.2.a
TOP: Lesson 1.3 Use Midpoint and Distance Formulas
KEY: distance formula coordinate geometry
NOT: 978-0-547-31534-8
ANS: C
PTS: 1
DIP: Level A
NAT: NCTM.PSSM.OO.MTH.9-12.GEO.2.a
TOP: Lesson 1.3 Use Midpoint and Distance Formulas
MSC: Application NOT: 978-0-547-31534-8
KEY: draw | ray | opposite rays
REF: PHGM0109
MSC: Application
REF: MHGM0013
MSC: Application
REF: DBXM1001
MSC: Application
REF: DBTM0807
MSC: Application
REF: AKA20905
KEY: midpoint formula
ID: A
9. ANS:
PTS: 1
DIP: Level B
REF: MLGE0189
NAT: NCTM.PSSM.OO.MTH.9-12.GEO.2.a
TOP: Lesson 1 .3 Use Midpoint and Distance Formulas
KEY: distance formula | segment length | midpoint coordinate geometry
MSC: Application NOT: 978-0-547-31534-8
10. ANS:
AB = 78, BC = 78
PTS:
NAT:
TOP:
MSC:
11. ANS:
1
DIP: Level B
REF: BS022003
NCTM.PSSM.OO.MTH.9-12.PRS.3 NCTM.PSSM.OO.MTH.9-12.REP.2
Lesson 1.3 Use Midpoint and Distance Formulas
KEY: segment length | midpoint
Synthesis
NOT: 978-0-547-31534-8
PM=J(3-(-7)
+(27-3)--26
=26
PQ=
PM= MQ and PM+MQ = PQ. Thus, M is the midpoint of PQ.
12
13.
14.
15.
PTS: 1
DIF: Level B
REF: MLGE0244
NAT: NCTM.PSSM.OO.MTH.9-12.GEO.1 .c | NCTM.PSSM.OO.MTH.9-12.GEO.2.a
NCTM.PSSM.OO.MTH.9-12.REA.3 I NCTM.PSSM.OO.MTH.9-12.REA.4
KEY: coordinate proof
TOP: Lesson 1.3 Use Midpoint and Distance Formulas
MSC: Analysis
NOT: 978-0-547-31534-8
REF: MHGM0014
ANS: D
PTS: 1
DIF: Level B
TOP: Lesson 1.4 Measure and Classify Angles
KEY: angle measure [ angle addition postulate
MSC: Application
NOT: 978-0-547-31534-8
PTS: 1
DIF: Level C
REF: MLGE0216
ANS: A
NAT: NCTM.PSSM.OO.MTH.9-12.PRS.3 NCTM.PSSM.OO.MTH.9-12.REP.2
TOP: Lesson 1.4 Measure and Classify Angles
KEY: angle addition postulate angle measure
MSC: Synthesis
NOT: 978-0-547-31534-8
REF: SX760169
PTS: 1
DIF: Level B
ANS: D
KEY: angle class
TOP: Lesson 1.4 Measure and Classify Angles
NOT: 978-0-547-3 534-8
MSC: Comprehension
REF: MLGE0245
ANS: D
PTS: 1
DIF: Level B
TOP: Lesson 1.4 Measure and Classify Angles
KEY: solve linear equation angle bisector
; measure
MSC: Application
NOT: 978-0-547-31534-8
ID: A
16. ANS:
30°
PTS: 1
DIP: Level B
REF: MLGE0193
TOP: Lesson 1.4 Measure and Classify Angles
KEY: angle addition postulate angle measure
NOT: 978-0-547-31534-8
17. ANS:
mZXAB = 68°
MSC: Application
PTS: 1
DIP: Level B
REF: MLGE0088
TOP: Lesson 1 .4 Measure and Classify Angles
KEY: angle bisector | angle measure
MSC: Comprehension
NOT: 978-0-547-31534-8
ANS:
mZ.G= 113°
PTS:
TOP:
KEY:
NOT:
19. ANS:
20.
21.
22.
23.
1
DIP: Level B
REF: MGEO0043
Lesson 1 .5 Describe Angle Pair Relationships
supplementary angles angle measure
978-0-547-31534-8
MSC: Application
PTS: 1
DIP: Level B
REF: MLGE0198
NAT: NCTM.PSSM.OO.MTH.9-12.PRS.3 | NCTM.PSSM.OO.MTH.9-12.REP.2
TOP: Lesson 1.5 Describe Angle Pair Relationships
KEY: supplementary angles | adjacent angles | solve
MSC: Application
NOT: 978-0-547-31534-8
ANS: D
PTS: 1
DIP: Level A
REF: HLGM0429
TOP: Lesson 1.6 Classify Polygons
KEY: identify | polygon
MSC: Knowledge NOT: 978-0-547-31534-8
REF: MLGE0403
ANS: A
PTS: 1
DIP: Level A
TOP: Lesson 1.6 Classify Polygons
KEY: identify | polygon
MSC: Knowledge NOT: 978-0-547-31534-8
ANS: C
PTS: 1
DIF: Level B
REF: MLGE0397
NAT: NCTM.PSSM.OO.MTH.9-12.MEA.2.b
TOP: Lesson 1.7 Find Perimeter, Circumference, and Area
KEY: area triangle
MSC: Application NOT: 978-0-547-31534-8
ANS:
perimeter = 330 ft
area = 2250 ft2
PTS: 1
DIF: Level B
REF: MLGE0090
NAT: NCTM.PSSM.OO.MTH.9-12.MEA.2.b
TOP: Lesson 1.7 Find Perimeter, Circumference, and Area
MSC: Application NOT: 978-0-547-31534-8
KEY: area perimeter | rectangle
ID: A
24. ANS:
Area: 50.24 square units, Circumference: 25.12 units
PTS:
NAT:
TOP:
MSC:
25. ANS:
136ft 2
1
DIP: Level B
REF: MLGE0394
NCTM.PSSM.OO.MTH.9-12.MEA.2.b
Lesson 1.7 Find Perimeter, Circumference, and Area
Application NOT: 978-0-547-31534-8
PTS:
NAT:
TOP:
MSC:
1
DIF: Level B
REF: MLGE0396
NCTM.PSSM.OO.MTH.9-12.MEA.2.b
Lesson 1.7 Find Perimeter, Circumference, and Area
Application NOT: 978-0-547-31534-8
KEY: circle area circumference
KEY: area triangle