Download IB 5.2 Reisistance Jan 19 Agenda

Survey
yes no Was this document useful for you?
   Thank you for your participation!

* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project

Document related concepts

Nanofluidic circuitry wikipedia , lookup

Nanogenerator wikipedia , lookup

Ohm's law wikipedia , lookup

Electric charge wikipedia , lookup

Transcript
Physics 4 – Jan 19, 2017

P3 Challenge –

What is the electrostatic force (magnitude and direction)
between a positive charge of 1.3 x 10-3 C and a negative
charge of 6.2 x 10-3 C when they are separated by a
distance of 15.0 cm?
Objectives/Agenda/Assignment

Objective:



5.2 Resistance
Assignment:
Agenda:

Homework Review

Potential difference
 p205
#14

Ohm’s Law
 p225
#15-22

Resistance

Power
Electric Potential Energy

The electric force is a conservative force so there is a potential energy that
corresponds to the opposite of the work done by the conservative force.

The state for 0 electrical potential energy is if a test charge is infinitely far away from
an isolated positive charge.

As the charge moves closer to the charge, it is more and more repelled and the
electric force is doing negative work. The charge therefore is experiencing a positive
potential energy change.

Positive charges are at a high potential energy

The work done by the electric force is equal to r times the force or W= −𝒌

The potential energy is the U = 𝒌
𝑸𝒒
𝒓
𝑸𝒒
𝒓
Electric potential

The potential energy per unit charge is known as the electric
𝑸
potential or V = 𝒌
and is measured in volts.
𝒓
W = QV

1 V = 1 J/C

Electric potential is to electrical potential energy as height is to
gravitational potential energy. The test charge is akin to the mass.

Work is done moving a charge across a potential difference, just
like work is done to raise a mass across a height.
Electric potential

The potential energy per unit charge is known as the electric
𝑸
potential or V = 𝒌
and is measured in volts.
𝒓
W = QV

1 V = 1 J/C

Electric potential is to electrical potential energy as height is to
gravitational potential energy. The test charge is akin to the mass.
Electric potential

Positive charges create a relative high potential state.

Negative charges create a relative low potential state.

Moving from a lower to a high potential is a positive voltage.

Just like height, the word potential can refer to both a fixed state
and a difference in states.

Wherever there is an electric field there will be a potential
difference.
The electron Volt (eV)

Because electrons are so small, the associated energies are very small,
much smaller than a J.

1 eV is the energy of one electron charge over 1 volt

1 eV = (1.6 x 10-19 C) (1 J/C)

1 eV = 1.6 x 10-19 J

If you get a very small amount of energy, convert to eV. Or you may be
given information in eV.
Ohm’s Law

The current through a conductor is proportional to the potential
difference across it. I V So a plot of I vs V is a line with a positive
slope.

V = IR

R is the resistance of the conductor.

A plot of V vs I is a line with a slope = R

Many conductors obey Ohm’s law but not all do. We will only be
dealing with those that obey Ohm’s law.

In data booklet as R = V/I
Graphs of V vs I are not always linear.
Unit: Ohm, 
Resistance


Source of resistance are collisions of moving electrons with the
atoms of the conductor.

The kinetic energy of the electrons moving (current) gets transferred to
the wiggling of the conductor atoms (kinetic energy of atoms =
temperature).

Resistance creates a heating in the conductor.
Factors effecting resistance: R =  L/A

Nature of material
 = resistivity of the material (tables exist)

Length (proportional)

Cross-sectional area (inversely proportional)
Sample Problems

The resistivity of copper is 1.68 x 10-8 m. What is the length of a
copper wire with a diameter of 2.00 mm with a resistance of 2.00 ?

What is the voltage across a 5.00  resistor when a 1.50 A current
passes through it?

What is the current through a 25.0  resistor when a 12 V voltage is
placed across it?
Electric power

Recall the work done when moving a charge through a potential
difference: W = QV

Power = W/t = QV/t

I = Q/t
 P=
IV
All three forms are included in the data booklet.

P= IV Sub V= IR
P = I2R

P=IV
P= V2/R
Sub I = V/R
Recall Unit: Watt, W = J/s
Exit slip and homework

Exit Slip – What is the current through a copper 2.00 mm diameter
15.0 cm in length wire when connected to a 9V battery?
(Resistivity of copper is 1.68 x 10-8 m)

What’s due? (homework for a homework check next class)
 P205

#14 and p225 #15-21
What’s next? (What to read to prepare for the next class)
 Read
5.2 p 212-226