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Five-Minute Check (over Lesson 1–2) CCSS Then/Now New Vocabulary Example 1: Verbal to Algebraic Expression Example 2: Algebraic to Verbal Sentence Key Concept: Properties of Equality Example 3: Identify Properties of Equality Key Concept: Addition and Subtraction / Multiplication and Division Properties of Equality Example 4: Solve One-Step Equations Example 5: Solve a Multi-Step Equation Example 6: Solve for a Variable Example 7: Standardized Test Example Over Lesson 1–2 A. naturals (N), wholes (W), integers (Z) B. wholes (W), integers (Z), reals (R) C. naturals (N), wholes (W), rationals (Q), reals (R) D. naturals (N), wholes (W), integers (Z), rationals (Q), reals (R) Over Lesson 1–2 A. naturals (N), wholes (W) B. reals (R) C. rationals (Q), reals (R) D. integers (Z), reals (R) Over Lesson 1–2 Name the property illustrated by a + (7 + c) = (a + 7) + c. A. Associative Property of Addition B. Distributive Property C. Substitution Property D. Commutative Property of Addition Over Lesson 1–2 Simplify (2c)(3d) + c + 5cd + 3c2. A. 3c2 + 5cd + c B. 3c2 + 11cd + c C. 3c2 + 10cd D. 3c2 + c Content Standards A.CED.1 Create equations and inequalities in one variable and use them to solve problems. Mathematical Practices 3 Construct viable arguments and critique the reasoning of others. 8 Look for and express regularity in repeated reasoning. You used properties of real numbers to evaluate expressions. • Translate verbal expressions into algebraic expressions and equations, and vice versa. • Solve equations using the properties of equality. • open sentence • equation • solution Verbal to Algebraic Expression A. Write an algebraic expression to represent the verbal expression 7 less than a number. Answer: n – 7 Verbal to Algebraic Expression B. Write an algebraic expression to represent the verbal expression the square of a number decreased by the product of 5 and the number. Answer: x2 – 5x A. Write an algebraic expression to represent the verbal expression 6 more than a number. A. 6x B. x + 6 C. x6 D. x – 6 B. Write an algebraic expression to represent the verbal expression 2 less than the cube of a number. A. x3 – 2 B. 2x3 C. x2 – 2 D. 2 + x3 Algebraic to Verbal Sentence A. Write a verbal sentence to represent 6 = –5 + x. Answer: Six is equal to –5 plus a number. Algebraic to Verbal Sentence B. Write a verbal sentence to represent 7y – 2 = 19. Answer: Seven times a number minus 2 is 19. A. What is a verbal sentence that represents the equation n – 3 = 7? A. The difference of a number and 3 is 7. B. The sum of a number and 3 is 7. C. The difference of 3 and a number is 7. D. The difference of a number and 7 is 3. B. What is a verbal sentence that represents the equation 5 = 2 + x? A. Five is equal to the difference of 2 and a number. B. Five is equal to twice a number. C. Five is equal to the quotient of 2 and a number. D. Five is equal to the sum of 2 and a number. Identify Properties of Equality A. Name the property illustrated by the statement. a – 2.03 = a – 2.03 Answer: Reflexive Property of Equality Identify Properties of Equality B. Name the property illustrated by the statement. If 9 = x, then x = 9. Answer: Symmetric Property of Equality A. What property is illustrated by the statement? If x + 4 = 3, then 3 = x + 4. A. Reflexive Property of Equality B. Symmetric Property of Equality C. Transitive Property of Equality D. Substitution Property of Equality B. What property is illustrated by the statement? If 3 = x and x = y, then 3 = y. A. Reflexive Property of Equality B. Symmetric Property of Equality C. Transitive Property of Equality D. Substitution Property of Equality Solve One-Step Equations A. Solve m – 5.48 = 0.02. Check your solution. m – 5.48 = 0.02 Original equation m – 5.48 + 5.48 = 0.02 + 5.48 Add 5.48 to each side. m = 5.5 Check m – 5.48 = 0.02 ? 5.5 – 5.48 = 0.02 0.02 = 0.02 Answer: The solution is 5.5. Simplify. Original equation Substitute 5.5 for m. Simplify. Solve One-Step Equations Original equation Simplify. Solve One-Step Equations Check Original equation ? Substitute 36 for t. Simplify. Answer: The solution is 36. A. What is the solution to the equation x + 5 = 3? A. –8 B. –2 C. 2 D. 8 B. What is the solution to the equation A. 5 B. C. 15 D. 30 Solve a Multi-Step Equation Solve 53 = 3(y – 2) – 2(3y – 1). 53 = 3(y – 2) – 2(3y – 1) Original equation 53 = 3y – 6 – 6y + 2 Apply the Distributive Property. 53 = –3y – 4 Simplify the right side. 57 = –3y Add 4 to each side. –19 = y Divide each side by –3. Answer: The solution is –19. What is the solution to 25 = 3(2x + 2) – 5(2x + 1)? A. –6 B. C. D. 6 Over Lesson 1–2 Pages 22 – 23 #22 – 27, 36 – 42, 45 – 50