Survey
* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project
* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project
W.35 Pure Mathematics (Complex Number) Ex.A 1. (a) (i) Express cos 4 sin 3 as a sum of sines of multiples of . (ii) Express cos3 sin 4 as a sum of cosines of multiples of . 2. (b) Hence, find (a) Show that cos 7 64 cos7 - 112 cos5 56 cos3 - 7 cos . cos3 sin 3 cos sin d . (b) Using (a), or otherwise, show that the roots of the equation 64 x 6 - 112 x 4 56 x 2 - 7 0 are cos π 3π 5π , cos and cos . 14 14 14 (c) Hence, deduce that cos 3. i By expanding 1 3 n (a) k0 4. (a) Show that π 3π 5π 7 cos cos . 14 14 14 8 2n , find the values of 1 C 2n 2k - 3 n -1 k (b) k0 sin (2n 1) sin 2n 1 n k0 where n is a positive integer and 0 < 2 2n C - 1k 2n 1C2k 1 1 2k 1 3 k . cot2 n - k . (b) Hence, show that n k 1 5. n (2n - 1) k cot 2 3 2n 1 n and k 1 2n (n 1) k csc 2 . 3 2n 1 (a) Let n be a positive integer. Prove that 1 i tan 1 - i tan Hence, show that n 1 i tan n . 1 - i tan n C1 cot n -1 - C3 cot n -3 C5 cot n -5 - ... n n n tan n . n n 2 cot - C2 cot C4 cot n -4 - ... n n (b) By considering the roots of the equation xn C x n -1 - C2 x n -2 - C3 x n -3 C4 x n -4 C5 x n -5 - ... 0 , n 1 n n n n n evaluate k 1 cot (4k - 1) . 4n Ex.B 1. Let n be a positive integer. Show that n -1 Hence, deduce that 1 x 2n 1-n cos 2 2n k 1 k z2n - zn cos n 1 - 1- x 2n n -1 4nx 2 2 k x tan 2n . k 1 n . 2. Factorize into real quadratic factors . 3. (a) Find all the complex numbers z satisfying the equation z z n -1 . (b) Find the sum 1 2w 3w 2 ... nw n -1 where w is a root of the equation w n = 1. 4. Solve for z where 5. (a) Show that 1 z 2n 1 1 - z 2n 1 and show that tan 2 π 2π tan 2 5 . 5 5 2 4 1 x 2 - 2x cos 1 x 6 x5 x 4 x3 x 2 x 1 x 2 - 2x cos 7 7 6 2 1 x - 2x cos 7 and deduce that sin π 2π 3π 7 sin sin . 7 7 7 8 (b) Show that 3 1 x 6 - x5 x 4 - x3 x 2 - x 1 x 2 - 2x cos 1 x 2 - 2x cos 7 7 5 2 1 x - 2x cos 7 π 3π 5π 1 sin sin . and deduce that sin 14 14 14 8 6. If and are the roots of the equation (a) - 2i and - 2i with the roots 7. (1 i) z 2 - 2i z (2 - 3i) 0 , construct the equation (b) 2 and 2 . (a) Write down all the 2n th roots of 1. (b) Hence, factorize z 2n - 1 into real quadratic factors. z2 - 2z cos rn n -1 (Answer : z 2n - 1 = z2 - 1 r 1 (c) Deduce from (b) that (i) sin n 2n -1 sin (ii) sin n -1 cos r 1 - cos r n π 2π (n - 1) n sin sin . n n n 2n -1 1 ) 8. If is a complex cube root of 1, show that (a) (b) (c) 9. 1 2 1 - 2 4 , 1 - 2 3 - 1 - 2 3 0 , 2 5 2 2 6 2 2 5 2 6 729 . If is a complex fifth root of 1, show that 1 10. By considering the equation 1 2 2 1 3 3 1 4 4 -1 . z i 8 x 4 - 28x 3 70x 2 - 28x 1 0 z - i 8 are tan 2 0 , prove that the roots of the equation π 3π 5π 7π , tan 2 , tan 2 and tan 2 . 16 16 16 16 Ex.C 1. Let Tn (x) = cos n cos-1x . (82) (a) Prove that Tn+1(x) = 2x Tn(x) - Tn-1(x) and hence show that Tn(x) is a polynomial in x of degree n with leading coefficient 2n-1 where n = 1, 2 , 3, … . (b) By using De Moivre’s Theorem, or otherwise, find ak (k = 0 , 1 , 2, … , n) in cos n n = k0 a k cos (n - 2k) . (c) By using (b), or otherwise, show that xn = 1 2n 1 n -1 2 k0 n Ck Tn -2k (x) for - 1 x 1 where n is any odd positive integer . 2. (a) State De Moivre’s Theorem for a positive integral value. (76) (b) Find a polynomial f (x) such that cos 5 cos f cos . Hence, find the value of ( 0 ) such that f cos = 0 . (c) By using (b), or otherwise, show that 3 1 - cos 1 - cos 10 10 3 Hence, show that sin sin 10 10 7 9 1 . 1 - cos 1 - cos 10 10 16 1 . 4 3. (a) Show that if P (x) is a polynomial with real coefficients and r is a complex number for which P (r) = 0, then P r 0 . (b) If z is a complex number whose imaginary part is positive, show that for any complex number r, r - z r - z r - z r - z if Im r 0 if Im r 0 . When does the equality hold? (c) Let z1 , z2 , … , zn be n complex numbers whose imaginary parts are all strictly positive and put z - z z n a i b z n -1 ... a i b n n 1 1 j j1 n j j j where a1 , a2 , … , an and b1 , b2 , … , bn are real . Show that if r is a root of the equation x n a1 x n -1 ... a n 0 , then n j1 n r - z j j j1 r - z j . j (d) Hence, deduce from (b) and (c) that every root of the equation x n a1 x n -1 ... a n 0 is real . 4. (a) By using De Moivre’s Theorem, show that sin (2n 1) sin 2n 1 n r0 where n is a positive integer and 0 < 2 - 1r 2n 1C2r 1 cot2 n - r . (b) By using (a) and the relations between the coefficients and the roots of the equation n r0 - 1r n - r 0 , show that 2n 1C2r 1 x n and deduce that k 1 n k 1 n (2n 2) k csc 2 . 3 2n 1 n (2n - 1) k cot 2 3 2n 1