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11-8 Solving Two-Step Inequalities California Standards Preview of Grade 7 AF4.1 Solve two-step linear equations and inequalities in one variable over the rational numbers, interpret the solution or solutions in the context from which they arose, and verify the reasonableness of the results. Holt CA Course 1 11-8 Solving Two-Step Inequalities When you solve two-step equations, you can use the order of operations in reverse to isolate the variable. You can use the same process when solving two-step inequalities. Holt CA Course 1 11-8 Solving Two-Step Inequalities Remember! Draw a closed circle when the inequality includes the point and an open circle when it does not include the point. Holt CA Course 1 11-8 Solving Two-Step Inequalities Additional Example 1A: Solving Two-Step Inequalities Solve. Then graph the solution set on a number line. y 2 –6>1 y 2 –6>1 +6 +6 y >7 2 y > (2)7 (2) 2 Add 6 to both sides. Multiply both sides by 2. y > 14 – 21 Holt CA Course 1 – 14 –7 0 7 14 21 11-8 Solving Two-Step Inequalities Additional Example 1A Continued Check y -6>1 2 ? 20 -6>1 2 4>1 Holt CA Course 1 20 is greater than 14 Substitute 20 for y. 11-8 Solving Two-Step Inequalities Additional Example 1B: Solving Two-Step Inequalities Solve. Then graph the solution set on a number line. 5≥ m +8 –3 m 5≥ +8 –3 –8 –8 m -3 ≥ –3 m (–3) (–3)(–3) ≤ –3 m≥9 Holt CA Course 1 Subtract 8 from both sides. Multiply both sides by –3, and reverse the inequality symbol. –3 0 3 6 • 9 12 15 11-8 Solving Two-Step Inequalities Additional Example 1C: Solving Two-Step Inequalities Solve. Then graph the solution on a number line. 4y – 5 < 11 4y – 5 < 11 +5 +5 4y < 16 4y 4 –6 Holt CA Course 1 Add 5 to both sides. < 16 4 y<4 –4 –2 0 Divide both sides by 4. º 2 4 6 11-8 Solving Two-Step Inequalities Additional Example 1D: Solving Two-Step Inequalities Solve. Then graph the solution set on a number line. –4 ≥ –3x + 5 –4 ≥ –3x + 5 –5 –9 ≤ –3x –3 –3 3≤x Holt CA Course 1 –5 Subtract 5 from both sides. Divide both sides by –3, and reverse the inequality symbol. –9 –6 –3 0 3 6 9 11-8 Solving Two-Step Inequalities Check It Out! Example 1A Solve. Then graph the solution set on a number line. h 7 + 1 > –1 h 7 + 1 > –1 –1 –1 h > –2 7 h > (7)(–2) (7) 7 Subtract 1 from both sides. Multiply both sides by 7. h > –14 – 21 Holt CA Course 1 – 14 –7 0 7 14 21 11-8 Solving Two-Step Inequalities Check It Out! Example 1A Continued Check h + 1 > -1 7 ? 7 + 1 > -1 7 is greater than -14 7 Substitute 7 for h. 2>1 Holt CA Course 1 11-8 Solving Two-Step Inequalities Check It Out! Example 1B Solve. Then graph the solution set on a number line. m +1≥7 –2 m +1≥7 –2 – 1 –1 Subtract 1 from both sides. m ≥ 6 –2 (–2) m ≤ (–2)(6) Multiply both sides by –2, and –2 reverse the inequality symbol. m ≤ –12 Holt CA Course 1 • –18 –12 –6 0 6 12 18 11-8 Solving Two-Step Inequalities Check It Out! Example 1C Solve. Then graph the solution on a number line. 2y – 4 > –12 2y – 4 > –12 +4 +4 2y > –8 2y 2 º > –8 2 y > –4 –6 –4 –2 Holt CA Course 1 0 2 4 Add 4 to both sides. Divide both sides by 2. 6 11-8 Solving Two-Step Inequalities Check It Out! Example 1D Solve. Then graph the solution set on a number line. –9x + 4 ≤ 31 –9x + 4 ≤ 31 – 4 –4 –9x ≤ 27 –9x ≥ 27 –9 –9 x ≥ –3 –9 –6 –3 Holt CA Course 1 0 3 6 Subtract 4 from both sides. Divide both sides by –9, and reverse the inequality symbol. 9 11-8 Solving Two-Step Inequalities Additional Example 2: Application Sun-Li has $30 to spend at the carnival. Admission is $5, and each ride costs $2. What is the greatest number of rides she can ride? Let r represent the number of rides Sun-Li can ride. 5 + 2r ≤ 30 –5 –5 Subtract 5 from both sides. 2r ≤ 25 Divide both sides by 2. 2r ≤ 25 2 2 1 25 , or 12 r≤ 2 2 Sun-Li can ride only a whole number of rides, so the most she can ride is 12. Holt CA Course 1 11-8 Solving Two-Step Inequalities Check It Out! Example 2 Brice has $30 to take his brother and his friends to the movies. If each ticket costs $4.00, and he must buy tickets for himself and his brother, what is the greatest number of friends he can invite? Let t represent the number of tickets. 8 + 4t ≤ 30 –8 –8 Subtract 8 from both sides. 4t ≤ 22 4t ≤ 22 Divide both sides by 4. 4 4 t ≤ 5.5 Brice can only buy a whole number of tickets, so the most people he can invite is 5. Holt CA Course 1