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Section 2.2 Notes - Almost Done Section2.2:TheNormalDistributions NormalDistributions Aclassofdistributionswhosedensitycurvesaresymmetric, uni-modal,andbell-shaped. NormaldistributionsareVERYimportantinstatistics. Whichnumericalsummarywouldweusetodescribethe centerandspreadofaNormaldistribution? Notation: Section 2.2 Notes - Almost Done CalculatingσusingtheNormaldensitycurve Section 2.2 Notes - Almost Done The68-95-99.7Rule-IntheNormaldistributionwith meanμadstandarddeviationσ: • 68%ofalltheobservationsfallwithinonestandard deviation(σ)ofthemeanμ(inbothdirections) • 95%ofalltheobservationsfallwithintwostandard deviations(2σ)ofthemeanμ(inbothdirections) • 99.7%ofalltheobservationsfallwithinthreestandard deviations(3σ)ofthemeanμ(inbothdirections) Section 2.2 Notes - Almost Done Thedistributionofheightsofwomenaged20to29isapproximately Normalwithmean64inchesandstandarddeviation2.7inches.Use the68-95-99.7ruletoanswerthefollowingquestions. (a)Betweenwhatheightsdothemiddle95%ofyoungwomenfall? (b)Whatpercentofyoungwomenaretallerthan61.3inches? Youtry: Thelengthofhumanpregnanciesfromconceptiontobirthvaries accordingtoadistributionthatisapproximatelyNormalwithmean266 daysandstandarddeviation16days.Usethe68-95-99.7ruleto answerthefollowingquestions. (a)Betweenwhatvaluesdothelengthsofthemiddle68%ofall pregnanciesfall? (b)Howshortaretheshortest2.5%ofallpregnancies? (c)Whatpercentofpregnanciesarelongerthan314days? Section 2.2 Notes - Almost Done ThestandardNormaldistribution • InXinitelymanyNormaldistributions Oneforeverypossiblecombinationofmeansandstandard deviations • StandardNormaldistribution-N(0,1) • Wecanstandardizeanyvalueofavariable,x.Thisstandardized valueiscalledthez-score,orz.Ifweactuallywanttodo calculationsusingthisstandardizedscoreweneedtoknowthe distributionoftheoriginalvariable.Iftheoriginalvariableis Normalthenthez-scorecomesfromastandardNormal distribution. •Az-scoretellsushowmanystandarddeviationstheoriginal observationfallsawayfromitsmeanANDinwhich direction. Section 2.2 Notes - Almost Done YOUTRY: Theheightsofwomenaged20to29areapproximatelyNormal withmean64inchesandstandarddeviation2.7inches:N(64,2.7). Menthesameagehavemeanheight69.3incheswithstandard deviation2.8inchesandfollowanapproximatelyNormal distribution:N(69.3,2.8).Whatarethez-scoresforawoman6feet tallandaman6feettall?Sayinsimplelanguagewhatinformation thez-scoresgivetheactualheightsdonot. Section 2.2 Notes - Almost Done UsingtheNormalcurvetodetermineproportions/percentiles (Beyondthe68-95-99.7rule) • TheareaunderanyNormalcurve(ordensitycurveforthatmatter) isequalto1. • Ifwewanttoknowtheproportionofobservationsthatliewithina certainrangeofobservationvalueswelookfortheareaofthe densitycurvebetweenthosetwovalues(forANYdensitycurve- notjustNormal) • WehaveatablethatgivesusthesevaluesforONLYthestandard Normaldistribution. UsetableAto+indtheproportionofobservationsfroma standardNormaldistributionthatsatis+ieseachofthe followingstatements.Ineachcase,sketchastandard Normalcurveandshadetheareaunderthecurvethatis theanswertothequestion. (a)z<2.66 (b)z>-1.45 (c)-0.58< z<1.93 SincewecanstandardizeANYNormaldistributionwecanusethistableforANYNormaldistribution. Section 2.2 Notes - Almost Done FOREXAMPLE: SupposethattheheightsofyoungwomenhaveaNormaldistribution, N(64,2.7).Whatproportionorpercentageofallyoungwomenare lessthan70inchestall? Usingthesamedistributionfromthelastexample,whatproportionof womenaregreaterthan60inchestall? Section 2.2 Notes - Almost Done Usingthesamedistributionfromthelastexample,whatproportionof womenarebetweentheheightsof62and68inchestall? YOUTRY: UsetableAtoXindtheproportionofobservationsfroma standardNormaldistributionthatsatisXieseachofthe followingstatements.Ineachcase,sketchastandard Normalcurveandshadetheareaunderthecurvethatis theanswertothequestion. (a)z<2.85 (b)z>2.85 (c)z>-1.66 (d)-1.66<z<2.85 Section 2.2 Notes - Almost Done Inthe2008Wimbledontennistournament,RafaelNadalaveraged115 milesperhour(mph)onhisXirstserves.Assumethatthedistributionof hisXirstservespeedsisNormalwithameanof115mphandastandard deviationof6mph. a)AboutwhatproportionofhisXirstserveswouldyouexpecttoexceed 120mph? b)WhatpercentofRafaelNadal’sXirstservesarebetween100and110 mph? x z TableA% Section 2.2 Notes - Almost Done Sometimeswearegivenaparticularproportionofobservationsthatlie aboveorbelowsomeobservedvalueandwewantto7indthatobserved value. FOREXAMPLE: UsetableAto+indthevalueof zofastandardNormalvariablethat satis2ieseachofthefollowingconditions. (a)Thepointzwith34%oftheobservationsfallingbelowit. (b)Thepointzwith12%oftheobservationsfallingaboveit. FOREXAMPLE: SupposethattheheightsofyoungwomenhaveaNormaldistribution, N(64,2.7).Whatheightsare75%ofyoungwomenlessthan? Section 2.2 Notes - Almost Done YOUTRY: UsetableAtoXindthevaluezofastandardNormalvariablethatsatisXies eachofthefollowingconditions.(UsethevalueofzfromTableAthat comesclosesttosatisfyingthecondition.)Ineachcase,sketchastandard Normalcurvewithyourvalueofzmarkedontheaxis. (a)Thepointzwith25%oftheobservationsfallingbelowit. (b)Thepointzwith40%oftheobservationsfallingaboveit. Section 2.2 Notes - Almost Done ScoresontheWechslerAdultIntelligenceScaleareapproximately Normallydistributedwithμ=100andσ=15. (a)WhatIQscoresfallinthelowest25%ofthedistribution? (b)HowhighanIQscoreisneededtobeinthehighest5%? Normal Calculations using your Calculator Taking an observation - x - and converting it to a percentile: 1. Press 2nd VARS to get the DISTR menu 2. select option 2:normalcdf 3. enter the lower bound, upper bound, µ, σ 4. If you are interested in the values LESS than a certain xvalue then use -10^99 as your lower bound 5. If you are interested in the values GREATER than a certain x-value then use 10^99 as your upper bound. 6. IF you have already converted your x-value to its corresponding z-score, don't enter the µ and σ Section 2.2 Notes - Almost Done Taking a percentile (percent to the left of a value) and converting it to a value of the original variable (x): 1. Press 2nd VARS to get the DISTR menu 2. select option invnorm 3. enter the percentile (percent to the left of a value), µ, σ 4. Remember, if you are given the percent GREATER than a value, subtract from 1 (100%) to get the percentile. 5. IF you just want the correspondingz-score (not x-value) don't enter µ and σ Assessing Normality As we've seen, Normal models provide good models for some distributions of real data. However, some common variables are usually skewed and therefore distinctly non-Normal. It is risky to assume that a distribution is Normal without inspecting the data or even if the data are uni-modal and roughly symmetric. We an check to see if the distribution of the data follow the 68-95-99.7 rule. We an also use a Normal Probability Plot - a plot of each observation against the corresponding z-score for the percentile it represents. If there is a strong linear pattern, the distribution is close to Normal. Section 2.2 Notes - Almost Done Normal Probability Plots on the Calculator 1. Enter the data into a single list 2. Go to STATPLOT (2nd Y=) 3. Turn a single plot on 4. Select the LAST of the graphs - bottom right 5. Select the correct Data List 6. Select X as your Data Axis 7. Choose the mark you would like to see in your graph for the points 8. Go to your graph and use Zoom option 9:zoomstat Section 2.2 Notes - Almost Done Themeasurementslistedbelowdescribetheuseablecapacity(incubicfeet)of asampleof36side-by-siderefrigerators.ArethedataclosetoNormal? 12.913.714.114.214.514.514.614.715.115.215.315.3 15.315.315.515.615.615.816.016.016.216.216.316.4 16.516.616.616.616.817.017.017.217.417.417.918.4 Section 2.2 Notes - Almost Done Homework:p.131#s41-59odd,63,65,66, 68,69-74all