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Solve for x.
1. 3π‘₯ + 1 = 8
2. 3 π‘₯ βˆ’ 2 = 4
3. βˆ’2 π‘₯ = 10
1.
3π‘₯ + 1 = 8
3x + 1 = 8
or 3x + 1 = - 8
-1
-1
-1
-1
3x = 7
3x = -9
3
3
3
3
x=
7
3
or x = -3
2. 3 π‘₯ βˆ’ 2 = 4
+2 +2
3π‘₯ =6
3
3
π‘₯ =2
x = 2 or x = -2
3. βˆ’2 π‘₯ = 10
-2
-2
π‘₯ = βˆ’5
No Solution
Algebra II
 To
write & solve inequalities
involving absolute value
 Less
Th”AND”
π‘₯ <5
x < 5 AND
 Great”OR”
π‘₯ >5
x > 5 OR
x > -5
Flip
Inequality
& Change
Sign!
x < -5
1.
2π‘₯ βˆ’ 1 < 5
Less ThAND
2x – 1 < 5
and 2x
+1 +1
2x < 6
2x
2
2
2
x < 6 and x > -2
–1>-5
+1
+1
> -4
2
-2 < x < 6
2.
3π‘₯ βˆ’ 4 ≀ 8
Less ThAND
3x - 4 ≀ 8
and 3x – 4 β‰₯ -8
+4 +4
+4 +4
3x ≀ 12
3x β‰₯ -4
3
3
3
3
x ≀ 4 and x β‰₯
4
βˆ’
3
4
βˆ’
3
≀x≀4
3.
2π‘₯ + 4 β‰₯ 6
GreatOR
2x + 4 β‰₯ 6 or
2x + 4 ≀-6
-4 -4
- 4 -4
2x β‰₯ 2
2x ≀ -10
2
2
2
2
x β‰₯ 1 or x ≀ -5
4.
5π‘₯ + 10 > 25
GreatOR
5x + 10 > 25 or 5x + 10 < -25
- 10 -10
-10 -10
5x > 15
5x < -35
5
5
5
5
x > 3 or x < -7
5.
βˆ’2π‘₯ + 3 > -4
All Real Numbers
Absolute Value is always positive &
will ALWAYS be greater than a
negative number!!
6.
βˆ’3π‘₯ + 4 < βˆ’12
No Solution
Absolute Value is always positive &
will NEVER be less than a negative
number!!
7.
* Know it’s Greatβ€œor” >
π‘₯βˆ’# >#
* Find average of endpoints
βˆ’1 + 11 10
=
=5
2
2
*Find how far endpts are from avg: 6
π‘₯βˆ’5 >6
8.
* Know it’s LessAnd or Equal to ≀
π‘₯βˆ’# ≀#
* Find average of endpoints
βˆ’8 + 12 4
= =2
2
2
*Find how far endpts are from avg: 10
π‘₯ βˆ’ 2 ≀10
9.
* Know it’s Greatβ€œor” or equal to β‰₯
π‘₯βˆ’# β‰₯#
* Find average of endpoints
βˆ’10 + 6 βˆ’4
=
= βˆ’2
2
2
*Find how far endpts are from avg: 8
π‘₯ βˆ’ (βˆ’2) β‰₯ 8
π‘₯+2 β‰₯8
10.
* Know it’s LessAnd <
π‘₯βˆ’# <#
* Find average of endpoints
βˆ’3 + 3 0
= =0
2
2
*Find how far endpts are from avg: 3
π‘₯βˆ’0 <3
π‘₯ <3
 Your
friend show the problem as
shown. Describe and correct the
error.
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