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Algebra 1 Unit 5.1 Post-test Review KEY 1. Write the equation for the following graphs in slope-intercept form. y –9 –8 –7 –6 –5 –4 –3 –2 –1 –1 –2 –3 –4 –5 –6 –7 –8 –9 y y 9 8 7 6 5 4 3 2 1 9 8 7 6 5 4 3 2 1 9 8 7 6 5 4 3 2 1 1 2 3 4 5 6 7 8 9 x –9 –8 –7 –6 –5 –4 –3 –2 –1 –1 –2 –3 –4 –5 –6 –7 –8 –9 𝒚 = −𝒙 − 𝟏 1 2 3 4 5 6 7 8 9 x –9 –8 –7 –6 –5 –4 –3 –2 –1 –1 –2 –3 –4 –5 –6 –7 –8 –9 𝒙=𝟓 1 2 3 4 5 6 7 8 9 x 𝒚 = 𝟑𝒙 + 𝟓 Given the following functions find each value. 𝑓(𝑥) = −𝑥 2 + 4 2 𝑘(𝑥) = −𝑥 2 − 4𝑥 − 2 ℎ(𝑥) = (𝑥 − 2)(3𝑥 + 1) 𝑔(𝑥) = 3 𝑥 − 9 2. 𝑔(−3) 3. 𝑘(−3) -11 1 4. 𝑓(−4) -12 Now find x for each of the following using 𝑓(𝑥), 𝑔(𝑥)𝑎𝑛𝑑 ℎ(𝑥)𝑎𝑛𝑑 𝑘(𝑥)𝑎𝑏𝑜𝑣𝑒. 5. 𝑓(𝑥) = −5 3 6. 𝑔(𝑥) = 5 and -3 7. ℎ(𝑥) = 0 21 2 and -1/3 8. Graph the equations described below. a) An equation parallel to 𝑦 = 𝑥 − 2 Explain how you know where to graph equation. The slope is 1 so graph any line with a positive y slope of 1 9 8 7 6 5 4 3 2 1 –9 –8 –7 –6 –5 –4 –3 –2 –1 –1 –2 –3 –4 –5 –6 –7 –8 –9 2013-2014 b) An equation perpendicular to 𝑦 = −2𝑥 − 2 How do you know where to graph the equation? Slope is -2 so perpendicular line would have y slope of ½. Start anywhere on y axis, go up 1 9 8 and right 2. 7 6 5 4 3 2 1 1 2 3 4 5 6 7 8 9 x –9 –8 –7 –6 –5 –4 –3 –2 –1 –1 –2 –3 –4 –5 –6 –7 –8 –9 1 2 3 4 5 6 7 8 9 x Page 1 Algebra 1 Unit 5.1 Post-test Review KEY 8.Continued c) An equation parallel to x =5 d) An equation with a slope of zero y y 9 8 7 6 5 4 3 2 1 –9 –8 –7 –6 –5 –4 –3 –2 –1 –1 –2 –3 –4 –5 –6 –7 –8 –9 9 8 7 6 5 4 3 2 1 Any vertical line Any horizontal line 1 2 3 4 5 6 7 8 9 x –9 –8 –7 –6 –5 –4 –3 –2 –1 –1 –2 –3 –4 –5 –6 –7 –8 –9 1 2 3 4 5 6 7 8 9 x 9. Write an equation in slope intercept form for the following lines. a) Slope is 7 and the y intercept is -2. b) line goes through (5,9) and (-33,9) y=9 𝒚 = 𝟕𝒙 − 𝟐 d) Perpendicular to 𝑦 = −5𝑥 − 2 and through (0,4) c) Slope is undefined and line goes through (5,7) x =5 y= e) Line goes through (0,-3) and (2,9) f) Perpendicular to 𝑦 = 4 7 𝟏 𝟓 x+4 + 2 and through (0,1) 𝟕 𝒚 = 𝟔𝒙 − 𝟑 𝒚 = −𝟒𝒙 + 𝟏 Use the table at the right to answer the following (express answer in function notation). a. Find 𝑟(−𝑤). (1 pt) 𝒓(−𝒘) = −𝟐. 𝟓 3 b. Solve 𝑟(𝑥) = 2. (2 pts) 𝒓(−𝒕) = 2013-2014 3 2 x r(x) -w -2.5 -t 3 2 0 -5 t 6.2 w -3 Page 2