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Bell Ringer If the test average for your class is 78 with a standard deviation of 5, what would your z-score be if you made an 88? Boxplot of 3rd Hour, 4th Hour 100 90 Data 80 70 60 50 3rd Hour 4th Hour Standardizing values means we shift the data to fit a normal model (bell-shaped curve). This is only appropriate for unimodal and symmetric distributions. Recall: A standardized value is called a z-score. Standardizing into z-scores does not change the shape of the distribution. Standardizing into z-scores changes the center to 0. (Also called the 68-95-99.7 Rule) About 68% of observations fall within 1 standard deviation of the mean. About 95% of observations fall within 2 standard deviations of the mean. About 99.7% of observations fall within 3 standard deviations of the mean. This means that almost all z-scores will be between -3 and 3. But we need to remember that all data make up 100% The Normal Model split into sections: (The total area under the curve is 100%) Only 2.5% of data will have a z-score greater than 2. 2.5% 𝜎 2.5% 𝜎 𝜎 𝜎 𝜎 𝜎 Similarly 2.5% will have a z-score less than -2. A number describing a population is called a parameter. A number describing a sample (just a part of the population) is called a statistic. Statistic 𝑥 = 𝑚𝑒𝑎𝑛 𝑆 = 𝑠𝑡𝑎𝑛𝑑𝑎𝑟𝑑 𝑑𝑒𝑣𝑖𝑎𝑡𝑖𝑜𝑛 Parameter 𝜇 = 𝑚𝑒𝑎𝑛 𝜎 = 𝑠𝑡𝑎𝑛𝑑𝑎𝑟𝑑 𝑑𝑒𝑣𝑖𝑎𝑡𝑖𝑜𝑛 𝑇ℎ𝑒 𝑛𝑜𝑡𝑎𝑡𝑖𝑜𝑛 𝑁 𝜇, 𝜎 𝑚𝑒𝑎𝑛𝑠 𝑡ℎ𝑒 𝑁𝑜𝑟𝑚𝑎𝑙 𝑚𝑜𝑑𝑒𝑙 𝑤𝑖𝑡ℎ 𝑎 𝑚𝑒𝑎𝑛 𝑜𝑓 𝜇 𝑎𝑛𝑑 𝑎 𝑠𝑡𝑎𝑛𝑑𝑎𝑟𝑑 𝑑𝑒𝑣𝑖𝑎𝑡𝑖𝑜𝑛 𝑜𝑓 𝜎. This model is N(184,8) 160 168 176 184 192 200 208 𝐶𝑜𝑛𝑠𝑡𝑟𝑢𝑐𝑡 𝑡ℎ𝑒 𝑁𝑜𝑟𝑚𝑎𝑙 𝑚𝑜𝑑𝑒𝑙 𝑓𝑜𝑟 𝑁(50, 7) 29 36 43 50 57 64 71 Example: In the 2006 Winter Olympics men’s combined event, Jean-Baptiste Grange of France skied the slalom in 88.46 seconds – about 1 standard deviation faster than the mean. If a Normal model is useful in describing slalom times (meaning the data was nearly symmetric), about how many of the 35 skiers finishing the event would be expected to have skied the slalom faster than Jean-Baptiste? His time lies at about 1 standard deviation below the mean. That means approximately 16% of the times were lower. 16% of 35 is 5.6, so probably 5 or 6 skiers did better. As a group, the Dutch are among the tallest people in the world. The average Dutch man is 184 cm tall – just over 6 feet. If a Normal model is appropriate and the standard deviation for men is about 8 cm, what percentage of all Dutch men will be over 2 meters (200 cm) tall? 160 168 176 184 192 200 208 About 2.5% of all Dutch men will be over 2 meters tall. Practice: Suppose it takes you 20 minutes, on average, to drive to school with a standard deviation of 2 minutes. Also suppose the Normal model is appropriate for the distribution of driving times. a) How often will you arrive at school in less than 22 minutes? b) How often will it take you more than 24 minutes? c) Do you think the distribution of your driving times is unimodal and symmetric? d) What does this say about the accuracy of your predictions? Answers: a) 84% of the driving times will be less than 22 minutes. b) 2.5% of the driving times will be more than 24 minutes. c) Road blocks, stop lights, wrecks, and other incidents could cause some driving times to be delayed. It is possible for the distribution to end up skewed to the right. d) If it is skewed, the Normal model would not be appropriate and our predictions would not be accurate. Today’s Assignment: Pg. 131 #25, 26