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Q1. A normal population has a mean of 20.0 and a standard deviation of 4.0. a. What proportion of the population is between 20.0 and 25.0? b. What proportion of eh population is less than 18.0? 25 20 1.25 4.0 a. 1.25 found by z b. 0.3944, found in Appendix D c. 0.3085, found by z 18 20 0.5 2.5 Find 0.1915 in Normal Distribution table for z = – 0.5 then 0.5000 – 0.1915 = 0.3085 Q2. The number of viewers of American Idol has a mean of 29 million with a standard deviation of 5 million. Assume the is distribution follows a normal distribution. What is the probability that next week's show will: a. Have between 30 and 40 million viewers? b. Have at least 23 million viewers? c. Exceed 40 million viewers. Let X be the number of viewers of American Idol. Given that X is normal with mean µ = 29 million and standard deviation = 5 million. Standardizing the variable X using Z X X 29 and from standard normal tables, 5 we can find the probabilities as follows. What is the probability that next week's show will have between 30 and 34 million viewers? 30 29 X 34 29 P (30 < X < 34) = P 5 5 = P (0.2 < Z < 1) = 0.262 Distribution Plot Normal, Mean=0, StDev=1 0.4 0.262 Density 0.3 0.2 0.1 0.0 0 0.2 X 1 What is the probability that next week's show will have at least 23 million viewers? We need P (X ≥ 23). X 23 29 P (X ≥ 23) = P = P (Z ≥ -1.2) = 0.8849 5 Distribution Plot Normal, Mean=0, StDev=1 0.4 0.3 Density 0.8849 0.2 0.1 0.0 -1.2 0 X What is the probability that next week's show will exceed 40 million viewers? We need P (X > 40). X 40 29 P (X > 40) = P = P (Z > 2.2) = 0.0139 5 Distribution Plot Normal, Mean=0, StDev=1 0.4 Density 0.3 0.2 0.1 0.0 0.0139 0 X 2.2