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Transcript
Conservation of Mechanical Energy
We have seen:
W1 → 2 = U 1 − U 2
But,
K1 + W1 → 2 = K 2
Implies,
Rearrange,
Conservation of Energy: The SUM of ALL energies remains constant.
Conservation of Mechanical Energy:
The SUM of ALL Potential and Kinetic
energies remains constant.
• Works only with conservative forces.
K1 + U 1 − U 2 = K 2
Law of Conservation of Energy
• Ignores thermodynamic energy, strain
energy, etc.
The total energy is neither increased nor decreased in any process.
Energy can be transformed from one form to another, and from one
body to another, but the total amount remains constant.
∴ ΔK + ΔU + Δ[all other forms of energy ]= 0
• Includes thermodynamic energy, strain energy, chemical energy, etc.
K1 + U 1 = K 2 + U 2 ⇒ K1 − K 2 + U 1 − U 2 = 0
∴ ΔK + Δ U = 0
Given: A 75.0 kg parachutists jumps off a
training tower that is 85.0 m high. He
lands with a vertical speed of 5.00 m/s.
Assume the drag force is constant
Potential Energy
•
The amount of work that a conservative force would do if
the force were to move from its current position to a
given (defined) reference position.
•
The reference position is called the datum.
•
The symbol of Potential Energy is U.
•
Types of forces that have Potential Energy:
Required: Calculate the drag force and
compare it to the man’s weight.
Solution:
•
•
Weight (i.e., the force due to gravity).
•
Spring.
•
ANY Constant Conservative Force.
Friction and ALL other Non-Conservative forces DO
NOT have a Potential Energy.
Where did the “lost work” go?
1
Newton’s Law of Universal Gravitation
„
„
Scalar form
mm
F = G 12 2
r21
Vector form
mm
F12 = − G 1 2 2 r̂21
r21
‰
Where
„
„
„
„
„
„
G = universal gravitational constant = 6.67 x 10-11 N⋅m2/kg
m1 = mass of body 1
m2 = mass of body 2
r21 = position vector from body 2 to body 1
r21 = magnitude of the position vector from body 2 to body 1
r̂21 = position vector from body 2 to body 1
Escape Speed
At what radial speed will an object
“escape” the pull of Earth’s gravitation?
Gravitational Potential
Locate the datum at
∞
∞
∞
U (r ) = ∫ − Fdr = − ∫ G
r
r
mmE
dr
r2
∞
1
dr
2
r r
U (r ) = −GmmE ∫
∞
1⎤
⎡1 ⎤
⎡1
U (r ) = −GmmE ⎢ ⎥ = −GmmE ⎢ − ⎥
r
r
∞
⎣ ⎦r
⎣
⎦
U (r ) = −G
mmE
r
Impact Speed
Astronomers discover a meteorite at a distance
of 80,000 km from the center of Earth. The
meteorite is moving directly toward Earth with
a velocity of 2000 m/s What will be the
velocity of the meteorite when it hits Earth’s
surface? Ignore all drag effects.
2