Download n is the # of sides

Survey
yes no Was this document useful for you?
   Thank you for your participation!

* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project

Document related concepts

Dessin d'enfant wikipedia , lookup

Line (geometry) wikipedia , lookup

Simplex wikipedia , lookup

Multilateration wikipedia , lookup

Perceived visual angle wikipedia , lookup

Apollonian network wikipedia , lookup

Golden ratio wikipedia , lookup

Euler angles wikipedia , lookup

Reuleaux triangle wikipedia , lookup

Rational trigonometry wikipedia , lookup

History of trigonometry wikipedia , lookup

Trigonometric functions wikipedia , lookup

Euclidean geometry wikipedia , lookup

Pythagorean theorem wikipedia , lookup

Incircle and excircles of a triangle wikipedia , lookup

Integer triangle wikipedia , lookup

Transcript
Part 2
Unit 4-Review
Part 2- Segment in a triangle
Name of relationship
In words/ Symbols
360
1. Exterior angles in a polygon.
a). ONE Exterior
b) Sum of Exterior
and Angle Relationships
a)
𝑛
n is the # of sides
b) Sum of Interior.
3. Segments in a triangle:
Exterior angles and formed by
extending a side of the triangle.
b) Sum is AlWAYS 360 degrees( NO MATH
NEEDED)
2. Interior angles in a polygon.
a) ONE Interior
Diagrams/ Hints/ Techniques
a) The supplement of on Exterior angle-they are
linear pairs!--> Exterior + Interior = 180
Remember! One exterior and one interior angle
add up to 180 degrees!
b) Number of β–³ ′𝑠 times 180. οƒ  ( n-2)180
Medians- Goes to the midpoint of the opposite side
creating two equal segments
Altitudes-Are perpendicular to the opposite side
creating right angles
Perpendicular bisectors- Goes to the midpoint of
opposite side and is perpendicular to it.
Angle bisectors- bisects the angle at the vertex it
goes through making 2 congruent angles.
** In Isosceles and Equilateral triangles these
segments coincide!
4. Points of concurrence.
Angle
Bisector
βŠ₯
Bisector
2 or more medians Centroid : Always inside the
triangle. Cuts each median into a 2:1 ratio
2 or more Altitudes Orthocenter: Inside for acute
triangles, on the triangle for right triangles and
outside for obtuse triangles.
2 or more angle bisectors Incenter: Always inside
the triangle.
ALL OF MY CHILDREN ARE
BRING IN PEANUT BUTTER
COOKIES.
2 or more perpendicular bisectors Circumcenter:
Inside for acute triangles, on the triangle for right
triangles and outside for obtuse triangles.
5.Centroid and Ratios
Centroid cuts every median into a 2:1 ratio. Use this
ratio to set up equation 2X + 1x= whole length of
median.
Read carefully- What is the segment they want?
Sometimes you need to substitute back in!
Part 2
1) In the diagram below of quadrilateral ABCD with diagonal
, and
. If
is parallel to
,
,
,
, find m < 𝐴𝐡𝐷
2) Using the inferences provided, identify each of the segments as one of the following for
Δ𝐢𝐡𝐴:
Altitude, Median, angle bisector, or perpendicular bisector.
B
Μ…Μ…Μ…Μ…
Μ…Μ…Μ…Μ… βŠ₯ 𝐴𝐢
a. Given: 𝐡𝐷
Μ…Μ…Μ…Μ…
𝐡𝐷 must be a(n)
G
A
Μ…Μ…Μ…Μ…
b. Given: Μ…Μ…Μ…Μ…
𝐴𝐸 β‰… 𝐸𝐢
Μ…Μ…Μ…Μ…
𝐡𝐸 must be a(n)
c. Given: ∑𝐴𝐡𝐹 β‰… ∑𝐢𝐡𝐹
Μ…Μ…Μ…Μ… must be a(n)
𝐡𝐹
d. Given Μ…Μ…Μ…Μ…
𝐺𝐸 βŠ₯ Μ…Μ…Μ…Μ…
𝐴𝐢 π‘Žπ‘›π‘‘ Μ…Μ…Μ…Μ…
𝐴𝐸 β‰… Μ…Μ…Μ…Μ…
𝐸𝐢
Μ…Μ…Μ…Μ… must be a(n)
𝐺𝐸
E
C
F
D
Part 2
3) Adrian thinks the segment NK in the following triangle is an altitude while Daniel thinks
it’s a median. Is Adrian correct? IS Daniel correct? Are they both correct? Are they both
incorrect? EXPLAIN!
4)
Find the coordinates of the centroid of the triangle with the given vertices.
J(βˆ’1, 2), K(5, 6), L(5, βˆ’2)
5) Find one of the exterior angles of a regular decagon.
6) Find the measure of one interior angle of a regular nonagon (9 sides).
7) Find the number of sides of a polygon whose sum of interior angles in 1620°.
Part 2
8) a. Circle the point of concurrence that is formed when 2 or more altitudes intersect.
Centroid
Orthocenter
Incenter
Circumcenter
e. Where could this point be located? ( circle all that apply)
Inside the triangle
outside the triangle
On the triangle
9) a. Circle the point of concurrence that is formed when 2 or more medians intersect.
Centroid
Orthocenter
Incenter
Circumcenter
f.
Where could this point be located? ( circle all that apply)
Inside the triangle
outside the triangle
On the triangle
10) In triangle ABC, Μ…Μ…Μ…Μ…Μ…
𝐴𝐷, Μ…Μ…Μ…Μ…Μ…
𝐢𝐹, and Μ…Μ…Μ…Μ…
𝐡𝐸 are medians. If Μ…Μ…Μ…Μ…
𝐢𝐹 = 33, find CG and FG.
In βˆ†π·πΈπΉ, π‘šβˆ π· = 3π‘₯ + 5, π‘šβˆ πΈ = 4π‘₯ βˆ’ 15, π‘Žπ‘›π‘‘ π‘šβˆ πΉ = 2π‘₯ + 10. Which statement would be true?