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Grade: High School Course: Algebra II District Adopted Materials: Algebra 2 (Glencoe/McGraw-Hill) 2003 Standard 1: Number and Computation – The student uses numerical and computational concepts and procedures in a variety of situations. Benchmark 1: Number Sense – The student demonstrates number sense for real numbers and algebraic expressions. Benchmark 2: Number Systems and Their Properties – The student demonstrates an understanding of the real number system; recognizes, applies, and explains their properties, and extends these properties to algebraic expressions. Benchmark 3: Estimation – The student uses computational estimation with real numbers in a variety of situations. Benchmark 4: Computation – The student models, performs, and explains computation with real numbers and polynomials in a variety of situations. Standard 2: Algebra – The student uses algebraic concepts and procedures in a variety of situations. Benchmark 1: Patterns – The student recognizes, describes, extends, develops, and explains the general rule of a pattern in a variety of situations. Benchmark 2: Variables, Equations, and Inequalities – The student uses variables, symbols, real numbers, and algebraic expressions to solve equations and inequalities in variety of situations. Benchmark 3: Functions – The student analyzes functions in a variety of situations. Benchmark 4: Models – The student develops and uses mathematical models to represent and justify mathematical relationships found in a variety of situations involving tenth grade knowledge and skills. Standard 3: Geometry – The student uses geometric concepts and procedures in a variety of situations. Benchmark 1: Geometric Figures and Their Properties – The student recognizes geometric figures and compares and justifies their properties of geometric figures in a variety of situations. Benchmark 2: Measurement and Estimation – The student estimates, measures and uses geometric formulas in a variety of situations. Benchmark 3: Transformational Geometry – The student recognizes and applies transformations on two- and three-dimensional figures in a variety of situations. Benchmark 4: Geometry From An Algebraic Perspective – The student uses an algebraic perspective to analyze the geometry of two- and three-dimensional figures in a variety of situations. Standard 4: Data – The student uses concepts and procedures of data analysis in a variety of situations. Benchmark 1: Probability – The student applies probability theory to draw conclusions, generate convincing arguments, make predictions and decisions, and analyze decisions including the use of concrete objects in a variety of situations. Benchmark 2: Statistics – The student collects, organizes, displays, explains, and interprets numerical (rational) and non-numerical data sets in a variety of situations. Indicators The student… HS.1.1.K1 knows, explains, and uses equivalent representations for real numbers and algebraic expressions including integers, fractions, decimals, percents, ratios; rational number bases with integer exponents; rational numbers written in scientific notation; absolute value; time; and money (2.4.K1a) ($), e.g., –4/2 = (–2); a(-2) b(3) = b3/a2 HS.1.1.A1 generates and/or solves real-world problems using equivalent representations of real numbers and algebraic expressions (2.4.A1a) ($), e.g., a math classroom needs 30 books and 15 calculators. If B represents the cost of a book and C represents the cost of a calculator, generate two different expressions to represent the cost of books and calculators for 9 math classrooms HS.1.2.K3▲names, uses, and describes these properties with the real number system and demonstrates their meaning including the use of concrete objects (2.4.K1a) ($): o commutative (a + b = b + a and ab = ba), associative [a + (b + c) = (a + b) + c and a(bc) = (ab)c], distributive [a (b + c) = ab + ac], and substitution properties (if a = 2, then 3a = 3 x 2 = 6); o identity properties for addition and multiplication and inverse properties of addition and multiplication (additive identity: a + 0 = a, multiplicative identity: a • 1 = a, additive inverse: +5 + –5 = 0, multiplicative inverse: 8 x 1/8 = 1); o symmetric property of equality (if a = b, then b = a); o addition and multiplication properties of equality (if a = b, then a + c = b + c and if a = b, then ac = bc) and inequalities (if a > b, then a + c > b + c and if a > b, and c > 0 then ac > bc); o zero product property (if ab = 0, then a = 0 and/or b = 0) HS.1.2.A1 generates and/or solves real-world problems with real numbers using the concepts of these properties to explain reasoning (2.4.A1a) ($): o commutative, associative, distributive, and substitution properties, e.g., the chorus is sponsoring a trip to an amusement park. They need to purchase 15 adult tickets at $6 each and 15 student tickets at $4 each. How much money will the chorus need for tickets? Solve this problem two ways. o identity and inverse properties of addition and multiplication, e.g., the purchase price (P) of a series EE Savings Bond is found by the formula ½ F = P where F is the face value of the bond. Use the formula to find the face value of a savings bond purchased for $500. o symmetric property of equality, e.g., Sam took a $15 check to the Teaching Time On-going Bloom’s Strand Sequence Synthesis Variables, Equations, and Inequalities; Advanced R M Analysis Equivalent Represent R M S(9-12) .5 Knowledge Number Systems and Properties S(9-11) .25 bank and received a $10 bill and a $5 bill. Later Sam took a $10 bill and a $5 bill to the bank and received a check for $15. $ addition and multiplication properties of equality, e.g., the total price for the purchase of three shirts in $62.54 including tax. If the tax is $3.89, what is the cost of one shirt, if all shirts cost the same? o addition and multiplication properties of equality, e.g., the total price for the purchase of three shirts is $62.54 including tax. If the tax is $3.89, what is the cost of one shirt? T = 3s + t $62.54 = 3s + $3.89 - $3.89 $62.54 - $3.89 = 3s $58.65 = 3s $58.65 = 3s = 3s ÷ 3 $19.55 = s o zero product property, e.g., Jenny was thinking of two numbers. Jenny said that the product of the two numbers was 0. What could you deduct from this statement? Explain your reasoning. HS.1.2.K4 uses and describes these properties with the real number system (2.3.K1a) ($): o transitive property (if a = b and b = c, then a = c), o reflexive property (a = a). HS.1.3.K2 uses various estimation strategies and explains how they were used to estimate real number quantities and algebraic expressions (2.4.K1a) ($) HS.1.4.K1c A student will be able to solve and graph equations and absolute value equations and inequalities. [1-6] HS.1.4.K3 finds prime factors, greatest common factor, multiples, and the least common multiple of algebraic expressions (2.4.K1b) HS.2.1.K1 identifies, states, and continues the following patterns using various formats including numeric (list or table), algebraic (symbolic notation), visual (picture, table, or graph), verbal (oral description), kinesthetic (action), and written o arithmetic and geometric sequences using real numbers and/or exponents (2.4.K1a); e.g., radioactive half-lives; o patterns using geometric figures (2.4.K1h); o algebraic patterns including consecutive number patterns or equations of functions, e.g., n, n + 1, n + 2, ... or f(n) = 2n – 1 (2.4.K1c,e); o special patterns (2.4.K1a), e.g., Pascal’s triangle and the Fibonacci sequence Knowledge Number Systems and Properties S(9-11) Application Advanced R S(9-11) Comprehension Analysis Variables, Equations, Inequalities Advanced Application Advanced I R M RM S(9-11) R S(9-11) .25 1 1.5 1 1 HS.2.2.K1 knows and explains the use of variables as parameters for a specific variable situation (2.4.K1f), e.g., the m and b in y = mx + b or the h, k, and r in (x – h)2 + (y – k)2 = r2 Analysis HS.2.2.A1 represents real-world problems using variables, symbols, expressions, equations, inequalities, and simple systems of linear equations (2.4.A1c-e) ($). HS.2.2.K2 manipulates variable quantities within an equation or inequality (2.4.K1e), e.g., 5x – 3y = 20 could be written as 5x – 20 = 3y or 5x(2x + 3) = 8 could be written as 8/(5x) = 2x + 3 Application HS.2.2.K2 solves (2.4.K1d) ($): o N linear equations and inequalities both analytically and graphically; o quadratic equations with integer solutions (may be solved by trial and error, graphing, quadratic formula, or factoring); o ▲N systems of linear equations with two unknowns using integer coefficients and constants; o radical equations with no more than one inverse operation around the radical expression; o equations where the solution to a rational equation can be simplified as a linear equation with a nonzero denominator, e.g., __3__ = __5__. (x + 2) (x – 3) o equations and inequalities with absolute value quantities containing one variable with a special emphasis on using a number line and the concept of absolute value. o exponential equations with the same base without the aid of a calculator or computer, e.g., 3x + 2 = 35 HS.2.2.A2 represents and/or solves real-world problems with (2.4.A1c) ($): o ▲N linear equations and inequalities both analytically and graphically, e.g., tickets for a school play are $5 for adults and $3 for students. You need to sell at least $65 in tickets. Give an inequality and a graph that represents this situation and three possible solutions. o quadratic equations with integer solutions (may be solved by trial and error, graphing, quadratic formula, or factoring), e.g., a fence is to be built onto an existing fence. The three sides will be built with 2,000 meters of fencing. To maximize the rectangular area, what should be the dimensions of the fence? o systems of linear equations with two unknowns, e.g., when comparing two cellular telephone plans, Plan A costs $10 per Analysis Analysis Variables, Equations, Inequalities; Advanced Variables, Equations, and Inequalities Variables, Equations, Inequalities; Advanced Variables, Equations, Inequalities; Advanced I R On-going R M S(9-12) R M S(9-11) On-going I R S(9-11) 3 On-going month and $.10 per minute and Plan B costs $12 per month and $.07 per minute. The problem is represented by Plan A = .10x + 10 and Plan B = .07x + 12 where x is the number of minutes. o radical equations with no more than one inverse operation around the radical expression, e.g., a square rug with an area of 200 square feet is 4 feet shorter than a room. What is the length of the room? o a rational equation where the solution can be simplified as a linear equation with a nonzero denominator, e.g., John is 2 feet taller than Fred. John’s shadow is 6 feet in length and Fred’s shadow is 4 feet in length. How tall is Fred? HS.2.3.K2 matches equations and graphs of constant and linear functions and quadratic functions limited to y = ax2 + c (2.4.K1d,f) Analysis Advanced HS.2.3.K4 determines x- and y-intercepts and maximum and minimum values of the portion of the graph that is shown on a coordinate plane (2.4.K1f) Analysis HS.2.3.K5 identifies domain and range of: o relationships given the graph or table (2.4.K1e-f) o linear, constant, and quadratic functions given the equation(s) (2.4.K1d) HS.2.3.K7 uses function notation Analysis Variables, Equations, Inequalities; Advanced Relations and Functions; Advanced HS.2.3.K8 evaluates function(s) given a specific domain ($) Comprehension Application HS.3.4.K2 determines if a given point lies on the graph of a given line or parabola without graphing and justifies the answer (2.4.K1f) Analysis HS.3.4.K4 ▲finds and explains the relationship between the slopes of parallel and perpendicular lines (2.4.K1f), e.g., the equation of a line 2x + 3y = 12. The slope of this line is ־2/3. What is the slope of a line perpendicular to this line? HS.3.4.K6 ▲ recognizes the equation of a line and transforms the equation into slope-intercept form in order to identify the slope and y-intercept and uses this information to graph the line (2.4.K1f). Analysis HS.3.4.K7 recognizes the equation y = ax2 + c as a parabola; represents and identifies characteristics of the parabola including opens upward or opens downward, steepness (wide/narrow), the vertex, maximum and Analysis Analysis Relations and Functions; Advanced Relations and Functions; Advanced Advanced Variables, Equations, Inequalities; Advanced Variables, Equations, Inequalities; Advanced Variables, Equations, Inequalities; I R S(9-11) I R .5 R M On-going R M On-going I R .5 R M S(9-11) R M S(9-11) .5 R M S(9-11) .5 R M S(9-11) 1 .5 .5 minimum values, and line of symmetry; and sketches the graph of the parabola (2.4.K1f). HS.3.4.K8 explains the relationship between the solution(s) to systems of equations and systems of inequalities in two unknowns and their corresponding graphs (2.4.K1f), e.g., for equations, the lines intersect in either one point, no points, or infinite points; and for inequalities, all points in double-shaded areas are solutions for both inequalities ACT 2-6, 6-6 A student will recognize and graph relations, functions, and special functions and identify the domain and range. Advanced Analysis Variables, Equations, Inequalities; Advanced R M S(9-11) 1.5 Comprehension Advanced 2 ACT 4-1 A student is able to organize data in matrix form and solve equations involving matrices. Comprehension Advanced ACT 4-2, 4-3 A student is able to add, subtract, and multiply matrices. Comprehension Advanced ACT 4-7, 4-8 A student is able to evaluate determinants. Comprehension Advanced ACT 4-6 A student is able to solve systems by Cramer's Rule. Comprehension Advanced ACT 5-1, 5-2 A student is able to do operations of polynomials. Comprehension Advanced ACT 5-4 A student is able to factor polynomials. Comprehension Advanced ACT 5-5, 5-6 A student is able to simplify radical and radical equations. Comprehension Advanced ACT 5-9 A student is able to do the operations of radicals and complex numbers. Comprehension Advanced ACT 6-3, 6-4, 6-5 A student will solve quadratic equations by several methods. Comprehension Advanced ACT 7-1 A student is able to graph a polynomial function. (ACT) [7-1] Comprehension Advanced ACT 7-4, 7-5, 7-6 A student is able to use synthetic division to evaluate functions, determine whether a binomial is a factor, and find the zeros of the Comprehension Advanced I R M I R M I R M I R M I R M I R M I R M I R M I R M I R M I R M I R 1 2 1 2 1 3 2 4 6 1 2 polynomial function. ACT 7-7 A student is able to find the sum, difference, product, quotient, and composition of functions. Comprehension Advanced ACT 7-8 A student is able to find the inverse of functions and proving the functions are inverses. Comprehension ACT 6-6, 8-2, 8-3, S3B4, S2B4 The student will write equations of parabolas and circles Comprehension Relations and Functions; Advanced Advanced ACT 8-4, 8-5, 8-6 The student will recognize equations and sketch graphs of conics including ellipse and hyperbola. Comprehension Advanced ACT 9-1, 9-2, 9-3 The student will add, subtract, multiply, and divide rational expressions. Comprehension Advanced ACT 10-1, 10-2 The student is able to solve exponential and logarithmic equations. Comprehension Advanced ACT 10-1 The student is able to graph exponential functions. Comprehension Advanced ACT 10-3 The student is able to evaluate logarithmic equations using properties of logarithms. Comprehension Advanced ACT 10-4 The student is able to solve exponential equations and inequalities using common logarithms. Comprehension Advanced ACT 10-5 The student is able to solve growth and decay application problems. Comprehension Advanced M I R M I R M I R M I R M I R M I R M I R M I R M I R M I R M 1 1 2 1 3 1 1 1 1 1