Survey
* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project
* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project
Lesson Plan Grade 10 Academic Math Lesson: Unit: Trigonometry 7 - 2___ Topic: Problems using Similar Triangles homework check: Principles of Mathematics 10 p. 378 # 4 – 6, 8, 11 – 13 note: Problems using Similar Triangles Similar triangles can be used to determine measurements that cannot be measured directly using standard techniques. This process is called indirect measurement. We continue to use the proportions of similar triangles to solve for unknown side lengths. It is important to note that the scale factor of one corresponding side to another can be used to multiply any other side to find the measure. For example, in the diagram D 51 A 6.0 cm 51 1.2 cm 1.1 cm 59 59 B 1.0 cm E C F The triangles are similar because two angles are equal, therefore, the ratio of side AB to DE should be the same for each of the other sides. Essentially, we want to know the scale factor ‘n’. DE n= AB 6 = 1.2 =5 Therefore, if we multiply each of the sides by 5, we find the missing measures. Side EF = 1(5) = 5 cm and side DF = 1.1(5) = 5.5 cm. Solving word problems involving diagrams that must be drawn requires some definition. An angle of inclination (or elevation) is an angle that rises from the horizontal. An angle of depression is an angle that falls from the horizontal. A new bridge is going to be built across a river, but the width of the river is unknown and cannot be measured directly. Surveyors set up posts are points A, B, C, D, and E and took the measurements relative to the posts. Find the width of the river. B river C A 9m D 50 m 13 m E Step 1: establish similarity < A = < D and < C = < C in each triangle, therefore the triangles are similar. Step 2: establish order of similarity triangle ABC = triangle DEC Step 3: solve for unknown measure AC AB = DC DE 50 AB = 9 13 13 ( 50 ) = AB 9 AB = 72m Therefore, the river is 72 m wide. homework assignment: Principles of Mathematics 10 p. 386 # 2, 4, 5, 7, 9, 11 – 13