Download Magnet

Ch. 31
Electromotive Force Revisited
•Suppose we have some source of force on charges that transport them
•Suppose it is capable of doing work W on each charge
•It will keep transporting them until the work required is as big as the
work it can do
–
q
+
W  qV
•The voltage difference at this point is the electromotive force (EMF)
•Denoted E
W
E
q
Motional EMF
vB
W
•Suppose you have the following circuit in
v
the presence of a magnetic field
L
•Charges inside the cylinder
B
•Now let cylinder move
•Moving charges inside conductor feel force
F  qv  B
•Force transport charges – it is capable of doing work
•This force is like a battery - it produces EMF W  F  s  LqvB
E  W q  vLB
dW
v
•v is the rate of change of the width W
•We can relate this to the change in magnetic flux dt
d  AB 
dA
dB
dW
E
LB   B


dt
dt
dt
dt
dB
E
dt
Lenz’s Law
Force on charges in rod move them upward gives counter-clockwise
current.
Counter clockwise current increases flux through loop
The magnetic field of an induced current
opposes the change that produced it.
Warmup 16
Concept questions
A wire, initially carrying no current, has a radius
that starts decreasing at t = 0. As it shrinks, which
way does current begin to flow in the loop?
A) Clockwise B) Counter-clockwise C) No current
D) Insufficient information
dB
E
dt
•Flux into screen is deceasing.
•Want to increase it to oppose that.
JIT Quick Quiz 31.1
A circular loop of wire is held in a uniform magnetic field, with the plane of the loop
perpendicular to the field lines. Which of the following will not cause a current to be induced in
the loop?
(a)
(b)
(c)
(d)
crushing the loop
rotating the loop about an axis perpendicular to the field lines
keeping the orientation of the loop fixed and moving it along the field lines
Pulling the loop out of the field
Ans C
Lenz’s Law
•As the wire shrunk, the magnetic flux decreased
•But the wire acquired a current,
which tried to increase it
The induced current in a loop is
Current loops
in the direction that opposes the
resist change
change in magnetic flux through
the area enclosed by the loop
dB
E
dt
•Move loop to the right
•Current flows to
maintain B-field
•Current dies away
•Move loop to the left
•Current flows to kill
B-field
•Current dies away
Power and Motional EMF
•Resistor feels a voltage – current flows
E  vLB
I E R
P  IE
•Where does the power come from?
•Current is in a magnetic field
F  IL  B
v
R
F  ILB
•To get it to move, you must oppose this force
•You are doing work
W  Fs
L
dW
ds
P 
 F
 ILBv  I E
dt
dt
The power dissipated in the resistor
matches the mechanical power you
must put in to move the rod
B
F
JIT Quick Quiz 31.2
In the figure below, a given applied force of magnitude Fapp results in a constant speed v and a
power input P. Imagine that the force is increased so that the constant speed of the bar is doubled
to 2v. Under these conditions, the new force and the new power input are which of the following?
(a) 2F and 2P
(b) 4F and 2P
(c) 2F and 4P
(d) 4F and 4P
I = e/R = BLv/R
F = ILB = B2L2v/R
P = Fv
Ans C
Electric Fields from Faraday
•We can generate electromotive force – EMF – by
moving the loop in and out of magnetic field
•Can we generate it by moving the magnet?
dB
E
dt
Magnet
Faraday’s Law works whether the wire
is moving or the B-field is changing*
•How can there be an EMF in the wire in this case?
•Charges aren’t moving, so it can’t be magnetic fields
•Electric fields must be produced by the changing B-field!
•The EMF is caused by an electric field that points around the loop
E W q
 F  ds
q
dB
 E  ds  dt  0

 E  ds
Ex- (Serway 31-10). An aluminum ring of radius r1 and Resistance R is placed on
top of a long air-core solenoid with n turns per meter and radius r2 as shown
below. Suppose the magnetic field due to the current in the solenoid at the end of
the solenoid is half that at the center of the solenoid, and is parallel to its axis.
Assume the field is negligible outside the solenoid. If the current in the solenoid is
increasing at a rate of I /t, (a) What is the magnitude and direction of the
current in the ring? (b) At the center of the ring, what is the magnitude and
direction of the magnetic field produced by the induced current in the ring?
Solve on
Board
CT-1- The bar magnet shown below is moved toward the loop. Va - Vb
is
S
A. positive
B. negative
C. zero.
Ans B
CT - 2-A long, straight wire carries a steady current I. A rectangular
conducting loop lies in the same plane as the wire, with two sides
parallel to the wire and two sides perpendicular. Suppose the loop is
pushed toward the wire as shown. Given the direction of I, the induced current in the loop is
A. clockwise.
B. counterclockwise.
C. need more information
Ans B
Warmup 17
Eddy Currents
What happens as I drop the magnet into the copper
tube (Compare to if drop equivalent non-magnet)?
A) Falls as usual
B) Falls slower
C) Falls faster
D) Floats constant
E) Pops back up and out
•As magnet falls, some places have magnetic fields
that diminish
•Current appears, replacing magnetic field
•This acts like a magnet, pulling it back up
•At bottom end, current appears to oppose change
•This repels the magnet, slowing it down
•Current is only caused by motion of magnet
•If motion stops, resistance stops current
•If motion is small, opposition will be small
•It doesn’t stop, it goes slowly
S
N
S
N
N
S
Warmup 17
How to make an AC generator
•Have a background source of magnetic fields, like permanent magnets
•Add a loop of wire, attached to an axle that can be rotated
•Add “slip rings” that connect the rotating loop to outside wires
•Rotate the loop at angular frequency 
•Magnetic flux changes with time
  t
 B  BA cos   BA cos t 
•This produces EMF
•To improve it, make the loop repeat
many (N) times
dB
e 
dt
A
e  N BA sin t 
Sample Problem
A rectangular loop of wire 20 cm by 20 cm with 50 turns is rotated
rapidly in a magnetic field B, so that the loop makes 60 full rotations a
second. At t = 0 the loop is perpendicular to B. (a) What is the EMF
generated by the loop, in terms of B at time t? (b) What B-field do we
need to get a maximum voltage of 170 V?
•The angle is changing constantly with time

•After 1/60 second, it must have gone in one full
loop of
circle
wire
1
  t
2   60
  120
•The flux is given by   NA  B  NAB cos  NAB cos t 
B
•The EMF is given by
dE
 NAB sin t   50  0.04120  B sin t 
E
dt
B  0.225 T
170  754B
 754B sin t 
Ex- Serway (31-34). A magnetic field directed into the page changes with
time according to B = (0.0300 t2 + 1.40) T, where t is the time in seconds.
The field has a cross-section of radius R = 2.5 cm (as though from a
solenoid). What are the magnitude and direction of the electric field at a
point r = 0.0200 m at t = 3.0 s?
Solve on
Board
Comments on Generators:
•The EMF generated is sinusoidal in nature (with simple designs)
•This is called alternating current - it is simple to produce
•This is actually how power is generated
•Generators extremely similar to motors
– often you can use a single one for both
•Turn the axle – power is generated
•Feed power in – the axle turns
•Regenerative braking for electric or hybrid cars
Jit Quick Quiz 31.4
In an AC generator, a coil with N turns of wire spins in a magnetic field. Of the following
choices, which will not cause an increase in the emf generated in the coil?
(a)
(b)
(c)
(d)
replacing the coil wire with one of lower resistance
spinning the coil faster
increasing the magnetic field
increasing the number of turns of wire on the coil
Ans A
Ground Fault Circuit Interrupters
•Fuses/circuit breakers don’t keep you from getting electrocuted
•But GFI’s (or GFCI’s) do
•Under normal use, the current
on the live wire matches the
current on the neutral wire
•Ampere’s Law tells you there is
no B-field around the orange
donut shape
GFCI
•Now, imagine you touch the live wire – current
path changes (for the worse)
•There is magnetic field around the donut
•Changing magnetic field means EMF in blue wire
•Current flows in blue wire
•Magnetic field produced by solenoid
•Switch is magnetically turned off