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Simple Harmonic Motion (SHM) Ball in a Bowl: SF SF FN Fg FN Fg F 0 Stable Equilibrium (restoring force, not constant force) m k rest position 0 +x F ma kx mx Hooke’s Law (equation of motion) “Guess” a solution: x t A sin Bt C Does it work? kA sin Bt C mAB 2 sin Bt C Yes, if: k mB 2 x(t) …A and C can take any value A = amplitude t C = phase lag = Period = 2p/B B = angular freq. = w w2pf So usually written… xt A sin wo t k wo m A and from initial conditions. Example: Mass (m) on spring (k) displaced x 1.2 = 1 cm at t=0: y = -9.8427 + 16.35x R= 1 1 xt A sin wo t x t Aw o cosw o t x 0 A sin 1cm p A sin 1cm 2 x 0 Awo cos 0 p 2 Force [N] 0.8 0.6 0.4 0.2 0 -0.2 0.58 A 1cm k p xt 1cm sin t m 2 0.6 0.62 0.64 0.66 Displacement [m] 0.68 0.7 When a mechanical system is at a point of stable equilibrium, a perturbation will result in a restoring force that drives it back to equilibrium. The resulting equation of motion has the following form: x wo x 0 2 The solution is an oscillating trajectory at frequency wo known as Simple Harmonic Motion.