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Discrete Random Variables Sometimes we want to compare 2 or more frequency distributions: Cost of living in UK Which is the cheapest place? We want to refer to a measure that Represents the whole distribution. Arithmetic Mean Measure of central tendency Expected value (E) Arithmetic mean and Expected value A fair dice is thrown 60 times and the results are recorded in a frequency distribution table: x 1 2 f 9 11 12 8 Mean? 3 4 5 6 NOW: given a probability function, calculate the Expected value of X. () 4 x 13 7 P( X x) fx f 3.43(2dp) Will ALWAYS be 1! 1 2 0.1 0.2 5 0.7 Multiply each value of X by its corresponding probability xP Add these values Divide by the total probability xP P Can you write a general formula for mean/expected value for any probability distribution? E (X ) xP( X x) Find E(X) and tell which is the best £1 gambling machine Pay out £ x P( X x) 0 2 0.7 0.2 5 0.1 50 p gambling machine Pay out £ P( X x) x0 1 10 0.75 0.2 0.05 E( X ) (0 0.7) (2 0.2) (5 0.1) E( X ) (0 0.75) (1 0.2) (10 0.05) E ( X ) 0.9 You will loose 10 pence on average per game. E ( X ) 0.7 You will win 20 pence on average per game. Variance and Standard Deviation Variance of a Frequency distribution ( x ) n 2 2 Standard Deviation of a Frequency distribution ( x ) 2 n Find the deviation of each possible value from the mean. x 2 (x ) Square each deviation Multiply each squared deviation by the corresponding probability ( x ) 2 P( X x ) Why is it unnecessary in the case of a random variable to divide by the total probability? Can you write a general formula for the variance for any probability distribution? Var (X ) 2 ( x ) P( X x ) 2 Var ( X ) x p 2 2 Try this… £1 gambling machine: Find Var (X) E ( X ) 0.9 Var (X ) 2.49 Pay out £ P( X x) x 0 2 0.7 0.2 5 0.1 You think you can do this…? The probability function of the discrete random variable X is shown in the table: x 1 2 3 4 P( X x) 0.2 a 0.25 b Given E(X) = 2.95, find the values of a and b. A = 0.1 HINTS: Probabilities add to 1 think about how we get E(X) Get two equations, solve simultaneously B = 0.45 Homework * uniform distributions = probabilities are the same… Exercise D page 93 Questions 3,4,5,6*,8 AND Exam question: A gambler plays a game in which two dice are rolled and the scores added. If the total is 2, she loses £10. If the total is 6, she loses £7, but if either dice show a 6, the gambler wins £6. A. Draw up the probability distribution table of the gambler’s losses. B. Find the expected gain per game for the gambler C. How much would the gambler gain if she played the game 200 times? Would you say the game is fair?