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Your college newspaper, The Collegiate Investigator, has fixed production costs of $70 per edition and marginal printing and distribution costs of 40¢ per copy. The Collegiate Investigator sells for 50¢ per copy. a) Write down the associated cost, revenue, and profit functions. Solution: The cost function has the form 𝐶 (𝑥 ) = 𝑚𝑥 + 𝑏, where 𝑚 is the marginal cost (cost per item) and 𝑏 is the fixed cost. It costs 40¢ per copy plus fixed costs of $70, so the cost function is 𝐶 (𝑥 ) = 0.40𝑥 + 70. Revenue is how much money is brought in. You find it by multiplying the price of the item by the number of items you sell, so Revenue = (price) × (quantity). In this case the price you sell the newspapers for is 50¢, and 𝑥 stands for the quantity that you sell. Thus, 𝑅(𝑥 ) = 0.50𝑥. Profit is revenue minus cost, so 𝑃(𝑥 ) = 𝑅(𝑥 ) − 𝐶 (𝑥 ) = 0.50𝑥 − (0.40𝑥 + 70) = 0.10𝑥 − 70. b) What profit (or loss) results from the sale of 500 copies of The Collegiate Investigator? Solution: Plug 500 into the profit function, which gives 𝑃(500) = 0.10(500) − 70 = −20, so selling 500 copies results in a loss of $20. c) How many copies should be sold in order to break even? To find the break-even point, set the profit function equal to 0 and solve for 𝑥. This gives 0.10𝑥 − 70 = 0, so 0.10𝑥 = 70 and 𝑥 = 700. Thus, they must sell 700 copies to break even.