Download Math 2 EOCT - Practice Test for Study Guide 1. What is the AREA of

Math 2 EOCT - Practice Test for Study Guide
1. What is the AREA of a square if the diagonal length is
8. If the pattern continues, how many total circles will
it take to create the first 20 figures?
A.
B.
C.
D.
5√2?
B. 25 2
A. 25
C. 50
D. 50 2
Use the quadratic graphed to answer #2-4.
2. What is the function's domain and range?
A. D: 4 < x < ∞, R; 4 < y < ∞
B. D: -∞ < x < ∞, R; -∞ < y < 4
C. D: -∞ < x < ∞, R; -∞ < y < ∞
D. D: -∞ < x < 4, R; -∞ < y < ∞
61
65
589
650
9. This graph shows a set of data from a study of the
nitrogen concentration in plants with multiple base
stems.
Which equation BEST
fits the data in the graph?
3. Find the interval of increasing.
A. -∞ < x < 3
C. -∞ < y < 4
B. 3 < x < -∞
D. 4 < y < - ∞
4. What is the function in vertex form?
A. 𝑓(𝑥) = (𝑥 + 3)2 + 4
B. 𝑓(𝑥) = −(𝑥 + 3)2 + 4
2
C. 𝑓(𝑥) = −(𝑥 − 3) + 4
D. 𝑓(𝑥) = (𝑥 − 3)2 − 4
5. A student drew this diagram of a right triangle.
What is the value of the tangent of angle R?
A.
C.
4
5
3
4
B.
D.
10. Which expression is equivalent to
5
4
A.
4
3
6. The graph of an exponential function is shown on this
coordinate plane.
Which equation represents
the function?
A. 𝑓(𝑥) = −6(2𝑥 ) + 2
B. 𝑓(𝑥) = −6(2−𝑥 ) + 2
C. 𝑓(𝑥) = 6(2𝑥 ) − 2
D. 𝑓(𝑥) = 6(2−𝑥 ) − 2
7. The table compares the number
of customers a restaurant had for
lunch and dinner during a year.
Which conclusion is correct?
B.
19
3
29
3
−
+
22
3
2
3
𝑖
𝑖
D.
2−𝑖
19
22
5
−
29
5
+
5
2
5
?
𝑖
𝑖
11. This equation can be used to determine a number
such that the square of the number is 25 less than 10
times the number:
x2 = 10x - 25
Which of the following is equivalent to the equation?
A. x2 = 5x
B. x2 = -15x
2
C. (x - 5) = 0
D. (x + 5)(x -5) = 0
12. Which function has zeros at -2 and 4?
A. 𝑓(𝑥) = 𝑥 2 + 2𝑥 − 8
C. 𝑓(𝑥) = 𝑥 2 − 2𝑥 − 8
B. 𝑓(𝑥) = 𝑥 2 − 2𝑥 + 4
D. 𝑓(𝑥) = 𝑥 2 + 2𝑥 − 4
13. Write the function f(x) = |x - 1| as a
piecewise function?
A. The average number of customers was greater for
lunch.
B. There was more variation in the number of customers
for lunch.
C. The average number of customers was greater for
dinner.
D. There was more variation in the number of customers
for dinner.
C.
12−5𝑖
 x  1, if x  1
x  1, if x  1
A. f ( x )  
 x  1, if x  1
 x  1, if x  1
B. f ( x )  
 x  1, if x  0
 x  1, if x  0
C. f ( x)  
14. A supply of hex nuts is produced and the production
records indicate a mean mass of 7.8g with a standard
deviation of 0.3g. Assuming a normal distribution,
estimate the percent of hex nuts with mass less than
7.5g.
A. 84%
B. 66%
C. 34%
D. 16%
22. What is the value of x?
15. Which data set has the least amount of variability
based on its standard deviation?
23. Which equation is equivalent to
A) 3, 11, 20, 14, 20
C) 12, 10, 13, 25, 12
B) 10, 13, 10, 25, 16
D) 14, 10, 12, 14, 3
 2 x 2 y 3
16. Which expression is equivalent to 
1
 3 xy
9y 4
A.
4x 2
4y 4
B.
9x 2
9x 2
C.
4y 4



2
4x 2
D.
9y 4
17. Solve 52x + 4 = 125x - 7
A. -11
B. 11
C. 17
D. 25
18. Segments ̅̅̅
𝐾𝐽 and ̅̅̅̅
𝐾𝐿 are tangent to circle P.
m∠JML = 40°.
What is the measure
of ∠JKL?
A. 140°
C. 30°
B. 100°
D. 50°
19. What are the solutions of the equation:
A.
B.
C.
D.
20. Which function is NOT an inverse of itself?
A. 𝑓(𝑥) = 1 − 𝑥
C. 𝑓(𝑥) = 𝑥 − 1
B. 𝑓(𝑥) = −𝑥
1
D. 𝑓(𝑥) =
𝑥
21. The graphs of the linear function
𝑓(𝑥) = −4 and the absolute value function
𝑓(𝑥) = −2|𝑥 − 2| + 3 are shown on this coordinate
plane.
Which of the following
are the best approximate
solutions of
−2|𝑥 − 2| + 3 = −4?
A.
B.
C.
D.
x = -0.5 & 3.5
x= -4 & 3
x = -1.5 & 5.5
x = -1 & 5
A. 24
C. 26.5
B. 25.5
D. 27.9
A.
B.
C.
D.
24. An exercise ball has a volume of 2304𝜋 cubic
inches. What is the surface area of the ball?
A. 96 𝜋 sq. in.
C. 288 𝜋 sq. in.
B. 192 𝜋 sq. in.
D. 576 𝜋 sq. in.
25. A sector of a circle measures 105°. The arc length
of the sector is 7π meters. What is the area of the
sector?
A. 84π m2
C. 42π m2
B. 49π m2
D. 21π m2
KEY
1. A
7. B
The bigger the standard
deviation, the more
variation there is in the
data.
2. B
The domain is x-values
(look left to right) and the
range is y-values (look up
and down)
8. D
3. A
9. D
The data points are curved
which means it must be a
quadratic function and not
linear. The function opens
down, so it has to have a in front.
4. C
𝑓(𝑥) = −(𝑥 − 3)2 + 4
Reflection
Shift right
Shift up
10. D
Multiply numerator and
denominator by conjugate
of denominator
12 − 5𝑖 2 + 𝑖
∙
2−𝑖 2+𝑖
24 + 12𝑖 − 10𝑖 − 5𝑖 2
=
4 − 2𝑖 + 2𝑖 − 𝑖 2
24 + 2𝑖 − 5(−1)
=
4 − (−1)
29 + 2𝑖
=
5
11. C
5. D
13. B
19. A
14. D
20. C
15. D
Plug each data set into the
calculator:
1) Clrdata 2) 1-var stat
3) Data (use arrow down key)
4) Statvar and look for σ.
21. C
Look where the two
functions intersect and
estimate the x values.
16. A
1) Distribute the exponent of
22. A
When a diameter or radius
meets at a point of
tangency, a right angle is
created. Use Pythagorean
thm. 102 + x2 = 262
X2 = 262-102
X = √262 − 102 = 24
23. D
-2.
2−2 𝑥 −4 𝑦 6
3−2 𝑥 −2 𝑦 2
2) reciprocal negative
exponents
Reflection,
growth,
shift up 2.
22 𝑥 4 𝑦 2
3) Now simplify.
9𝑦 4
4𝑥 2
17. D
1) Get both to have same
base # of 5. 52𝑥+4 = 53 (𝑥−7)
2) Since they both have same
base, exponents are equal.
2𝑥 + 4 = 3(𝑥 − 7)
2𝑥 + 4 = 3𝑥 − 21
25 = 𝑥
18. B
6. A
𝑓(𝑥) = −6(2𝑥 ) + 2
32 𝑥 2 𝑦 6
12. C
X = -2 and x = 4
(x + 2)(x - 4) = 0
X2 + 2x - 4x -8 = 0
X2 - 2x - 8 = 0
25.
24. D